Periodic Classification of Elements Test

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Periodic Classification of Elements Test - 26

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Weekly Quiz Competition

Question 1
1 / -0

Which element resembles cobalt and nickel but was placed in Newlands' table far away from those elements?

A
Sodium

B
Calcium

C
Iron

D
Chlorine

Solution

Iron resembles cobalt and nickel but in Newlands' table, it was placed far away from these elements in the last group.
Question 2
1 / -0

According to Mendeleev's periodic table, one element whose atomic mass is greater than that of nickel is placed before nickel. Name the element.

A
Copper

B
Iron

C
Zinc

D
Cobalt
Question 3
1 / -0

Find the sum of period number and group number of phosphorous?

A
$$16$$

B
$$17$$

C
$$18$$

D
$$19$$

Solution

The period number of phosphorous is $$3$$ and group number is $$15$$, so, the sum is $$18$$.
Question 4
1 / -0

Hydrogen resembles :

A
alkali metals

B
halogens

C
both A and B

D
noble gases

Solution

Hydrogen resembles alkali metals because it has only one electron in the outermost shell same as alkali metals. It can donate one electron to become $$H^+$$.
It resembles halogens because it needs one electron to completely fill its valence shell to attain noble gas configuration. It also forms diatomic molecule, combines with metals and non-metals to form compounds.
Question 5
1 / -0

According to the Newlands' law of octaves, the properties of fluorine are similar to those of ________ .

A
hydrogen

B
lithium

C
sodium

D
potassium

Solution

John Newlands arranged the known elements in increasing order of their atomic masses. He started with the element having the lowest atomic mass ( hydrogen ) and ended at thorium which was the $$56^{th}$$. According to his law, when elements are arranged in order of their increasing atomic masses, the properties of $$8^{th}$$ succeeding element resemble with that of the first one. The properties of fluorine are similar to those of hydrogen because fluorine is eight-element starting from hydrogen.

Hence, the correct option is $$A$$
Question 6
1 / -0

The correct order of atomic size of $$Na, Be$$ and $$Mg$$ is:

A
$$Be > Mg > Na$$

B
$$Na > Mg > Be$$

C
$$Mg > Na > Be$$

D
$$Na = Mg > Be$$

Solution

As we move down the group, the atomic size increases.
$$\therefore Mg>Be$$. And along the period, the atomic size decreases towards the right, hence $$Na>Mg$$.

Thus final order is $$Na>Mg>Be$$.
Question 7
1 / -0

Classification of elements makes the study of physical and chemical properties of elements ________ and __________.

A
slow, difficult

B
simple, organised

C
Complicated, unorganized

D
none of these

Solution

Periodic classification of elements is the method by which elements are grouped on the basis of their characteristics. Classification of elements makes the study of physical and chemical properties of elements simple and organised.
Question 8
1 / -0

John Newlands arranged the known elements in a/an ______ order of their atomic _______ .

A
increasing, masses

B
decreasing, masses

C
increasing, numbers

D
decreasing, numbers

Solution

John Newlands arranged the known elements in increasing order of their atomic masses. He started with the element having the lowest atomic mass ( hydrogen) and ended at thorium which was the $$56^{th}$$ element. He found that every eighth element had properties similar to the first. Some of the elements satisfying this order are arranged as $$H, Li, Be, B, C, N, O$$.
Question 9
1 / -0

Dobereiner was the first person to illustrate the relationship between the ____________ of elements and their properties.

A
atomic masses

B
electron negativity

C
molecular masses

D
number of protons

Solution

Dobereiner grouped elements in sets of triads. Each group had 3 elements. He illustrated the relationship between the atomic masses of elements and their properties with his law of triads.
Question 10
1 / -0

Which one of the following is an example of Dobereiner's triad?

A
$$Li , Al , Ca$$

B
$$Li , Na , K$$

C
$$Li , K , Na$$

D
$$K , Al , Ca$$

Solution

$$Li, Na, K$$ is the example of Dobereineer's triad. Here, the average atomic weights of $$Li$$ and $$K$$ equal the atomic weight of $$Na$$.

$$\dfrac{Weight\ of\ Li + weight\ of\ K}{2}$$ =$$\dfrac{7+39}{2}$$ =$$\dfrac{46}{2}$$ =23

= weight of $$Na$$.
Hence, option B is correct.

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Periodic Classification of Elements Test - 26

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Periodic Classification of Elements Test - 26

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Question 1

Sodium

Calcium

Iron

Chlorine

Solution

Question 2

Copper

Iron

Zinc

Cobalt

Question 3

$$16$$

$$17$$

$$18$$

$$19$$

Solution

Question 4

alkali metals

halogens

both A and B

noble gases

Solution

Question 5

hydrogen

lithium

sodium

potassium

Solution

Question 6

$$Be > Mg > Na$$

$$Na > Mg > Be$$

$$Mg > Na > Be$$

$$Na = Mg > Be$$

Solution

Question 7

slow, difficult

simple, organised

Complicated, unorganized

none of these

Solution

Question 8

increasing, masses

decreasing, masses

increasing, numbers

decreasing, numbers

Solution

Question 9

atomic masses

electron negativity

molecular masses

number of protons

Solution

Question 10

$$Li , Al , Ca$$

$$Li , Na , K$$

$$Li , K , Na$$

$$K , Al , Ca$$

Solution

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