Mathematical Ability Test-4

Result

Mathematical Ability Test-4

Score
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Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
1 / -0

A man is standing on the 8 m long shadow of a 6 m long pole. If the length of the shadow of a man is 2.4 m, then the height of the man is:

A
1.4 m

B
1.8 m

C
1.6 m

D
2.0 m

Solution

Question 2

1 / -0

Find the mode of the following data

Class	0 -10	10 - 20	20 - 30	30 - 40	40 - 50
frequency	6	10	14	12	4

25

26.66

36.66

20 Solution

From the given data it is cleared data the highest frequency is 14 and it belongs to 20 - 30 class interval so 20 - 30 is the modal class.

Question 3
1 / -0

A
⁽ⁿ⁺²⁾C_r

B
⁽ⁿ⁺¹⁾C_r

C
⁽ⁿ⁻²⁾C_r

D
⁽ⁿ⁻¹⁾C_r

Solution
Question 4
1 / -0

A pair of dice is thrown. Find the probability of obtaining a sum of 8 or getting an even number on both the dice.

A
2/3

B
1/3

C
11/36

D
5/36

Solution

Let the events be defined as:

A: Obtaining a sum of 8

B: Getting an even number on both dice

Now cases favourable to A are (3, 5)(5, 3)(2, 6)(6, 2)(4, 4)

So, P(A) = 5/36
Question 5
1 / -0

Ramu works 4 times as fast as Somu. If Somu can complete a work in 20 days independently, then the number of days in which Ramu and Somu together can complete the work is:

A
4 days

B
6 days

C
3 days

D
5 days

Solution

Given:

Ramu works 4 times as fast as Somu.

Somu can complete a work in =20 days

Formula:

Total work = Efficiency × Time

Calculation:

Let efficiency of Somu be 1 unit/day

The efficiency of Ramu =4 unit/day

Total work = 1 × 20 = 20 unit

∴ Time taken by Ramu and Somu to complete the same work
Question 6
1 / -0

A
32

B
63

C
64

D
31

Solution
Question 7
1 / -0

A
[0,3]

B
[−3,3]

C
[−3,0]

D
[0,9]

Solution
Question 8
1 / -0

The length of the base of a triangle is 5/7 of the base of a parallelogram. The area of the triangle and the parallelogram is the same. Find the ratio of the respective heights of the triangle and the parallelogram.

A
5 : 3

B
7 : 5

C
14 : 5

D
21 : 10

Solution

⇒TP=145

∴ The required ratio of the respective heights of the triangle and the parallelogram is 14 ∶ 5.
Question 9
1 / -0

In Δ ABC, ∠B = 90° and ∠A = 45°. If the length of its hypotenuse is 8 units, then the length of any other side (in units) is:

A
4√2

B
3√2

C
2√2

D
1

Solution

Given:

In Δ ABC,

∠B = 90° and ∠A = 45°

In right angled triangle

(Hypotenuse)² = (Base)²+ (Perpendicular)²

In Δ ABC,

⇒ ∠A + ∠B + ∠C = 180°

⇒ 45° + 90° + ∠C = 180°

⇒ ∠C = 180° - 135°

⇒ ∠C = 45°

and

Given triangle is right angled triangle because ∠B = 90° then,

⇒ (8)² = AB² + BC²

∠A and ∠C are equal so opposite sides of ∠A and ∠B also equal.

⇒ AB = BC

⇒ (8)² = AB² + AB²

⇒ 2AB² = 64

⇒ AB² = 32

⇒ AB = 4√2

∴ The length of any other two sides (in units) is 4√2.
Question 10
1 / -0

In the following trigonometry expression, find the value of (MN).

A
3

B
6

C
4

D
2

Solution