Light Reflection and Refraction Test

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Light Reflection and Refraction Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

The unit of linear magnification is

A
Dioptre

B
It is unitless

C
Metre

D
Metre per second

Solution

Linear magnification is a ratio of image size to the object size; therefore it is a unitless quantity.
Question 2
1 / -0

If an object is moved away from a convex mirror, then its image ________ .

A
Moves towards the pole and becomes larger in size.

B
Moves towards the principal focus and becomes smaller in size.

C
Moves towards the pole and becomes smaller in size.

D
Moves towards the principal focus and becomes larger in size.

Solution

If an object is moved away from a convex mirror, then its image moves towards the principal focus and becomes smaller in size.
Question 3
1 / -0

The nature of the image formed by the convex mirror is always ________ and ________ irrespective of the position of the object.

A
Virtual and inverted

B
Real and erect

C
Virtual and erect

D
Real and inverted

Solution

Convex mirror always forms a virtual and erect image irrespective of the position of the object.
Question 4
1 / -0

Two thin lenses of power +3.5 D and -2.5 D are placed in contact. Find the focal length of the lens combination.

A
-16.7 m

B
100 cm

C
16.7 m

D
1 cm

Solution

For combination of lenses, the power of each lens is added to get the resultant power.

P = P₁ + P₂

= +3.5 - 2.5

= 1 D

Now, f (in m) = 1/P (in D)

So, f = 1/1 = 1 m = 100 cm
Question 5
1 / -0

An object 4 cm tall is placed in front of a convex lens. It produces an image 3 cm tall. What is the magnification of the lens?

A
0.75

B
1.33

C
12

D
10

Solution

m = h'/h = 3/4 = 0.75
Question 6
1 / -0

After refraction through a rectangular glass slab the emergent ray is?

A
parallel to incident ray.

B
totally internally reflected.

C
perpendicular to incident ray.

D
collinear to incident ray.

Solution

The extent of bending at opposite parallel faces is equal and opposite. Thus, emergent ray is parallel to incident ray.
Question 7
1 / -0

Identify the type of spherical mirror and find its radius of curvature if its focal length is - 0.5 cm

A
+1 cm; Convex

B
+1 cm; concave

C
-1 cm; convex

D
-1 cm ; Concave

Solution

Radius of curvature (R) = 2 × Focal length (f) Since, f = - 0.5 cm; therefore, R = 2 × (- 0.5) = - 1 cm Since its focal length is negative, it is a convex mirror.
Question 8
1 / -0

When light goes from an optically rarer to an optically denser medium,

A
angle of incidence = angle of refraction

B
angle of incidence < angle of refraction

C
angle of incidence > angle of refraction

D
angle of incidence > angle of reflection

Solution

As the light goes from an optically rarer to an optically denser medium, it bends towards the normal. Hence, the angle of incidence is greater than the angle of refraction.

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Re-Attempt Weekly Quiz Competition

Light Reflection and Refraction Test - 4

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Light Reflection and Refraction Test - 4

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SHARING IS CARING

Question 1

Dioptre

It is unitless

Metre

Metre per second

Solution

Question 2

Moves towards the pole and becomes larger in size.

Moves towards the principal focus and becomes smaller in size.

Moves towards the pole and becomes smaller in size.

Moves towards the principal focus and becomes larger in size.

Solution

Question 3

Virtual and inverted

Real and erect

Virtual and erect

Real and inverted

Solution

Question 4

-16.7 m

100 cm

16.7 m

1 cm

Solution

Question 5

0.75

1.33

12

10

Solution

Question 6

parallel to incident ray.

totally internally reflected.

perpendicular to incident ray.

collinear to incident ray.

Solution

Question 7

+1 cm; Convex

+1 cm; concave

-1 cm; convex

-1 cm ; Concave

Solution

Question 8

angle of incidence = angle of refraction

angle of incidence < angle of refraction

angle of incidence > angle of refraction

angle of incidence > angle of reflection

Solution

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