Periodic Classification of Elements Test

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Periodic Classification of Elements Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

For which element, the Law of Octaves was not found to be applicable?

A
Oxygen

B
Calcium

C
Cobalt

D
Potassium
Question 2
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In Mendeleev's Periodic Table, gaps were left for the elements to be discovered later. Which of the following elements found a place in the periodic table later?

A
Germanium

B
Chlorine

C
Oxygen

D
Silicon Ana

Solution

Mandeleev named the undiscovered elements as Eka-boron, Eka-aluminlum and Eka-silicon. These were replaced with scandium, gallium and germanium respectively in due course of time.
Question 3
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Doberiener's system of classification into triads was not found to be useful as he could identify only:

A
Two triads

B
Three triads

C
Four triads

D
Five triads

Solution

He could only find 3 triads in elements due to this his concept was discarded.
Question 4
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Which one of the following does not increase while moving down the group of the periodic table?

A
Atomic radius

B
Metallic character

C
Valency

D
Number of shells in an element

Solution

Valency of an element remains the same in a group.
Question 5
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The correct order of increasing radius of the elements Si, Al, Na and P is:

A
$$Si < Al< P < Na$$

B
$$P < Si < Al < Na$$

C
$$Al < Si< P< Na$$

D
$$Al < P < Si < Na$$

Solution

The elements Na, Al, Si, and P are present in same period (2nd period). Atomic radius increases from left to right in a period. So, the order of atomic radius for the given elements will be Na > Al > Si > P.
Question 6
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In the Modern Periodic Table, the metals among the first ten elements are

A
$$Be, Na$$

B
$$Li, Be$$

C
$$Be, Li, Na$$

D
$$Li, Na$$

Solution

The first ten elements in the Modern Periodic Table are hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon. Among these, lithium (Li) and beryllium (Be) are metals.
Question 7
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The correct sequence of atomic radii is

A
$$ Na > Mg > Al > Si $$

B
$$ Al > Si > Na > Mg $$

C
$$Si > Al > Mg > Na $$

D
$$Si > Al > Na > Mg $$

Solution

In a period, atomic radii decrease from left to right.
Hence, option A is correct.
Question 8
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Based on general trends in the periodic table, predict which element in each of the following pairs has the most metallic character.
(i) Sn or Pb (ii) Ag or Sr (iii) Al or B (iv) Br or As

A
(i) Pb (ii) Sr (iii) Al (iv) As

B
(i) Sn (ii) Ag (iii) B (iv) As

C
(i) Pb (ii) Ag (iii) Al (iv) Br

D
(i) Sn (ii) Sr (iii) B (iv) Br
Question 9
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Arrange the following elements in the order of their increasing non-metallic character:

Li, Be, C, O, F

A
F < O < C < Be < Li

B
Li < Be < C < O < F

C
F < O < C < Be < Li

D
F < O < Be < C < Li

Solution

On moving from left to right in the Periodic Table, non-metallic character increases. This is because there is a decrease in atomic size and so, the attraction between nucleus and outermost electron increases, making it difficult to lose electron.

So, if we arrange the given elements in the order in which they appear in the Periodic Table, we can see that the elements on the left are most metallic and on the right are most non-metallic.

Li < Be < C < O < F
Question 10
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Which of the following accounts best for the fact that fluorine atom is smaller than that of oxygen?

A
Fluorine atom has a lower nuclear charge than oxygen atom, so electrons are more spread out.

B
Oxygen atom has a higher nuclear charge that pulls electrons closer.

C
Fluorine atom has a higher nuclear charge that pulls electrons closer.

D
None of the above

Solution

Atomic radius decreases in from left to right along a period in the Periodic Table. This is because as we go from left to right, the elements have higher nuclear charge which tends to pull electrons closer to the nucleus and reduces the size of the atom.

Fluorine comes after oxygen in the Periodic Table. So, it has larger nuclear charge and so, is smaller in size compared to oxygen atom.

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Periodic Classification of Elements Test - 28

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Periodic Classification of Elements Test - 28

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Question 1

Oxygen

Calcium

Cobalt

Potassium

Question 2

Germanium

Chlorine

Oxygen

Silicon Ana

Solution

Question 3

Two triads

Three triads

Four triads

Five triads

Solution

Question 4

Atomic radius

Metallic character

Valency

Number of shells in an element

Solution

Question 5

$$Si < Al< P < Na$$

$$P < Si < Al < Na$$

$$Al < Si< P< Na$$

$$Al < P < Si < Na$$

Solution

Question 6

$$Be, Na$$

$$Li, Be$$

$$Be, Li, Na$$

$$Li, Na$$

Solution

Question 7

$$ Na > Mg > Al > Si $$

$$ Al > Si > Na > Mg $$

$$Si > Al > Mg > Na $$

$$Si > Al > Na > Mg $$

Solution

Question 8

(i) Pb (ii) Sr (iii) Al (iv) As

(i) Sn (ii) Ag (iii) B (iv) As

(i) Pb (ii) Ag (iii) Al (iv) Br

(i) Sn (ii) Sr (iii) B (iv) Br

Question 9

F < O < C < Be < Li

Li < Be < C < O < F

F < O < C < Be < Li

F < O < Be < C < Li

Solution

Question 10

Fluorine atom has a lower nuclear charge than oxygen atom, so electrons are more spread out.

Oxygen atom has a higher nuclear charge that pulls electrons closer.

Fluorine atom has a higher nuclear charge that pulls electrons closer.

None of the above

Solution

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