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Chemical Reactions and Equations Test - 23

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Chemical Reactions and Equations Test - 23
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Magnesium ribbon is burnt in an atmosphere of nitrogen gas to form solid magnesium nitride. This is a :
    Solution
    Reaction of magnesium with nitrogen is a combination reaction as these two reactants ( $$Mg$$ and $$N_{2}$$) combine together to form a single product as magnesium nitride ($$Mg_{3}N_{2}$$). The equation can be written as:

    $$3Mg(s)  +  N_{2}(g)  \rightarrow   Mg_{3}N_{2}(s)$$
  • Question 2
    1 / -0
    Which of the following is/are combination reaction(s)?
    (i) $$2KClO_{3} \overset{Heat}{\rightarrow} 2KCl + 3O_{2}$$
    (ii) $$MgO + H_{2}O \rightarrow  Mg(OH)_{2}$$
    (iii) $$4Al + 3O_{2} \rightarrow  2Al_{2} O_{3}$$
    (iv) $$Zn + FeSO_{4} \rightarrow  ZnSO_{4} + Fe$$
    Solution
    Option (i) is a decomposition reaction.
    Option (ii) is a combination reaction as magnesium oxide $$(MgO)$$ and water combines to form magnesium hydroxide $$(Mg(OH)_{2})$$.
    Option (iii) is again a combination reaction as aluminium $$(Al)$$ combines with oxygen $$(O_{2})$$ to form aluminium oxide $$(Al_{2}O_{3})$$.
    Option (iv) is a displacement reaction.
    The correct answer is option $$D$$.
  • Question 3
    1 / -0
    Which of the following statements about the given reaction is/are correct?
    $$3Fe(s) + 4H_{2}O(g) \rightarrow Fe_{3}O_{4}(s) + 4H_{2}(g)$$
    (i) Iron metal is getting oxidised.
    (ii) Water is getting reduced.
    (iii) Water is acting as reducing agent.
    (iv) Water is acting as oxidising agent.
    Solution
    Option (i) is correct as iron (Fe) is combining with oxygen to form iron oxide ($$Fe_3O_4=Fe^{II}O.{ Fe^{III} }_{ 2 }{ O }_{ 3 }$$).
    Iron is oxidising from 0 to +2 and +3 state.
    Option (ii) is correct as water ($$H_{2}O$$) is being reduced by removal of oxygen to form hydrogen ($$H_{2}$$) gas.

    Option (iv) is correct as water ($$ H_{2}O$$) itself is being reduced and is oxidising Iron(Fe), thereby acting as an oxidising agent.

    Option C is correct.
  • Question 4
    1 / -0
    If copper is kept open in air, it slowly loses its shining brown surface and gains a green coating. It is due to the formation of:
    Solution
    The green coat is due to the basic copper carbonate formation and is a mixture of copper carbonate and copper hydroxide $$(CuCO_3$$ and $$Cu(OH)_2)$$.
  • Question 5
    1 / -0
    Silver articles become black on prolonged exposure to air. 
    This is due to the formation of :
    Solution
    Silver metal is highly unreactive, i.e., it does not react with oxygen. 
    But with prolonged exposure to air, it reacts with hydrogen sulphide gas ($$H_2S$$). 
    Silver articles form a coating of silver sulphide ($$Ag_2S$$) and lose their shine (get tarnished).
  • Question 6
    1 / -0
    On adding a drop of barium chloride solution to an aqueous solution of sodium sulphite, white precipitate is obtained. What other name can be given to this precipitation reaction?
    Solution
    Barium chloride ($$BaCl_{2}$$) reacts with sodium sulphite ($$Na_{2}SO_{3}$$) to form barium sulphite ($$BaSO_{3}$$) and sodium chloride (NaCl).

    $$ BaCl_{2}(aq)  +  Na_{2}SO_{3}(aq)  \rightarrow   BaSO_{3}(s)  +  2NaCl(aq)$$
                                                        (white ppt)

    The above precipitation reaction is also a double displacement reaction as both reactants exchange their ions to form new products.
  • Question 7
    1 / -0
    Identify the type of chemical reaction.
    $$Mg(s) + Cl_{2}(g) \rightarrow  MgCl_{2}(s)$$
    Solution
    Magnesium ($$Mg$$) combines with chlorine ($$Cl_{2}$$) to form a new product as magnesium chloride ($$MgCl_{2}$$). Therfore its a combination reaction and the balanced equation can be written as:
    $$Mg(s)  +  Cl_{2}(g)  \rightarrow   MgCl_{2}(s)$$
  • Question 8
    1 / -0
    $$HgO(s) \xrightarrow{Heat} Hg(l) + O_{2}(g)$$
    The above given reaction is:
    Solution
    Mercuric oxide ($$HgO$$) decomposes on heating to give mercury ($$Hg$$) and oxygen ($$O_{2}$$). It is a thermal decomposition reaction and the balanced equation can be written as:
    $$2HgO(s)  \overset{heat}{\rightarrow}  2Hg(l)  +  O_{2}(g)$$
  • Question 9
    1 / -0
    What type of chemical reaction does the reaction belong to?
    A piece of sodium metal is added to absolute ethanol to form sodium ethoxide and hydrogen gas.
    Solution
    Sodium metal $$(Na)$$ reacts with ethanol ($$C_{2}H_{5}OH$$) to produce sodium ethoxide ($$C_{2}H_{5}ONa$$) and hydrogen ($$H_{2}$$). It is a displacement reaction in which the more active sodium displaces hydrogen in ethanol. The equation can be written as:
    $$2Na  +  2C_{2}H_{5}OH  \rightarrow   2C_{2}H_{5}ONa  +  H_{2}$$
  • Question 10
    1 / -0
    Write the balanced chemical equations for the following reactions:
    Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.
    Solution
    $$NaHCO_3+HCl\longrightarrow NaCl+H_2O+CO_2$$

     

    No. of Atom

    No. of Atom

    $$Na$$

     $$1$$

    $$1$$

    $$H$$

     $$2$$

    $$2$$

    $$C$$

     $$1$$

    $$1$$

    $$Cl$$

     $$1$$

    $$1$$

    $$O$$ 

     $$3$$

    $$3$$

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