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Chemistry Test - 1

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Chemistry Test - 1
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  • Question 1
    1 / -0
    At temperature 300 K for reaction  C2H4(g) + 3O2(g)→ 2CO2(g) + 2H2O(); ΔH = − 336.2 kcal.  The approximate value of ΔU  at 300 K for the same reaction (R = 2 cal degree− 1 mol− 1) will be-
    Solution

    C2H4(g) + 3 O2(g)→2 CO2(g) + 2 H2O()

    At 300 K ΔH = − 336.2 kcal

    Δng = 2 − (1 + 3) = − 2

    T = 300 K, ΔH = − 336.2 kcal,

    R = 2 × 10−3 kcal degree−1 mol−1

    ΔH = ΔU+ ΔngRT

    − 336.2 = ΔU + (− 2) × 300 × 2 × 10−3

    ΔU = − 336.2 + 1.2 = − 335.0 kcal.

    Hence option B is correct.

  • Question 2
    1 / -0

    The products A and B of the above reaction are respectively.
    Solution


    Hence option B is correct.

  • Question 3
    1 / -0
    0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample is
    Solution
    \begin{equation}\begin{aligned}
    &CaSO _{4(aq )}+ BaCl _{2( aq )} \rightarrow BaSO _{4( s )}+ CaCl _{2( aq )}\\
    &136 g \text { CaSO }_{4} \text { produces } 233 g \text { BaSO }_{4}\\
    &\text { Weight of } BaSO _{4}=0.617 g\\
    &\text { Mass of } CaSO _{4} \text { reacted }=\frac{0.617 \times 136}{233}=0.3601 g\\
    &\text { Percentage purity of } \operatorname{CaSO}_{4}=\frac{0.3601 \times 100}{0.400}=90.025
    \end{aligned}\end{equation}
    Hence option B is correct.
  • Question 4
    1 / -0
    Which one of the following is wrong?
    Solution

    Ag+1 ion has 18 valence electrons so it is more covalent due to greater polarizability on anion.

    Hence option B is correct.

  • Question 5
    1 / -0
    Consider the reaction 2A + B →products, when the concentration of A alone was doubled, the half-life of the reaction did not change. When the concentration of B alone was doubled, the rate was not altered. The unit of rate constant for this reaction is
    Solution

    \(2 A+B \rightarrow\) Product

    Let rate of reaction, \(r=k[A]^{x} 1[B]^{x_{2}}\)

    When concentration of B doubled rate does not changes So \(r_{1}=r_{2}\)

    \(\Rightarrow k[A]^{x_{1}}[B]^{x_{2}}=k[A]^{x_{1}}[2 B]^{x_{2}}\)

    \(\Rightarrow[B]^{x_{2}}=[2 B]^{x_{2}}\)

    \(\Rightarrow x_{2}=0\)

    so rate, \(r=k[A]^{x_{1}}\)

    Now when Concentration of A doubled half life does not change it means reaction is first order so \(x_{1}=1\)

    and \(r=k[A]\)

    order of reaction \(=1\)

    so unit of rate constant \(= s ^{-1}\)

    Hence option A is correct.
  • Question 6
    1 / -0
    products can be?
    Solution

    Hence option B is correct.

  • Question 7
    1 / -0
    The compound when kept in pentane converts to a constitutional isomer. Identify that isomer.
    Solution

    Hence B is correct.

  • Question 8
    1 / -0
    Study the following reactions and identify the reactant 'R'. 
    Solution

    Hence option B is correct.

  • Question 9
    1 / -0
    Which of the following type of compound is used to increase the hardness of the silicone polymer.
    Solution

    Hydrolysis followed by condensation polymerization of RSiCl3 produces 3-D cross-linked silicones which are hard.

    Hence option B is correct.

  • Question 10
    1 / -0

    The cations present in 'A'
    Solution


    Hence option B is correct.

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