Quantitative Ability (S.A.) Test

Result

Quantitative Ability (S.A.) Test - 1

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Weekly Quiz Competition

Question 1
4 / -1

What percent of the odd numbers between 1 and 50 are divisible by only one and the number itself?

A
60%

B
58.33%

C
62.66%

D
56%

Solution

Number of odd numbers between 1 to 50 = 24 Only 14 odd prime numbers satisfy the given condition, i.e. 3,5,7,11,13,17,19,23,29,31,37,41,43 and 47

∴ Required percentage = 14/24 x 100 = 58.33%
Question 2
4 / -1

What value should come in place of the question mark (?) in the following question?

12.5 × 14 ÷ 8.75 + 42 = 50 + ?

A
42

B
26

C
12

D
28

Solution

Given,

12.5 × 14 ÷ 8.75 + 42 = 50 + ?

⇒ 12.5 × 1.6 + 42 = 50 + ?

⇒ 20 + 42 = 50 + ?

⇒ 62 = 50 + ?

⇒ ? =12

Hence, the correct option is (C).
Question 3
4 / -1

Three cards are drawn from a well-shuffled pack of 52 cards. What is the probability that all three will be queens?

A
3/4

B
1/13

C
3/22100

D
1/5525

Solution

Total number of ways of drawing 3 cards = ⁵²C₃ Number of ways of drawing 3 queens = ⁴C₃ Required probability

= ⁴C₃ / ⁰²C₃= 1 / 5525
Question 4
4 / -1

Using base BC of a Δ ABC, another Δ BCD is constructed, such that ∠ BAC is equal to ∠ BDC and AC is parallel to BD. If area of the Δ ABC is equal to 45 cm2, then what is the area of the Δ BDC,?

A
24 cm²

B
36 cm²

C
45 cm²

D
48 cm²

Solution
Question 5
4 / -1

A sum of money is divided between A, B and C such that their shares are in the proportions 1/2: 2/3: 3/4 If the share of A is Rs. 2,040, then what is the initial sum of money?

A
Rs.5,520

B
Rs.7,820

C
Rs.9,200

D
Rs.6,900

Solution

Ratio of the shares of A, B and C = 1 / 2 : 2 / 3 : 3 / 4 Taking L.C.M of the denominators, we get
Question 6
4 / -1

The average age of a group of 10 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group?

A
32 years

B
26 years

C
25.5 years

D
27 years

Solution

The average age of a group of 10 students is 20.

Therefore, the sum of the ages of all 10 of them = 10 x 20 = 200

When two new students join the group, the average age increases by 2. New average = 22.

Now, there are 12 students.

Therefore, the sum of the ages of all 12 of them = 12 × 22 = 264

Therefore, the sum of the ages of the two new students who joined = 264 − 200 =64

And the average age of each of the two new students

= 64 / 2 = 32 years.
Question 7
4 / -1

If Rahim moves 20 metres in the East direction and then turns to his left and then moves 15 metres and then he turns to his right and moves 25 metres. After this, he turns to his right and moves 15 metres. Now, how far is he from the starting point?

A
40 m

B
50 m

C
25 m

D
45 m

Solution

Rahim's movement is showing in the following diagram

Therefore, the distance of Rahim from his starting point,

= 20 + 25

= 45 meters

Hence, the correct option is (D).
Question 8
4 / -1

Blood relation:

A is the father of C and D is the son of B. E is the brother of A. If C is the sister of D, how is B related to E?

A
Father

B
Uncle

C
Maternal uncle

D
Sister-in-law

Solution

A is the father of C and C is the sister of D. So, A is the father of D. But D is the son of B. So, B is the mother of D and wife of A also. E is the brother of A So, B is the sister-in-law of E.
Question 9
4 / -1

Directions For Questions

Answer the following questions based on the given information: Three friends are married to three girls named Deepika, Malaika and Radhika.

I. Radhika is the only friend with a pierced nose

II. One of the girls, who is a DJ, lives in Manchester

III. Deepak’s wife is not a DJ.

IV. The friend with the pierced nose does not like to send mails.

V. Sachin is married to the DJ.

VI. The only friend who does not like to send mails lives in Paris.

VII. The girl in Madrid is married to Manoj.

VIII. Deepika rings her DJ sister once every week.

IX. Radhika receives a mail from Manchester once a week.

...view full instructions

Who is the DJ?

A
Malaika

B
Radhika

C
Deepika

D
Cannot be determined

Solution
Question 10
4 / -1

Directions For Questions

Answer the following questions based on the given information: Three friends are married to three girls named Deepika, Malaika and Radhika.

I. Radhika is the only friend with a pierced nose

II. One of the girls, who is a DJ, lives in Manchester

III. Deepak’s wife is not a DJ.

IV. The friend with the pierced nose does not like to send mails.

V. Sachin is married to the DJ.

VI. The only friend who does not like to send mails lives in Paris.

VII. The girl in Madrid is married to Manoj.

VIII. Deepika rings her DJ sister once every week.

IX. Radhika receives a mail from Manchester once a week.

...view full instructions

Who is Radhika’s husband?

A
Manoj

B
Deepak

C
Sachin

D
Deepak or Sachin

Solution

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Re-Attempt Weekly Quiz Competition

Quantitative Ability (S.A.) Test - 1

Result

Quantitative Ability (S.A.) Test - 1

Score

-

Rank

-

SHARING IS CARING

Question 1

60%

58.33%

62.66%

56%

Solution

Question 2

42

26

12

28

Solution

Question 3

3/4

1/13

3/22100

1/5525

Solution

Question 4

24 cm2

36 cm2

45 cm2

48 cm2

Solution

Question 5

Rs.5,520

Rs.7,820

Rs.9,200

Rs.6,900

Solution

Question 6

32 years

26 years

25.5 years

27 years

Solution

Question 7

40 m

50 m

25 m

45 m

Solution

Question 8

Father

Uncle

Maternal uncle

Sister-in-law

Solution

Question 9

Malaika

Radhika

Deepika

Cannot be determined

Solution

Question 10

Manoj

Deepak

Sachin

Deepak or Sachin

Solution

User

Question Analysis

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24 cm²

36 cm²

45 cm²

48 cm²