Quantitative Skills Test-2

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Quantitative Skills Test-2

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Question 1

1 / -0

Directions For Questions

Directions: Study the following table carefully and answer the questions given below it.

Generation of products by six plants at different durations
Plants	Duration (in Month)	Average no. of units generation per month	Total Manufacturing Cost (Rs.)	Total Selling Price (Rs.)	Profit Percentage
A	5	150	45000	–	–
B	10	50	–	–	10
C	–	–	18000	–	6
D	4	–	–	25235	–
E	5	–	–	39200	12
F	–	125	–	46725	5

...view full instructions

The manufacturing cost in plant F is Rs. 89 per unit. What is the duration of generation of products in plant F?

5 months

6 months

4 months

8 months

None of these

Solution

From the table,

The manufacturing cost in plant F is Rs. 89 per unit. The total selling price of products in plant F = Rs. 46725

Profit percentage = 5

Question 2

1 / -0

Directions For Questions

Directions: Study the following table carefully and answer the questions given below it.

Generation of products by six plants at different durations
Plants	Duration (in Month)	Average no. of units generation per month	Total Manufacturing Cost (Rs.)	Total Selling Price (Rs.)	Profit Percentage
A	5	150	45000	–	–
B	10	50	–	–	10
C	–	–	18000	–	6
D	4	–	–	25235	–
E	5	–	–	39200	12
F	–	125	–	46725	5

...view full instructions

If the manufacturing cost per unit is Rs. 70, what is average no. of units generated per month in plant E?

100

160

150

250

140 Solution

From the table,

The manufacturing cost per unit is Rs. 70 in plant E.Total selling price of products in plant E = Rs. 39,200

Profit percentage = 12

Question 3

1 / -0

Directions For Questions

Directions: Study the following table carefully and answer the questions given below it.

Generation of products by six plants at different durations
Plants	Duration (in Month)	Average no. of units generation per month	Total Manufacturing Cost (Rs.)	Total Selling Price (Rs.)	Profit Percentage
A	5	150	45000	–	–
B	10	50	–	–	10
C	–	–	18000	–	6
D	4	–	–	25235	–
E	5	–	–	39200	12
F	–	125	–	46725	5

...view full instructions

If the ratio of average no. of units generated per month between plant B and D is 2 : 7, find the profit percentage in plant D. [Given, manufacturing cost per unit is Rs. 35 in plant D]

2

3

4

14 None of these

Solution

From the table,

Given, the ratio of average no. of units generated per month between plant B and D is 2 : 7. The average no. of units generation per month in plant B = 50

So, the average no. of units generation per month in plant D = 50 × (7/2) = 175

Generation duration in plant D = 4 months

Then, the total no. of units generated in plant D = 175 × 4 = 700

The manufacturing cost per unit is Rs. 35 in plant D. So, the total manufacturing cost of products in plant D = Rs. 700 × 35 = Rs. 24,500

The total selling price of products in plant D = Rs. 25,235

So, profit = Rs. (25,235 – 24,500) = Rs. 735

Question 4

1 / -0

Directions For Questions

Directions: Study the following table carefully and answer the questions given below it.

Generation of products by six plants at different durations
Plants	Duration (in Month)	Average no. of units generation per month	Total Manufacturing Cost (Rs.)	Total Selling Price (Rs.)	Profit Percentage
A	5	150	45000	–	–
B	10	50	–	–	10
C	–	–	18000	–	6
D	4	–	–	25235	–
E	5	–	–	39200	12
F	–	125	–	46725	5

...view full instructions

If the manufacturing cost per unit product in plant B is Rs. 55, what is the total selling price of products in plant B?

Rs. 42980

Rs. 34560

Rs. 32150

Rs. 30250

None of these

Solution

From the table,

The manufacturing cost per unit product in plant B is Rs. 55. Generation duration of plant B = 10 months

Average no. of units generation per month in plant B = 50

Total no. of units generation of plant B = 50 × 10 = 500

Total manufacturing cost in plant B = Rs. 500 × 55 = Rs. 27,500

Profit percentage = 10

Hence, the total selling price of products in plant B = Rs. 27,500 × (110/100) = Rs. 30250

Question 5
1 / -0

Directions For Questions

Direction: Following pie chart represent the percentage of distribution of area of the 5 circular parks. Total area of the 5 park is 15386 m².

...view full instructions

What is the difference in the circumference of the park Q and A?

A
8.54 m

B
10.68 m

C
12.74 m

D
15.62 m

E
18.98 m

Solution
Question 6
1 / -0

Directions For Questions

Direction: Following pie chart represent the percentage of distribution of area of the 5 circular parks. Total area of the 5 park is 15386 m².

...view full instructions

A man is cycling near the boundary of the park P at 100 revolutions per minute. If the diameter of the wheel is 50 cm, the time take to complete the 4 round of the park P is _______

A
3.5 min

B
4 min

C
4.34 min

D
5.2 min

E
6 min

Solution
Question 7
1 / -0

Directions For Questions

Direction: Following pie chart represent the percentage of distribution of area of the 5 circular parks. Total area of the 5 park is 15386 m².

...view full instructions

What will be the difference in the area of park A if its shape of the park change to square with the same periphery as the circle?

A
592

B
609

C
684.6

D
642.8

E
None of the above

Solution
Question 8
1 / -0

Directions For Questions

Direction: Following pie chart represent the percentage of distribution of area of the 5 circular parks. Total area of the 5 park is 15386 m².

...view full instructions

In park B, tiles need to be attach in the specific area shown in the pie chart. If the radius of center circle is 2/5th of the diameter of park, width of each track is 1.5 meter and cost of fitting tiles in 1 m² is Rs. 4.5. Total cost for the fitting of tile is Rs. ____________

A
6583

B
7314

C
6873

D
8012

E
7241

Solution
Question 9
1 / -0

A shopkeeper has two types of mixture of tea. In 48 kg of first mixture ratio of tea to impurity is 5:3 and in 42 kg of second mixture ratio of tea to impurity is 3:1. If the shopkeeper mixes these two mixtures with 56 kg of pure tea in a large container, then find the ratio of tea to impurity in the container?

A
235 : 57

B
235 : 56

C
232 : 47

D
223 : 29

E
253 : 37

Solution
Question 10
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Consider 3 consecutive prime integers. Twice the first integer is 5 more than the third integer and second is 4 less than the third integer. Sum of the integers is 41. Find the smallest integer among the three.

A
11

B
13

C
7

D
5

E
None of these

Solution

Let first, second and third integer be a, b and c respectively.

2a = c + 5 ⇒ a = (c + 5)/2

b + 4 = c ⇒ b = c – 4

a + b + c = 41

Solving the above equation, a + b + c = 41

⇒ (c + 5)/2 + (c – 4) + c = 41 ⇒ c = 17

⇒ a = (17 + 5)/2 = 11

⇒ b = 17 – 4 = 13

∴ Smallest integer among the three is 11.