Self Studies

Descriptive Statistics Test 2

Result Self Studies

Descriptive Statistics Test 2
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    The variance of first $$ 50$$ even natural numbers is
    Solution
    $${\textbf{Step-1: Use mean formula and find the mean.}}$$
                     $$\Rightarrow \sigma^2 = \dfrac{1}{n} \sum x_i^2 - \bar{(x)}^2$$
     
                     $$\Rightarrow n = 50, \sum x_i = 2 +4+6+8+...+100$$
                     $${\text{We know that,}}$$
                     $$\Rightarrow \bar {x} = \dfrac{\sum x_i}{n}$$

                     $$\Rightarrow \bar {x} = \dfrac{2 +4+6+8+...+100}{50}$$

                     $$\Rightarrow \bar {x} = \dfrac{50 \times 51}{50}$$ $$[\because \sum 2n = n(n+1)]$$

                     $$\Rightarrow \bar {x} = 51$$
    $${\textbf{Step-2: Put the values in variance formula.}}$$
                     $$\Rightarrow \sigma^2 = \dfrac{1}{n} \sum x_i^2 - \bar{(x)}^2$$
                     $$= \dfrac{1}{50} (2^2 +4^2+6^2+8^2+...+100^2) - {(51)}^2$$
                     $$= \dfrac{1}{50} [({2.1})^2 +({2.2})^2+({2.3})^2+({2.4})^2+...+({2.50})^2] - {(51)}^2$$
                     $$= \dfrac{1}{50} 2^2[({1})^2 +({2})^2+({3})^2+({4})^2+...+({50})^2] - {(51)}^2 ...(1)$$
                     $${\text{But,}}$$
                     $$\Rightarrow ({1})^2 +({2})^2+({3})^2+({4})^2+...+({n})^2 = \dfrac{n(n+1)(2n+1)}{6}$$
                     $$\Rightarrow ({1})^2 +({2})^2+({3})^2+({4})^2+...+({50})^2 = \dfrac{50(50+1)(2 \times 50+1)}{6}$$
                    $$\Rightarrow ({1})^2 +({2})^2+({3})^2+({4})^2+...+({50})^2 = \dfrac{50(51)(101)}{6}$$
                     $${\text{Equation (1) become,}}$$
                     $$= \dfrac{1}{50} 2^2[\dfrac{50(51)(101)}{6}] - {(51)}^2$$
                     $$= 34 \times 101 -2601$$
                     $$ = 3434-2601$$
                     $$=833$$
    $${\textbf{Thus, option B is correct.}}$$
  • Question 2
    1 / -0
    The following line graph shows the yearly sales figures for a manufacturing company. Compute the difference between the sales (in Rs. crores) in $$2002$$ and $$2006$$.

    Solution
    From the graph the value on $$y $$ - axis (denoting sales) for the year $$2002$$ is Rs $$4$$ crore.
    From the graph the value on $$y $$ - axis (denoting sales) for the year $$2006$$ is Rs $$8$$ crore.
    Difference in sales $$= 8 - 4$$ = $$4$$ crore.
  • Question 3
    1 / -0
    The following line graph shows the yearly sales figures for a manufacturing company. What were the sales (in Rs. crores) in $$2002$$?

    Solution
    As shown in the above graph, $$y$$ axis represents the sales(in crores) and $$x$$ axis represents the years.
    So in the year $$2002$$ the sales were upto $$4$$ crore.
  • Question 4
    1 / -0
    The following line graph shows the yearly sales figures for a manufacturing company. What were the sales in $$2005$$?

    Solution
    From the graph the value on $$y - axis$$ (denoting sales) for the year $$2005$$ is Rs. $$10$$ crore
  • Question 5
    1 / -0
    _____  represents data that changes continuously over period of time.
    Solution
    The line graphs shows a change in data over time. A line graph is useful for displaying data or information that changes continuously over time. Another name for a line graph is a line chart.
    Hence, option A is correct.
  • Question 6
    1 / -0

    Directions For Questions

    The following graph shows the temperature of a patient in a hospital, recorded every hour.

    ...view full instructions

    The patient's temperature was same for two times during the period given. These two times were:

    Solution
    From the graph the temperature curve is straight at 1 PM and at 2 PM. 
    This denotes that the temperature of the patient remained  same from 1 PM to 2 PM
    Hence, the answer is 1 pm and 2 pm.
  • Question 7
    1 / -0
    The variance is the _______ of the standard deviation.
    Solution
    Standard Deviation:

    The Standard Deviation is a measure of how spread out numbers are.

    Its symbol is  (the greek letter sigma)

    The formula is easy: it is the square root of the Variance. So now you ask, "What is the Variance?"

    Variance:

    The Variance is defined as: The average of the squared differences from the Mean.

  • Question 8
    1 / -0
    The following line graph shows the yearly sales figures for a manufacturing company. What were the sales (in Rs. crores) in $$2006$$?

    Solution
    From the graph the value on $$y - axis$$ (denoting sales) for the year $$2006$$ is Rs $$8$$ crore
  • Question 9
    1 / -0
    The following line graph shows the yearly sales figures for a manufacturing company. What were the sales (in Rs. crores) in $$2003$$?

    Solution
    From the graph the value on $$y - axis$$ (denoting sales) for the year $$2003$$ is Rs $$7$$ crore
  • Question 10
    1 / -0
    Draw a graph for the following:
    Side of square (in cm)
    2
    3
    4
    5
    6
    Area (in cm$$^2$$)
    4
    9
    16
    25
    36
    Is the graph linear?
    Solution
    Plotting the given points on the graph, we get a graph as shown in the figure above.
    As seen in the graph, the points do not lie on the same straight line. 

    Hence, the graph is not linear.

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now