Metals and Non-metals Test

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Metals and Non-metals Test - 43

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Weekly Quiz Competition

Question 1
1 / -0

Generally metals reacts with acids to give salt and hydrogen gas. Which of the following acids does not give hydrogen gas on reacting with metals (except $Mn$ and $Mg$ )?

A
$H_2SO_4$

B
$HCl$

C
$HNO_3$

D
All of these

Solution

Hint: Nitric acid is a strong oxidizing agent that can oxidise hydrogen gas.

Step 1:
Generally metals reacts with acids to give salt and hydrogen gas. For example:
$K(s)+H_2SO_4(aq)\to K_2SO_4(aq)+H_2(g)$ .
$2K(s)+2HCl(aq)\to 2KCl(aq)+H_2(g)$

Step 2:
The end product of the reaction nitric acid with metals depends on the reactivity of the metal since nitric acid is a strong oxidizing agent that can oxidise hydrogen gas produced to water along with the production of oxides of nitrogen.
For example:
$Mg(s)+2HNO_3(aq)\to Mg(NO_3)_2(aq)+H_2(g)$
$8K(s)+10HNO_3(aq)\to 8KNO_3(aq)+N_2O(g)+5H_2O(l)$

Step 3:
In the second reaction of metal with nitric acid, no hydrogen gas is produced because the hydrogen gas produced by displacement is oxidised to water.

Final step: So, the correct option is (C) $HNO_3$ .
Question 2
1 / -0

Which of the following oxide(s) of iron would be obtained on prolonged reaction of iron with steam?

A
$FeO$

B
$Fe_2O_3$

C
$Fe_3O_4$

D
$Fe_2O_3$ and $Fe_3O_4$

Solution

Hint: Less reactive metals like iron react with steam to form oxide and release hydrogen gas.

Step 1:
$\bullet$ Reactive metals like sodium, potassium, calcium, etc. react with cold or hot water to form hydroxides and release hydrogen gas.
$\bullet$ Moderately reactive metals like magnesium react with hot water to form less soluble hydroxide and release hydrogen gas.
$\bullet$ Less reactive metals do not react with cold or hot water but react with steam to form metallic oxides.
$\bullet$ Least reactive metals like gold, silver, etc. do not react at all.

Step 2:
Iron does not react with cold or hot water because it is a less reactive metal, but it reacts with steam to form mixed iron oxide and hydrogen gas. The reaction of iron with the steam is as follows:

$3Fe(s)+4H_2O(g)\to Fe_3O_4(s)+4H_2(g)$

Note: $Fe_3O_4$ is a mixed oxide of $FeO$ and $Fe_2O_3.$

Final step: So, the correct option is (C) $Fe_3O_4$ .
Question 3
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The metal which produces hydrogen gas on reaction with dilute hydrochloric acid as well as sodium hydroxides solution is

A
copper

B
aluminium

C
iron

D
sodium

Solution

Aluminium being amphoteric in nature reacts with both acids and bases.
Hence, option "B" is correct answer.
Question 4
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Materials that can be drawn into wires are called ductile. Which of the following is not ductile material?

A
Silver

B
Sulphur

C
Copper

D
Aluminium

Solution

Sulphur is not ductile because it is non-metal. Non-metals are not ductile.
Hence, option $B$ is the correct answer.
Question 5
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Which one of the following metal do not react with cold or hot water?

A
Sodium (Na)

B
Calcium (Ca)

C
Magnesium (Mg)

D
Iron (Fe)

Solution

Reaction of metals with cold or hot water depends on the reactivity of the metals.

Reactive metals like sodium, potassium, calcium, etc. react with cold or hot water.
Moderately reactive metals like magnesium react with hot water.
Less reactive metals do not react with cold or hot water but react with steam.
Least reactive metals like gold, silver, etc. do not react at all.

Less reactive metals like iron react with steam to form an oxide and release hydrogen gas. The reaction is as follows:

$3Fe(s)+4H_2O(g)\to Fe_3O_4(s)+4H_2(g)$
Question 6
1 / -0

Which one of the following figures correctly describes the process of electrolytic refining?

A

B

C

D
Question 7
1 / -0

During electrolytic refining of zinc, it gets

A
deposited on cathode

B
deposited on anode

C
deposited on cathode as well as anode

D
remains in the solution

Solution

Hint: Electrolytic refining is one method of refining impure metals like Cu, Zn, Ag, etc.

Step 1: There are different methods available for refining metals. Some methods are - vapor phase refining, zone refining, distillation, electrolysis, etc. Electrolytic refining is one such method mainly used for metals like Cu, Zn, Ag, etc. In electrolytic refining, electrical energy is used to convert non-spontaneous reactions to spontaneous reactions.

Step 2: In the electrolytic refining of zinc, impure zinc is made as an anode, and a thin sheet of pure zinc is made as the cathode. A metal salt solution is taken as an electrolyte. At anode oxidation of zinc occurs and at the cathode reduction of zinc occurs.

Step 3: During the course of refining, the size of the anode decreases and impurities settle down at the bottom of the anode as anodic mud. The size of the cathode increases due to the deposition of zinc on the surface thereby obtaining the pure metals of zinc at the cathode.
Cell reaction is as follows:
At anode: $Zn(s)\to Zn^{2+}(aq)+2e^-$
At cathode: $Zn^{2+}(aq)+2e^-\to Zn(s)$

Final step: So, the correct option is (A) deposited on cathode.
Question 8
1 / -0

If copper is kept open in air, it slowly loses its shining brown surface and gains a green coating. It is due to the formation of

A
$CuSO_4$

B
$CuCO_3$

C
$Cu(NO_3)_2$

D
$CuO$

Solution

Hint: Copper when exposed to air for a long time undergo corrosion.

Step 1: Metal when exposed to air for a long time undergo corrosion. During corrosion, the metal on the surface undergoes a chemical reaction forming a new compound that changed the property of the metal at the surface. Rusting of iron is a common phenomenon of corrosion.

Step 2: Copper is a metal. Similarly, copper when kept open in air for a long time it slowly loses its shining brown surface and gains a green coating because of corrosion. During corrosion of copper, it reacts with carbon dioxide gas and moisture present in the air. This is called tarnishing of copper. The reaction is as follows.

$2Cu + H_2O + CO_2 + O_2 \to Cu(OH)_2 + CuCO_3$

Step 3: Different methods are available to prevent corrosion. Corrosion of copper can be protected by coating it with a thin layer of tin.

Final step: So the correct option is (B) $CuCO_3.$
Question 9
1 / -0

Which one of the following forms a brown flaky coat when exposed to air?

A
Sodium

B
Copper

C
Iron

D
Silver

Solution

Iron when exposed to moist air for a long time acquires a coating of a brown flaky substance called rust (chemically hydrated ferric oxide).
Thus, option $C$ is correct.
Question 10
1 / -0

Reacting with water, a metal produces

A
oxygen

B
nitric acid

C
a base

D
water

Solution

Metals react with water and produce a metal oxide and hydrogen gas. Metal oxides that are soluble in water dissolve in it to further form metal hydroxide which are usually bases.

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Re-Attempt Weekly Quiz Competition

Metals and Non-metals Test - 43

Result

Metals and Non-metals Test - 43

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Question 1

H2SO4H_2SO_4H2​SO4​

HClHClHCl

HNO3HNO_3HNO3​

All of these

Solution

Question 2

FeOFeOFeO

Fe2O3Fe_2O_3Fe2​O3​

Fe3O4Fe_3O_4Fe3​O4​

Fe2O3Fe_2O_3Fe2​O3​ and Fe3O4Fe_3O_4Fe3​O4​

Solution

Question 3

copper

aluminium

iron

sodium

Solution

Question 4

Silver

Sulphur

Copper

Aluminium

Solution

Question 5

Sodium (Na)

Calcium (Ca)

Magnesium (Mg)

Iron (Fe)

Solution

Question 6

Question 7

deposited on cathode

deposited on anode

deposited on cathode as well as anode

remains in the solution

Solution

Question 8

CuSO4CuSO_4CuSO4​

CuCO3CuCO_3CuCO3​

Cu(NO3)2Cu(NO_3)_2Cu(NO3​)2​

CuOCuOCuO

Solution

Question 9

Sodium

Copper

Iron

Silver

Solution

Question 10

oxygen

nitric acid

a base

water

Solution

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$H_2SO_4$

$HCl$

$HNO_3$

$FeO$

$Fe_2O_3$

$Fe_3O_4$

$Fe_2O_3$ and $Fe_3O_4$

$CuSO_4$

$CuCO_3$

$Cu(NO_3)_2$

$CuO$