Analytical Reasoning Skills Test

Result

Analytical Reasoning Skills Test - 6

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Question 1
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Directions For Questions

Read the following information carefully and answer the questions given below.

Eight persons A, B, C, D, E, F, G and H live in an eight floor building. Each of them likes a different chocolate viz. Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky, but not necessarily in the same order. The lower floor is numbered 1, the upper floor is numbered 2 and the topmost floor is numbered 8.

There is only one floor between the one who likes Five Star and the one who likes Chunky. There are two floors between the one who likes Toblerone and C. F lives on an even numbered floor and likes Bar One. Neither A nor B likes Toblerone or Hershey’s. The one who likes Munch lives on floor no. 1. There are three floors between the floor on which B lives and the floor on which E lives. F lives above C, who does not live on first floor but likes Dairy Milk. The one who likes Five Star lives on the topmost floor. H does not like Five Star. G lives on the floor number which is between A and F. B lives above E and A. Only one person lives between the one who likes Hershey’s and the one who likes Toblerone.

...view full instructions

Which of the following combination is true?

A
2 – B – Dairy Milk

B
1 – F – Munch

C
5 – G – Toblerone

D
7 – A – Cadbury

Solution

Person: A, B, C, D, E, F, G and H.

Chocolate: Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky.

Floor: 1 to 8

Hence, H likes Munch.

1. The one who likes Munch lives on floorno.1. The one who likes Five Star lives on the topmost floor.Therels only one floor between the one wholikes Five star and the one who likeschunky.

2. Flives on an evennumbered floor and likes Bar one.Flves abovec, who doesnot live on first floor butikes Dairy Milk. There are two floors between the one wholikes Toblerone and C.

3. There are three floors between the flooron which Blives and the floor on which lives. Blivesabove and A.NeitherAnor Blikes Toblerone orHershey's.

The only possible case is:

4. G lives on the floor numberwhichis between AandF. (Acannot live on floorno8). NeitherAnor Bikes Toblerone or Hershey's.

5. H doesnotlike Five Star.

Hence, 5 – G – Toblerone is correct.
Question 2
1 / -0.25

Directions For Questions

Read the following information carefully and answer the questions given below.

Eight persons A, B, C, D, E, F, G and H live in an eight floor building. Each of them likes a different chocolate viz. Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky, but not necessarily in the same order. The lower floor is numbered 1, the upper floor is numbered 2 and the topmost floor is numbered 8.

There is only one floor between the one who likes Five Star and the one who likes Chunky. There are two floors between the one who likes Toblerone and C. F lives on an even numbered floor and likes Bar One. Neither A nor B likes Toblerone or Hershey’s. The one who likes Munch lives on floor no. 1. There are three floors between the floor on which B lives and the floor on which E lives. F lives above C, who does not live on first floor but likes Dairy Milk. The one who likes Five Star lives on the topmost floor. H does not like Five Star. G lives on the floor number which is between A and F. B lives above E and A. Only one person lives between the one who likes Hershey’s and the one who likes Toblerone.

...view full instructions

Who among the following lives on floor no. 7?

A
H

B
The one who likes Hershey’s

C
D

D
The one who likes Cadbury

Solution

Person: A, B, C, D, E, F, G and H.

Chocolate: Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky.

Floor: 1 to 8

Hence, H likes Munch.

1. The one who likes Munch lives on floorno.1. The one who likes Five Star lives on the topmost floor.Therels only one floor between the one wholikes Five star and the one who likeschunky.

2. Flives on an evennumbered floor and likes Bar one.Flves abovec, who doesnot live on first floor butikes Dairy Milk. There are two floors between the one wholikes Toblerone and C.

3. There are three floors between the flooron which Blives and the floor on which lives. Blivesabove and A.NeitherAnor Blikes Toblerone orHershey's.

The only possible case is:

4. G lives on the floor numberwhichis between AandF. (Acannot live on floorno8). NeitherAnor Bikes Toblerone or Hershey's.

5. H doesnotlike Five Star.

Hence, B who likes Cadbury, lives on floor no. 7.
Question 3
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Directions For Questions

Read the following information carefully and answer the questions given below.

Eight persons A, B, C, D, E, F, G and H live in an eight floor building. Each of them likes a different chocolate viz. Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky, but not necessarily in the same order. The lower floor is numbered 1, the upper floor is numbered 2 and the topmost floor is numbered 8.

There is only one floor between the one who likes Five Star and the one who likes Chunky. There are two floors between the one who likes Toblerone and C. F lives on an even numbered floor and likes Bar One. Neither A nor B likes Toblerone or Hershey’s. The one who likes Munch lives on floor no. 1. There are three floors between the floor on which B lives and the floor on which E lives. F lives above C, who does not live on first floor but likes Dairy Milk. The one who likes Five Star lives on the topmost floor. H does not like Five Star. G lives on the floor number which is between A and F. B lives above E and A. Only one person lives between the one who likes Hershey’s and the one who likes Toblerone.

...view full instructions

How many people live between H and the person who likes Cadbury?

A
Six

B
Five

C
Four

D
Three

Solution

Person: A, B, C, D, E, F, G and H.

Chocolate: Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky.

Floor: 1 to 8

Hence, H likes Munch.

1. The one who likes Munch lives on floorno.1. The one who likes Five Star lives on the topmost floor.Therels only one floor between the one wholikes Five star and the one who likeschunky.

2. Flives on an evennumbered floor and likes Bar one.Flves abovec, who doesnot live on first floor butikes Dairy Milk. There are two floors between the one wholikes Toblerone and C.

3. There are three floors between the flooron which Blives and the floor on which lives. Blivesabove and A.NeitherAnor Blikes Toblerone orHershey's.

The only possible case is:

4. G lives on the floor numberwhichis between AandF. (Acannot live on floorno8). NeitherAnor Bikes Toblerone or Hershey's.

5. H doesnotlike Five Star.

Hence, five people live between H and the person who likes Cadbury.
Question 4
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Directions For Questions

Read the following information carefully and answer the questions given below.

Eight persons A, B, C, D, E, F, G and H live in an eight floor building. Each of them likes a different chocolate viz. Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky, but not necessarily in the same order. The lower floor is numbered 1, the upper floor is numbered 2 and the topmost floor is numbered 8.

There is only one floor between the one who likes Five Star and the one who likes Chunky. There are two floors between the one who likes Toblerone and C. F lives on an even numbered floor and likes Bar One. Neither A nor B likes Toblerone or Hershey’s. The one who likes Munch lives on floor no. 1. There are three floors between the floor on which B lives and the floor on which E lives. F lives above C, who does not live on first floor but likes Dairy Milk. The one who likes Five Star lives on the topmost floor. H does not like Five Star. G lives on the floor number which is between A and F. B lives above E and A. Only one person lives between the one who likes Hershey’s and the one who likes Toblerone.

...view full instructions

E likes which of the following Chocolate?

A
Hershey’s

B
Bar One

C
Munch

D
Cadbury

Solution

Person: A, B, C, D, E, F, G and H.

Chocolate: Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky.

Floor: 1 to 8

Hence, H likes Munch.

1. The one who likes Munch lives on floorno.1. The one who likes Five Star lives on the topmost floor.Therels only one floor between the one wholikes Five star and the one who likeschunky.

2. Flives on an evennumbered floor and likes Bar one.Flves abovec, who doesnot live on first floor butikes Dairy Milk. There are two floors between the one wholikes Toblerone and C.

3. There are three floors between the flooron which Blives and the floor on which lives. Blivesabove and A.NeitherAnor Blikes Toblerone orHershey's.

The only possible case is:

4. G lives on the floor numberwhichis between AandF. (Acannot live on floorno8). NeitherAnor Bikes Toblerone or Hershey's.

5. H doesnotlike Five Star.

Hence, E likes Hershey’s.
Question 5
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Directions For Questions

Read the following information carefully and answer the questions given below.

Eight persons A, B, C, D, E, F, G and H live in an eight floor building. Each of them likes a different chocolate viz. Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky, but not necessarily in the same order. The lower floor is numbered 1, the upper floor is numbered 2 and the topmost floor is numbered 8.

There is only one floor between the one who likes Five Star and the one who likes Chunky. There are two floors between the one who likes Toblerone and C. F lives on an even numbered floor and likes Bar One. Neither A nor B likes Toblerone or Hershey’s. The one who likes Munch lives on floor no. 1. There are three floors between the floor on which B lives and the floor on which E lives. F lives above C, who does not live on first floor but likes Dairy Milk. The one who likes Five Star lives on the topmost floor. H does not like Five Star. G lives on the floor number which is between A and F. B lives above E and A. Only one person lives between the one who likes Hershey’s and the one who likes Toblerone.

...view full instructions

Which of the following likes Munch?

A
B

B
F

C
G

D
H

Solution

Person: A, B, C, D, E, F, G and H.

Chocolate: Dairy Milk, Toblerone, Five Star, Munch, Hershey’s, Cadbury, Bar One and Chunky.

Floor: 1 to 8

Hence, H likes Munch.

1. The one who likes Munch lives on floorno.1. The one who likes Five Star lives on the topmost floor.Therels only one floor between the one wholikes Five star and the one who likeschunky.

2. Flives on an evennumbered floor and likes Bar one.Flves abovec, who doesnot live on first floor butikes Dairy Milk. There are two floors between the one wholikes Toblerone and C.

3. There are three floors between the flooron which Blives and the floor on which lives. Blivesabove and A.NeitherAnor Blikes Toblerone orHershey's.

The only possible case is:

4. G lives on the floor numberwhichis between AandF. (Acannot live on floorno8). NeitherAnor Bikes Toblerone or Hershey's.

5. H doesnotlike Five Star.
Question 6
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Directions For Questions

Read the following information carefully and answer the questions given below it:

There are eight members Y, Z, U, W, Q, S, C and E. Each of them is related to Y in some way or the other and all of them have different chocolates among 20, 27, 33, 38, 40, 43, 45 and 50 but not necessarily in the same order and all are sitting in a straight line facing North.

Q is sitting second to right of Y’s son. Two people are sitting between Q and Z’s brother. Two people are sitting between Y’s son and Y’s father. S is an immediate neighbour of Y’s father. S is sitting at one of extreme ends. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. W and Y’s brother are sitting together. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U. Y’s brother is sitting second to left of Y. Two people are sitting between W and Y’s sister. Y is not an immediate neighbour of Q. C has more number of chocolates than Y but less than S. E’s father is sitting to the immediate right of Y’s daughter. Y’s wife is immediate neighbour of E. C is younger than U.

...view full instructions

How many chocolates does Y have?

A
33

B
20

C
40

D
38

Solution

Members – Y, Z, U, W, Q, S, C and E

1. S is sitting at one of extreme ends.S is an immediate neighbour of Y's father.Two people are sitting between Y's son and Y's father.Q is sitting second toright of Y's son. Two people are sitting between Q and Z's brother.

Case 1:

2. W and Y's brother are sitting together.Y's brother is sitting second tol eft of Y. Y is not an immediate neighbour of Q.

Case 1:

Hence,Yis brother of Z.

3. Two people are sitting between W and Y's sister.

This is not possible in case 1. So, case 2 is correct.

Hence, W is daughter of Y and E is son of Y.

Case 2:

Hence, Q is daughter of Y and Z, Y and E are siblings.

5.Y's wife is immediate neighbour of E.

This is not possible in case 1. So, case 2 is correct.

Hence, E is Y's brother, Z is Y's sister, W is Y's wife,Q is Y's daughter and S is Y's mother.

C is younger than U.

So, V is Y's father and C is Y's son.

According to the information given, relations of Y are father, mother, sister, brother, wife, son and daughter.

6. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. C has more number of chocolates than Y but less than S.Hence, C does not have the highest number of chocolates. If we assume chocolates of C be 20 and chocolates of Q be 50 then it does not follow the condition of sum of chocolates of C and Q is equal to sum of chocolates of W and E.

Therefore sum of chocolates of W and E is 50 + 20 = 70. Sum of chocolates of C and Q is 27 + 43 = 70.

S > C > Y. So, chocolates of C is 43, S is 45 and Q is 27.

5. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U.

W – Z = Q – U

Chocolates of Q are 27.

Hence, U chocolates can be 33, 38 and 40.

Therefore, difference between chocolates of U and Q can be 6, 11 and 13.

Let marks of W be 20 then chocolates of T can be 33, 38 and 40.

Therefore, difference between chocolates of W and Z can be 13, 18 and 20.

Hence, chocolates of W is 20, E is 50, Z is 33 and U is 40.

Chocolates of Y is 38.

Hence, Y has 38 chocolates.
Question 7
1 / -0.25

Directions For Questions

Read the following information carefully and answer the questions given below it:

There are eight members Y, Z, U, W, Q, S, C and E. Each of them is related to Y in some way or the other and all of them have different chocolates among 20, 27, 33, 38, 40, 43, 45 and 50 but not necessarily in the same order and all are sitting in a straight line facing North.

Q is sitting second to right of Y’s son. Two people are sitting between Q and Z’s brother. Two people are sitting between Y’s son and Y’s father. S is an immediate neighbour of Y’s father. S is sitting at one of extreme ends. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. W and Y’s brother are sitting together. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U. Y’s brother is sitting second to left of Y. Two people are sitting between W and Y’s sister. Y is not an immediate neighbour of Q. C has more number of chocolates than Y but less than S. E’s father is sitting to the immediate right of Y’s daughter. Y’s wife is immediate neighbour of E. C is younger than U.

...view full instructions

Who among the following sits third to the left of C?

A
U

B
E

C
Z

D
Y

Solution

Members – Y, Z, U, W, Q, S, C and E

1. S is sitting at one of extreme ends.S is an immediate neighbour of Y's father.Two people are sitting between Y's son and Y's father.Q is sitting second toright of Y's son. Two people are sitting between Q and Z's brother.

Case 1:

2. W and Y's brother are sitting together.Y's brother is sitting second tol eft of Y. Y is not an immediate neighbour of Q.

Case 1:

Hence,Yis brother of Z.

3. Two people are sitting between W and Y's sister.

This is not possible in case 1. So, case 2 is correct.

Hence, W is daughter of Y and E is son of Y.

Case 2:

Hence, Q is daughter of Y and Z, Y and E are siblings.

5.Y's wife is immediate neighbour of E.

This is not possible in case 1. So, case 2 is correct.

Hence, E is Y's brother, Z is Y's sister, W is Y's wife,Q is Y's daughter and S is Y's mother.

C is younger than U.

So, V is Y's father and C is Y's son.

According to the information given, relations of Y are father, mother, sister, brother, wife, son and daughter.

6. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. C has more number of chocolates than Y but less than S.Hence, C does not have the highest number of chocolates. If we assume chocolates of C be 20 and chocolates of Q be 50 then it does not follow the condition of sum of chocolates of C and Q is equal to sum of chocolates of W and E.

Therefore sum of chocolates of W and E is 50 + 20 = 70. Sum of chocolates of C and Q is 27 + 43 = 70.

S > C > Y. So, chocolates of C is 43, S is 45 and Q is 27.

5. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U.

W – Z = Q – U

Chocolates of Q are 27.

Hence, U chocolates can be 33, 38 and 40.

Therefore, difference between chocolates of U and Q can be 6, 11 and 13.

Let marks of W be 20 then chocolates of T can be 33, 38 and 40.

Therefore, difference between chocolates of W and Z can be 13, 18 and 20.

Hence, chocolates of W is 20, E is 50, Z is 33 and U is 40.

Chocolates of Y is 38.

Hence, E sits third to the left of C.
Question 8
1 / -0.25

Directions For Questions

Read the following information carefully and answer the questions given below it:

There are eight members Y, Z, U, W, Q, S, C and E. Each of them is related to Y in some way or the other and all of them have different chocolates among 20, 27, 33, 38, 40, 43, 45 and 50 but not necessarily in the same order and all are sitting in a straight line facing North.

Q is sitting second to right of Y’s son. Two people are sitting between Q and Z’s brother. Two people are sitting between Y’s son and Y’s father. S is an immediate neighbour of Y’s father. S is sitting at one of extreme ends. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. W and Y’s brother are sitting together. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U. Y’s brother is sitting second to left of Y. Two people are sitting between W and Y’s sister. Y is not an immediate neighbour of Q. C has more number of chocolates than Y but less than S. E’s father is sitting to the immediate right of Y’s daughter. Y’s wife is immediate neighbour of E. C is younger than U.

...view full instructions

How is S related to C?

A
Mother

B
Grandmother

C
Sister

D
Daughter

Solution

Members – Y, Z, U, W, Q, S, C and E

1. S is sitting at one of extreme ends.S is an immediate neighbour of Y's father.Two people are sitting between Y's son and Y's father.Q is sitting second toright of Y's son. Two people are sitting between Q and Z's brother.

Case 1:

2. W and Y's brother are sitting together.Y's brother is sitting second tol eft of Y. Y is not an immediate neighbour of Q.

Case 1:

Hence,Yis brother of Z.

3. Two people are sitting between W and Y's sister.

This is not possible in case 1. So, case 2 is correct.

Hence, W is daughter of Y and E is son of Y.

Case 2:

Hence, Q is daughter of Y and Z, Y and E are siblings.

5.Y's wife is immediate neighbour of E.

This is not possible in case 1. So, case 2 is correct.

Hence, E is Y's brother, Z is Y's sister, W is Y's wife,Q is Y's daughter and S is Y's mother.

C is younger than U.

So, V is Y's father and C is Y's son.

According to the information given, relations of Y are father, mother, sister, brother, wife, son and daughter.

6. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. C has more number of chocolates than Y but less than S.Hence, C does not have the highest number of chocolates. If we assume chocolates of C be 20 and chocolates of Q be 50 then it does not follow the condition of sum of chocolates of C and Q is equal to sum of chocolates of W and E.

Therefore sum of chocolates of W and E is 50 + 20 = 70. Sum of chocolates of C and Q is 27 + 43 = 70.

S > C > Y. So, chocolates of C is 43, S is 45 and Q is 27.

5. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U.

W – Z = Q – U

Chocolates of Q are 27.

Hence, U chocolates can be 33, 38 and 40.

Therefore, difference between chocolates of U and Q can be 6, 11 and 13.

Let marks of W be 20 then chocolates of T can be 33, 38 and 40.

Therefore, difference between chocolates of W and Z can be 13, 18 and 20.

Hence, chocolates of W is 20, E is 50, Z is 33 and U is 40.

Chocolates of Y is 38.

Hence, S is grandmother of C.
Question 9
1 / -0.25

Directions For Questions

Read the following information carefully and answer the questions given below it:

There are eight members Y, Z, U, W, Q, S, C and E. Each of them is related to Y in some way or the other and all of them have different chocolates among 20, 27, 33, 38, 40, 43, 45 and 50 but not necessarily in the same order and all are sitting in a straight line facing North.

Q is sitting second to right of Y’s son. Two people are sitting between Q and Z’s brother. Two people are sitting between Y’s son and Y’s father. S is an immediate neighbour of Y’s father. S is sitting at one of extreme ends. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. W and Y’s brother are sitting together. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U. Y’s brother is sitting second to left of Y. Two people are sitting between W and Y’s sister. Y is not an immediate neighbour of Q. C has more number of chocolates than Y but less than S. E’s father is sitting to the immediate right of Y’s daughter. Y’s wife is immediate neighbour of E. C is younger than U.

...view full instructions

Who among the following is father of Y?

A
U

B
Z

C
W

D
E

Solution

Members – Y, Z, U, W, Q, S, C and E

1. S is sitting at one of extreme ends.S is an immediate neighbour of Y's father.Two people are sitting between Y's son and Y's father.Q is sitting second toright of Y's son. Two people are sitting between Q and Z's brother.

Case 1:

2. W and Y's brother are sitting together.Y's brother is sitting second tol eft of Y. Y is not an immediate neighbour of Q.

Case 1:

Hence,Yis brother of Z.

3. Two people are sitting between W and Y's sister.

This is not possible in case 1. So, case 2 is correct.

Hence, W is daughter of Y and E is son of Y.

Case 2:

Hence, Q is daughter of Y and Z, Y and E are siblings.

5.Y's wife is immediate neighbour of E.

This is not possible in case 1. So, case 2 is correct.

Hence, E is Y's brother, Z is Y's sister, W is Y's wife,Q is Y's daughter and S is Y's mother.

C is younger than U.

So, V is Y's father and C is Y's son.

According to the information given, relations of Y are father, mother, sister, brother, wife, son and daughter.

6. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. C has more number of chocolates than Y but less than S.Hence, C does not have the highest number of chocolates. If we assume chocolates of C be 20 and chocolates of Q be 50 then it does not follow the condition of sum of chocolates of C and Q is equal to sum of chocolates of W and E.

Therefore sum of chocolates of W and E is 50 + 20 = 70. Sum of chocolates of C and Q is 27 + 43 = 70.

S > C > Y. So, chocolates of C is 43, S is 45 and Q is 27.

5. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U.

W – Z = Q – U

Chocolates of Q are 27.

Hence, U chocolates can be 33, 38 and 40.

Therefore, difference between chocolates of U and Q can be 6, 11 and 13.

Let marks of W be 20 then chocolates of T can be 33, 38 and 40.

Therefore, difference between chocolates of W and Z can be 13, 18 and 20.

Hence, chocolates of W is 20, E is 50, Z is 33 and U is 40.

Chocolates of Y is 38.

Hence, U is father of Y.
Question 10
1 / -0.25

Directions For Questions

Read the following information carefully and answer the questions given below it:

There are eight members Y, Z, U, W, Q, S, C and E. Each of them is related to Y in some way or the other and all of them have different chocolates among 20, 27, 33, 38, 40, 43, 45 and 50 but not necessarily in the same order and all are sitting in a straight line facing North.

Q is sitting second to right of Y’s son. Two people are sitting between Q and Z’s brother. Two people are sitting between Y’s son and Y’s father. S is an immediate neighbour of Y’s father. S is sitting at one of extreme ends. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. W and Y’s brother are sitting together. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U. Y’s brother is sitting second to left of Y. Two people are sitting between W and Y’s sister. Y is not an immediate neighbour of Q. C has more number of chocolates than Y but less than S. E’s father is sitting to the immediate right of Y’s daughter. Y’s wife is immediate neighbour of E. C is younger than U.

...view full instructions

What is the sum of chocolates of C and W?

A
88

B
63

C
70

D
73

Solution

Members – Y, Z, U, W, Q, S, C and E

1. S is sitting at one of extreme ends.S is an immediate neighbour of Y's father.Two people are sitting between Y's son and Y's father.Q is sitting second toright of Y's son. Two people are sitting between Q and Z's brother.

Case 1:

2. W and Y's brother are sitting together.Y's brother is sitting second tol eft of Y. Y is not an immediate neighbour of Q.

Case 1:

Hence,Yis brother of Z.

3. Two people are sitting between W and Y's sister.

This is not possible in case 1. So, case 2 is correct.

Hence, W is daughter of Y and E is son of Y.

Case 2:

Hence, Q is daughter of Y and Z, Y and E are siblings.

5.Y's wife is immediate neighbour of E.

This is not possible in case 1. So, case 2 is correct.

Hence, E is Y's brother, Z is Y's sister, W is Y's wife,Q is Y's daughter and S is Y's mother.

C is younger than U.

So, V is Y's father and C is Y's son.

According to the information given, relations of Y are father, mother, sister, brother, wife, son and daughter.

6. The sum of chocolates of C and Q is equal to sum of chocolates kept by W and E. One among the four have the highest number of chocolates and one among the four have the lowest number of chocolates. C has more number of chocolates than Y but less than S.Hence, C does not have the highest number of chocolates. If we assume chocolates of C be 20 and chocolates of Q be 50 then it does not follow the condition of sum of chocolates of C and Q is equal to sum of chocolates of W and E.

Therefore sum of chocolates of W and E is 50 + 20 = 70. Sum of chocolates of C and Q is 27 + 43 = 70.

S > C > Y. So, chocolates of C is 43, S is 45 and Q is 27.

5. The difference between the chocolates of W and Z is equal to the difference between the chocolates of Q and U.

W – Z = Q – U

Chocolates of Q are 27.

Hence, U chocolates can be 33, 38 and 40.

Therefore, difference between chocolates of U and Q can be 6, 11 and 13.

Let marks of W be 20 then chocolates of T can be 33, 38 and 40.

Therefore, difference between chocolates of W and Z can be 13, 18 and 20.

Hence, chocolates of W is 20, E is 50, Z is 33 and U is 40.

Chocolates of Y is 38.

Hence, sum of chocolates of C and W is 63.