CBSE Class 10th Science Mix Test

Result

CBSE Class 10th Science Mix Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium Iodide solution to it. What would she observe?

A
The solution turned red.

B
Yellow precipitate was formed.

C
White precipitate was formed.

D
The reaction mixture became hot.

Solution

The relation between lead nitrate and potassium iodide is an example of precipitation reaction.

\(Pb(NO_3)_2+2KI\longrightarrow\)\(PbI_2+2KNO_3\) (yellow ppt)

The yellow ppt of load iodide can be recovered by filtration.
Question 2
1 / -0

Which of the following correctly represents a balanced chemical equation?

A
\(Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+4H_2(g)\)

B
\(3Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+4H_2(g)\)

C
\(3Fe(s)+H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+H_2(g)\)

D
\(3Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+H_2(g)\)

Solution

\(3Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+4H_2(g)\)
Question 3
1 / -0

In the reaction of iron with copper sulphate solution:

\(CuSO_4+Fe\longrightarrow\)\(Cu+FeSO_4\)

Which option in the given table correctly represents the substance oxidised and the reducing agent?

A

Substance Oxidized Reducing Agent

Fe Fe

B

Substance Oxidized Reducing Agent

Fe \(FeSO_4\)

C

Substance Oxidized Reducing Agent

Cu Fe

D

Substance Oxidized Reducing Agent

\(CuSO_4\) Fe

Solution

Substance which is oxidized, reduces the other substance. Hence, substance oxidized is itself a reducing agent.
Question 4
1 / -0

The chemical reaction between copper and oxygen can be categorized as

A
Displacement reaction

B
Decomposition reaction

C
Combination reaction

D
Double displacement reaction

Solution

When copper combines with oxygen, the process is known as corrosion or oxidation. When copper reacts with oxygen, then it produces copper oxide, a black color compound.

\(4Cu+O_2\longrightarrow\)\(2CuO_2\) (Combination reaction)
Question 5
1 / -0

Which of the given options correctly represents the Parent acid and base of Calcium Carbonate?

A

PARENT ACID PARENT BASE

\(HCl\) \(NaOH\)

B

PARENT ACID PARENT BASE

\(H_2CO_3\) \(Ca(OH)_ 2\)

C

PARENT ACID PARENT BASE

\(H_3PO_3\) \(CaSO_4\)

D

PARENT ACID PARENT BASE

\(H_2SO_4\) \(CaSO_4\)

Solution

\(H_2CO_3+Ca(OH)_2\longrightarrow\)\(CaCO_3+2H_2O\)

So, Parent acid and parent base for the formation of calcium carbonate is \(H_2CO_3\) and \(Ca(OH)_2\) respectively.
Question 6
1 / -0

How will you protect yourself from the heat generated while diluting a concentrated acid?

A
By adding acid to water with constant stirring

B
By adding water to acid with constant stirring.

C
By adding water to acid followed by base.

D
By adding base to acid with constant stirring

Solution

The process of dissolving an acid or a base in water is a highly exothermic one. The acid must always be added slowly to water with constant stirring. It water is added to concentrated acid, the heat generated may cause the mixture to splash out and cause burns.
Question 7
1 / -0

Why is it important to balance a skeletal chemical equation?

A
To verify law of conservation of energy.

B
To verify the law of constant proportion.

C
To verify the law of conservation of mass

D
To verify the law of conservation of momentum.

Solution

To verify the Law of conservation of mass.
Question 8
1 / -0

Opening and closing of stomatal pore depends on:

A
Atmospheric temperature

B
oxygen concentration around stomata

C
carbon dioxide concentration around stomata

D
water content in the guard cells

Solution

water content in the guard cells
Question 9
1 / -0

Which of the following mirror is used by a dentist to examine a small cavity in a patient’s teeth?

A
Convex mirror

B
Plane mirror

C
Concave mirror

D
Any spherical mirror

Solution

Concave mirror
Question 10
1 / -0

Which of the following can make a parallel beam of light when light from a point source is incident on it?

A
Concave mirror as well as convex lens

B
Convex mirror as well as concave lens

C
Two plane mirrors placed at \(90^{\circ}\) to each others.

D
Concave mirror as well as concave lens

Solution

We light rays from a point source is incident on concave mirror and convex lens, emergent beams are parallel and the image is formed at infinity.

Convex mirror and concave lens on the other hand always form a virtual image. Emergent beams from these are not parallel but diverging when the object is kept at focus.
Question 11
1 / -0

Consider these indices of refraction: glass: 1.52; air: 1.0003; water: 1.333. Based on the refractive indices of three materials, arrange the speed of light through them in decreasing order

A
The speed of light in water > the speed of light in air > the speed of light in glass

B
The speed of light in glass > the speed of light in water > the speed of light in air.

C
The speed of light in air > the speed of light in water > the speed of light in glass.

D
The speed of light in glass > the speed of light in air > the speed of light in water

Solution

Higher the refractive index, lesser is the speed of light in that medium and vice versa.
Question 12
1 / -0

If a beam of red light and a beam of violet light are incident at the same angle on the inclined surface of a prism from air medium and produce angles of refraction r and v respectively, which of the following is correct?

A
r = v

B
r > v

C
\(r=\frac{1}{v}\)

D
r < v

Solution

While passing through the prism, red light bends the least and violet light the most.
Question 13
1 / -0

Vinay observed that the stain of curry on a white shirt becomes reddish-brown when soap is scrubbed on it, but it turns yellow again when the shirt is washed with plenty of water.

What might be the reason for his observation?

i. Soap is acidic in nature

ii. Soap is basic in nature

iii. Turmeric is a natural indicator which gives reddish tinge in bases

iv. Turmeric is a natural indicator which gives reddish tinge in acids

A
i and ii

B
ii and iii

C
i and iv

D
ii and iv

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Substance Oxidized	Reducing Agent
Fe	Fe

Substance Oxidized	Reducing Agent
Fe	\(FeSO_4\)

Substance Oxidized	Reducing Agent
Cu	Fe

Substance Oxidized	Reducing Agent
\(CuSO_4\)	Fe

CBSE Class 10th Science Mix Test - 6

Result

CBSE Class 10th Science Mix Test - 6

Score

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Rank

-

SHARING IS CARING

Question 1

The solution turned red.

Yellow precipitate was formed.

White precipitate was formed.

The reaction mixture became hot.

Solution

Question 2

\(Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+4H_2(g)\)

\(3Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+4H_2(g)\)

\(3Fe(s)+H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+H_2(g)\)

\(3Fe(s)+4H_2O(g)\longrightarrow\)\(Fe_3O_4(s)+H_2(g)\)

Solution

Question 3

Substance Oxidized Reducing Agent Fe Fe

Substance Oxidized Reducing Agent Fe \(FeSO_4\)

Substance Oxidized Reducing Agent Cu Fe

Substance Oxidized Reducing Agent \(CuSO_4\) Fe

Solution

Question 4

Displacement reaction

Decomposition reaction

Combination reaction

Double displacement reaction

Solution

Question 5

PARENT ACID PARENT BASE \(HCl\) \(NaOH\)

PARENT ACID PARENT BASE \(H_2CO_3\) \(Ca(OH)_ 2\)

PARENT ACID PARENT BASE \(H_3PO_3\) \(CaSO_4\)

PARENT ACID PARENT BASE \(H_2SO_4\) \(CaSO_4\)

Solution

Question 6

By adding acid to water with constant stirring

By adding water to acid with constant stirring.

By adding water to acid followed by base.

By adding base to acid with constant stirring

Solution

Question 7

To verify law of conservation of energy.

To verify the law of constant proportion.

To verify the law of conservation of mass

To verify the law of conservation of momentum.

Solution

Question 8

Atmospheric temperature

oxygen concentration around stomata

carbon dioxide concentration around stomata

water content in the guard cells

Solution

Question 9

Convex mirror

Plane mirror

Concave mirror

Any spherical mirror

Solution

Question 10

Concave mirror as well as convex lens

Convex mirror as well as concave lens

Two plane mirrors placed at \(90^{\circ}\) to each others.

Concave mirror as well as concave lens

Solution

Question 11

The speed of light in water > the speed of light in air > the speed of light in glass

The speed of light in glass > the speed of light in water > the speed of light in air.

The speed of light in air > the speed of light in water > the speed of light in glass.

The speed of light in glass > the speed of light in air > the speed of light in water

Solution

Question 12

r = v

r > v

\(r=\frac{1}{v}\)

r < v

Solution

Substance Oxidized Reducing Agent

Fe Fe

Substance Oxidized Reducing Agent

Fe \(FeSO_4\)

Substance Oxidized Reducing Agent

Cu Fe

Substance Oxidized Reducing Agent

\(CuSO_4\) Fe

PARENT ACID PARENT BASE

\(HCl\) \(NaOH\)

PARENT ACID PARENT BASE

\(H_2CO_3\) \(Ca(OH)_ 2\)

PARENT ACID PARENT BASE

\(H_3PO_3\) \(CaSO_4\)

PARENT ACID PARENT BASE

\(H_2SO_4\) \(CaSO_4\)