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Electricity Test - 21

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Electricity Test - 21
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  • Question 1
    1 / -0
    Current in a circuit flows:
    Solution
    Electric current flows from positive electrode of cell to negative electrode of cell, i.e., from high potential to low potential.
  • Question 2
    1 / -0
    To increase the effective resistance in a circuit the resistors are connected in ______.
    Solution

  • Question 3
    1 / -0
    The current which is assumed to be flowing in a circuit from positive terminal to negative, is called:
    Solution
    The current flowing from positive terminal to negative terminal is due to flow of positive charge, which is the conventional current.
  • Question 4
    1 / -0
    A dynamo develops $$0.5 A$$ at $$6 V$$. The energy which is generated in one second is
    Solution
    Given:
    Voltage(V) = $$6V$$
    Current(I) = $$0.5A$$
    Time(t) = $$1sec$$
    Energy generated = $$VIt$$
    $$\Rightarrow$$Energy $$= 6\times 0.5 \times 1=3 J$$
  • Question 5
    1 / -0
    The device used for producing current is called a _____.
    Solution
    In electricity generation A generator is a device which uses mechanical energy to produce electrical energy which flows in form of electric current in circuits. hence Generator can produce current.
  • Question 6
    1 / -0
    The insulator of electricity is :
    Solution
    Silk does not allow electric current to pass through it.
  • Question 7
    1 / -0
    An electric lamp is marked $$60\ W,\ 220\ V$$. The cost of kilo watt hour of electricity is $$Rs.\ 1.25$$. The cost of using thing lamp on $$220\ V$$ for $$8\ hrs$$ is:
    Solution
    Given:
    Power, $$P=60\ W$$
    Time, $$t=8\ hrs$$

    Energy consumed per day, $$E=Pt=60\times 8=480\ Whr=\dfrac{480}{1000}=0.48\ kW hr$$
    Hence total cost, $$C=0.48\times 1.25=Rs. 0.60 $$
  • Question 8
    1 / -0
    1 kilowatt hour $$=$$ ___________ .
    Solution
    $$1\ watt = 3600\ joule$$
    $$1\ kW = 1000\ watt$$
    $$1\ h=60\times 60 = 3600\ s$$
    $$1\ kWh= 1\ kW\times 1\ hour=1000\ W\times 3600\ s = 1000 \times 3600 joule = 3.6 \times 10^{6}\ J$$
  • Question 9
    1 / -0
    The unit of current is :
    Solution
    Current is measured in Coulomb/sec or Ampere. 
  • Question 10
    1 / -0
    The smallest resistance that can be obtained by the combination of  $$n$$ resistors, each of resistance  $$R$$ is:
    Solution
    For smallest resistance, the resistors are to be connected in parallel. The effective resistance $$= $$ R/n.
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