Self Studies

Descriptive Statistics Test 22

Result Self Studies

Descriptive Statistics Test 22
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Directions For Questions

    The following graph shows the temperature forecast and the actual temperature for each day of a week.

    ...view full instructions

    The actual temperature differs the most from the forecast temperature on:

    Solution
    In the given graph, the dotted line represents the forecast temperature and the straight line represents the actual temperature.

    From the graph, we can observe that the actual temperature and the forecast temperature differs mostly on Thursday i.e., the maximum difference between actual and forecast temperature ($$23.5-15=8.5$$)
  • Question 2
    1 / -0

    Directions For Questions

    A courier person cycles from a town to a neighboring suburban area to deliver a parcel to a merchant. His distance from the town at different times is shown by the following graph.

    ...view full instructions

    How far is the place of the merchant from the town?

    Solution
    It is given that the courier person travels from town to a neighboring suburban area. 

    From the graph, we can observe that the destination place is $$22\space k.m.$$ from the town.
  • Question 3
    1 / -0

    Directions For Questions

    A courier person cycles from a town to a neighboring suburban area to deliver a parcel to a merchant. His distance from the town at different times is shown by the following graph.

    ...view full instructions

    When did the person stop on his way?

    Solution
    The person had stopped between the time $$10$$ a.m to $$10.30$$ a.m.
    This can be easily concluded since the curve on the graph between these times was horizontal to the x-axis which means no distance travelled.
    Hence, option C is correct.
  • Question 4
    1 / -0

    Directions For Questions

    A courier person cycles from a town to a neighboring suburban area to deliver a parcel to a merchant. His distance from the town at different times is shown by the following graph.

    ...view full instructions

    Fastest ride is from interval :

    Solution

    Time                          
    Period
    Distance
    covered
    8am-9am $$10 - 0 =  10 km$$
    9am-10am $$16 - 10 =  6 km$$
    10am-10.30am $$0 km$$
    10.30am-12am $$22 - 16= 6 km$$
    The person ride fastest during 8am to 9am.
  • Question 5
    1 / -0
    The quartile deviation of the income of a certain person given in rupees for 12 months in a year:139, 150, 151,151,157,158,160,161,162,162,173,175
    Solution
    S.NO.Income(Rs)
    1139
    2150
    3151
    4151
    5157
    6158
    7160
    8161
    9162
    10162
    11173
    12175
    $$N=12$$
    $${ Q }_{ 1 }=$$ Size of $$\displaystyle\frac { N+1 }{ 4 } th=3.25th$$ item
    $$=$$ size of $$3rd$$ item $$+0.25$$(size of $$4th$$ item)$$-$$(size of $$3rd$$ item)
    $$=151+0.25(151-151)=$$Rs.$$151$$
    $${ Q }_{ 3 }=$$ Size of $$\displaystyle\frac { 3(N+1) }{ 4 } th=9.75th$$ item
    $$=$$ size of $$9th$$ item $$+0.75$$(size of $$10th$$ item)$$-$$(size of $$9th$$ item)
    $$=162+0.75(162-162)=$$Rs.$$162$$
    $$\therefore$$ Quartile Deviation $$\displaystyle=\frac { 1 }{ 2 } \left( { Q }_{ 3 }-{ Q }_{ 1 } \right) =\frac { 11 }{ 2 } =$$Rs.$$5.5$$
  • Question 6
    1 / -0
    Standard deviation for first 10  natural numbers is
    Solution
    Standard deviation of first $$n$$ natural number is $$\displaystyle =\sqrt{\frac{n^2-1}{12}}=\sqrt{\frac{10^2-1}{12}}=2.87$$  
  • Question 7
    1 / -0
    The quartile deviation of daily wages (in Rs.) of 7 persons given below:
    $$12,7,15,10,17,17,25$$ is
    Solution
    Writing the series in ascending order $$7,10,12,15,17,19,25$$
    $$\displaystyle{ Q }_{ 1 }=\frac { 15+7 }{ 2 } =11,{ Q }_{ 3 }=\frac { 25+15 }{ 2 } =20$$
    $$\therefore$$ Quartile Deviation
    $$\displaystyle=\frac { { Q }_{ 3 }-{ Q }_{ 1 } }{ 2 } =\frac { 20-11 }{ 2 } =4.5$$
  • Question 8
    1 / -0
    Let $${ x }_{ 1 },{ x }_{ 2 },.....{ x }_{ n }$$ be $$n$$ observations with mean $$m$$ and standard deviation $$s$$. Then the standard deviation of the observations $$a{ x }_{ 1 },a{ x }_{ 2 },.....a{ x }_{ n }$$, is
    Solution
    $$S.D(ax) = \sqrt{E[ax-a\bar{x}]^2}=\sqrt{E[a(x-\bar{x})^2]}=\sqrt{a^2.E[(x-\bar{x})^2]}=|a|.\sqrt{E[(x-\bar{x})^2]}=|a|.S.D(x)=|a| s$$
  • Question 9
    1 / -0
    Standard deviation for first 10 even natural numbers is
    Solution
    We know standard deviation of first $$n$$ even natural number is $$, \sigma =\sqrt{\cfrac{n^2-1}{3}}$$
    Here $$n =10$$
    $$\therefore \sigma = \sqrt{\cfrac{100-1}{3}}=\sqrt{33}=5.74$$
  • Question 10
    1 / -0
    Consider the frequency distribution
    Class interval:
    0-6
    6-12
    12-18
    Frequency:
    2
    4
    6
    The variance of the above frequency distribution, is
    Solution
    Class interval$$f_i$$$$x_i$$$$d_i={x_i-A}$$$$d_i^2$$$$f_id_i^2$$$$f_id_i$$
    0-623-63672-12
    6-12490000
    12-1861563621636
    Here,$$N=\sum {f_i }=12$$
    $$\sum {f_id_i^2}=288$$
    $$\sum {f_id_i}=24$$

    Now, variance $$\displaystyle { \sigma  }^{ 2 }=\frac { \sum { f_{ i }d_{ i }^{ 2 } }  }{ N } -{ \left( \frac { \sum { f_{ i }d_{ i } }  }{ N }  \right)  }^{ 2 }$$

    $$\Rightarrow \displaystyle { \sigma  }^{ 2 }=\frac { 288 }{ 12 } -{ \left( \frac { 24 }{ 12 }  \right)  }^{ 2 }$$

    $$\Rightarrow { \sigma  }^{ 2 }=20$$
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now