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Periodic Classification of Elements Test - 8

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Periodic Classification of Elements Test - 8
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  • Question 1
    1 / -0

    Electronic configuration of Al3+ is-

    Solution

    Electronic configuration of Al is 2,8,3

    To form Al3+ , electronic configuration of Al is 2,8.

  • Question 2
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    Which of the following element forms dipositive ions very easily?

    Solution

    Electronic configuration of Mg is 2,8,2

    To complete its octet, it will lose two electrons readily and form divalent ion, Mg2+.

  • Question 3
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    Which of the following is not the limitation of Mendeleev’s periodic table?

    Solution

    Instead of limitation, it is one of the greatest merits of Mendeleev's periodic table. He had already predicted the existence of some elements that had not been discovered at that time. When these elements were discovered later on, they were placed in those gaps, withuot disturbing the existing elements.

  • Question 4
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    What is the atomic number of the first element of the lanthanide series?

    Solution

    The first element of the lanthanide series is called lanthanum with atomic number 57.

  • Question 5
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    Which of the following statement is true?

    Statement A : Electron affinity of fluorine is more than that of chlorine.

    Statement B : Carbon monoxide is an acidic oxide.

    Solution

    Statement A : Fluorine, though higher than chlorine in the periodic table, has a very small atomic size. This makes the fluoride anion so formed unstable (highly reactive).As a result, fluorine has an electron affinity less than that of chlorine.

    Statement B: Carbon monoxide is a neutral oxide

  • Question 6
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    Which of the following statement is true?

    Statement A : Energy is always released when a neutral atom gains an electron

     Statement B : Tellurium and polonium are semi metals

    Solution

    Statement A: Sometimes, energy is to be supplied to the atom while adding electron to it.

    Statement B : Since, both Tellerium and Polonium shows properties of both metals and non-metals, therefore, they are semi-metals.

  • Question 7
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    What is the number of valence electrons in the last element of 3rd period?

    Solution

    The element in the last of the 3rd period is a noble gas i.e. its octet is complete. So, it has 8 valence electrons in its outermost shell.

  • Question 8
    1 / -0

    Arrange the following elements in the decreasing order of their atomic radii. 

    Solution

    On moving from left to right in a period, the atomic size decreases. So, lithium(Li) being on the extreme left has the highest atomic size and oxygen(O) being on the extreme right side of period 2 has the least size. 

  • Question 9
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    Metallic character ____________ down a group

    Solution

    As we go down in a group, one more electron shell is added at each stage and size of the atom increases. The valence electrons become more and more far away from the nucleus and so the atom can lose electrons more easily to form positive ions. Therefore, metallic character increases down the group. 

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