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Descriptive Statistics Test 13

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Descriptive Statistics Test 13
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  • Question 1
    1 / -0

    Directions For Questions

    Study the following bar chart and answer the questions carefully.

    ...view full instructions

    What is the approximate difference between the average sales turnover of all the companies put together between the years 2001 - 2002 and 2002 - 2003?

    Solution
    The sum of the difference between  two years divided by 5.'
  • Question 2
    1 / -0

    Directions For Questions

    The following bar chart shows the trends of foreign direct investments(FDI) into India from all over the world.

    ...view full instructions

    What was the ratio of investment in 1997 over the investment in 1992?

    Solution
    The 1997 figure of investment as a factor of 1992 investment = (31.36/5.70) = 5.50
  • Question 3
    1 / -0
    Find the mean deviation about the mean of the following data:
    $$15,17,10,13,7,18,9,6,14,11$$.
    Solution
    Let the mean of data be $$u=\dfrac{\sum x_i}{n}=\dfrac {120}{10}=12$$
    Calculating the deviation : $$|x_i-u|$$ we get,
    $$3,5,-2,1,5,6,3,6,2,1$$.
    $$\therefore M.D (u)= \dfrac{\sum{|x_i-u|}}{n}= \dfrac{34}{10}=3.4$$
    Thus, $$M.D(u) =3.4$$.
    Ans- Option $$D$$
  • Question 4
    1 / -0
    Find odd one out:
    Mean, Median, Mode, Variance
    Solution
    Mean, median, mode are the measures of the central tendencies. Therefore, the odd one is the variance.
  • Question 5
    1 / -0
    $${\sigma}^2$$ is  known as 
    Solution
    Variance gives the degree to which the numerical data tend to spread about the value.

    Variance is denoted by $$\sigma^2$$

    Variance is given by $$\dfrac{\sum x^2}{n}-(\dfrac{\sum x}{n})^2$$

    But mean $$\bar x=\dfrac{\sum x}{n}$$

    Therefore, variance is $$\dfrac{\sum x^2}{n}-(\bar x)^2$$

  • Question 6
    1 / -0
    Find odd man out: 
    Standard Deviation, Variance, Mean, Quartile deviation.
    Solution
    Standard deviation, variance, quartile deviation gives the dispersion of the data. Therefore the odd one is mean.
  • Question 7
    1 / -0
    Variance can be calculated using:
    Solution
    Variance gives the degree to which the numerical data tend to spread about the value.

    Variance is given by $$\dfrac{\sum x^2}{n}-(\dfrac{\sum x}{n})^2$$
  • Question 8
    1 / -0

    Directions For Questions

    The following chart shows the production of cars in thousands.

    ...view full instructions

    The ratio of Hindustan Motors production in 2003 - 2004 to Honda's production in 2002 - 2003 is?

    Solution
    The required ratio is (9/6) = 1.5.'
  • Question 9
    1 / -0
    Find the variance of first $$10$$ multiples of $$3$$.
    Solution
    First $$10$$ multiples of $$3$$ are $$3,6,9...30$$.
    This is an A.P.
    $$sum=\dfrac n2 (a+l)= \dfrac {10}{2} \times (3+30)$$
    $$\therefore sum=165$$.
    Mean, $$u=\dfrac {sum}{n}=\dfrac{165}{10}$$.
    Variance, $$\sigma ^2=\dfrac{\sum(x_i ^2)}{n}-u^2$$.
    $$\therefore \sigma ^2=\dfrac{3^2+6^2+...30^2}{10}-{16.5}^2$$.
    $$\therefore \sigma ^2=\dfrac{3\times(1^2+2^2+...10^2)}{10}-{16.5}^2$$.
    $$\therefore \sigma ^2=\dfrac{9\times 10\times (10+1)\times (2\times 10+1)}{6\times 10}-{16.5}^2$$.
    $$\therefore \sigma ^2=346.5-272.25$$
    $$\therefore \sigma ^2=74.25$$
    Ans-Option $$C$$.
  • Question 10
    1 / -0

    Directions For Questions

    Factory$$A$$$$B$$
    Number of Workers$$4000$$$$5000$$
    Mean Wages$$3500$$$$3500$$
    Variance in wages$$64$$$$81$$

    ...view full instructions

    Find the Coefficient of Variation for Factory $$B$$:
    Solution
    Coefficient of Variation, $$C.V=\dfrac{\text{S.D}}{\text{Mean}} \times 100 \%$$
    So, $$C.V_B=\dfrac{{S.D_B}}{{Mean_B}} \times 100 \%$$
    Therefore, $$C.V_B=\dfrac{\sqrt {81}}{3500} \times 100 \%$$
    $$\Rightarrow  C.V_A=0.25714 \%$$.
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