Quantitative Ability Test

Result

Quantitative Ability Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

In a GP consisting of positive terms, each term equals the sum of the next two terms. Then the common ratio of the GP is:

A

B

C

D

Solution
Question 2
1 / -0

How many different permutations can be made out of the letters of the word 'INDIANARMY'?

A

B

C

D

Solution

Given word is : INDIANARMY

Total 10 letters are there, in which A,I and N are repeating twice.

We know that:

Number of Permutations of 'n' things taken 'r' at a time:

Number of Permutations of ‘n’ objects where there are n₁ repeated items, n₂ repeated items, nk repeated items taken ‘r’ at a time:
Question 3
1 / -0

A
11

B
10

C
9

D
2

Solution
Question 4
1 / -0

In what ratio must 2 varieties of coffee costing Rs. 330 and Rs. 440 per kg be mixed to get a mixture worth Rs. 363 per kg?

A
3 : 7

B
7 : 3

C
5 : 7

D
7 : 5

Solution

Given:

Price of 1 variety = Rs 330

Price of 2 variety = Rs 440

Mixture Price = Rs. 363

The required ratio should be

= (440 – 363) : (363 – 330)

= 77 : 33

= 7 : 3
Question 5
1 / -0

What is the least value of 25 cosec² x + 36 sec² x?

A
1

B
11

C
120

D
121

Solution
Question 6
1 / -0

A sum of money becomes 5 times at simple interest in 16 years. What is the rate of interest?

A
33.33%

B
25%

C
20%

D
30%

Solution

Given:

The Sum of money becomes 5 times of itself in 16 years

Formula used:
Question 7
1 / -0

The relation between, AM, GM and HM is:

A
AM < GM < HM

B
AM > GM > HM

C
AM > GM < HM

D
AM ≥ GM ≥ HM

Solution
Question 8
1 / -0

A
(1,1) Maximum

B
(1,-1), Maximum

C
(1,1) Minimum

D
(1,-1) Minimum

Solution
Question 9
1 / -0

The floor of a room is 25 m long and 16 m wide, the size of a brick is 20 cm by 10 cm. Number of bricks required to fill the floor of the room is:

A
20

B
200

C
2,000

D
20,000
Question 10
1 / -0

Find the ratio between the H.C.F and L.C.M of 105 and 48.

A
1 ∶ 560

B
3 ∶ 114

C
2 ∶ 157

D
3 ∶ 110

Solution

Given:

Two numbers are 105 and 48

Factors of 105 = 3 × 5 × 7

Factors of 48 = 2 × 2 × 2 × 2 × 3

H.C.F of 105 and 48 is 3

L.C.M of 105 and 48 is 1680 (i.e 3 × 5 × 7 × 2 × 2 × 2 × 2)

Required ratio = 3 : 1680

⇒ 1 ∶ 560

∴ Ratio between the H.C.F and L.C.M of 105 and 48 is 1 ∶ 560.