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Chemistry Test - 11

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Chemistry Test - 11
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  • Question 1
    1 / -0

    In case of physical adsorption, there is desorption when:

    Solution

    In case of physical adsorption, there is desorption when temperature increases.

    Physical adsorption is exothermic in nature. Hence, it is observed at low temperature. it involves weak van der Waals forces that break at high temperature causing desorption.

  • Question 2
    1 / -0

    Gravity separation process is used for the concentration of _____________.

    Solution

    Gravity separation process is used for the concentration of haematite. Gravity method is based on the difference between the densities of the ore particle and gangue. It is used for the concentration of denser ores from the water soluble and lighter impurities (gangue). Oxide ores and carbonate ores are concentrated by this method.

  • Question 3
    1 / -0

    For a gaseous reaction 2B ⇌ A , the equilibrium constant. Kp is ____________ to/ than Kc.

    Solution
    \(K_{p}=K_{c}(R T)^{\Delta n}\) and
    \(R T>1\)
    For a reaction, \(a A+b B \rightleftharpoons c C+d D\)
    \(\Delta n=(c+d)-(a+b)\)
    Here, \(\Delta n=1-2=-1\)
    Thus, \(K_{p}\) is less than \(K_{c}\)
  • Question 4
    1 / -0

    The hormone that helps in the conversion of glucose into glycogen is:

    Solution

    Insulin helps in conversion of glucose to glycogen. This process is called glycogenolysis.

  • Question 5
    1 / -0

    Select the correct statement(s).

    Solution

  • Question 6
    1 / -0

    When 1 L of CO2 is heated with graphite, the volume of the gases collected is 1.5 L. Calculate the number of moles of CO produced at STP.

    Solution
    \(C O_{2}(g)+C(s) \longrightarrow 2 C O(g) ; \quad x\) is amount
    \(\begin{array}{lll}1 L & 0 & 0 & \text { of } C O_{2} \text { consumed }\end{array}\)
    \(2 x\)
    \(\Longrightarrow(1-x)+2 x=\) Total volume \(=1.5 x\)
    \(\Rightarrow x=0.5 L\)
    So, amount of \(C O\) consumed \(=1 L\) \(\Longrightarrow 1\) mole of \(C O \rightarrow 22.4 L C O(g)\)
    \(y \rightarrow 1 L C O\)
    \(\Longrightarrow y=\frac{1}{22.4}\) moles of \(C O\)
  • Question 7
    1 / -0

    All noble gases crystalline in the ccp structure except:

    Solution

    All noble gases crystallize in the ccp structure except helium which has two allotropes, one in hcp structure and the other in bcc structure.

    Contrary to theoretical calculations that helium should be in the face- or body-centered cubic structure, in the entire range of pressures of this study, the measurements demonstrate that helium crystallizes in hexagonal-close-packed structure (Fig.), which is the same as that of solid hydrogen under these conditions

  • Question 8
    1 / -0

    The strongest oxidising agent is :

    Solution

    An element which can readily accept an electron is a good oxidising agent. Halogens are good oxidising agents because they have strong tendency to accept an electron due to (i) small atomic size, (ii) high electronegativity and  (iii) high electron affinity. Fluorine, being smallest, is best oxidising agent.

  • Question 9
    1 / -0

    A solution containing 8.6 g urea in 1 L was found to be isotonic with a 5% (weight/volume) solution of an organic non-volatile solute. The molecular weight of later is:

    Solution
    For two non-electrolyte solutions, if isotonic \(C_{1}=C_{2}\). \(\therefore \frac{8.6}{60 \times 1}=\frac{5 \times 1000}{M w_{2} \times 100} \Rightarrow M w_{2}=348.9\)
  • Question 10
    1 / -0

    Which of the following compounds does not give a silver mirror with Tollen's reagent ?

    Solution

    Tollens' reagent is a chemical reagent most commonly used to determine whether a known carbonyl-containing compound is an aldehyde or a ketone.

    Ketones are not oxidized by Tollens reagent, so the treatment of a ketone with Tollens reagent in a glass test tube does not result in a silver mirror.

    Formic acid is unique amongst simple carboxylic acids since it contains a hydrogen atom instead of an alkyl group(H-COOH, all other carboxylic acid contains an alkyl group attached to C instead of hydrogen on the left side).

    Thus formic acid may be regarded both as an aldehyde as well as a carboxylic acid..like aldehydes it can be easily oxidized to carbonic acid (H2CO3) which decomposes to give CO2 and H2O

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