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Descriptive Statistics Test 5

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Descriptive Statistics Test 5
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  • Question 1
    1 / -0
    $$\Uparrow \quad \Uparrow\quad  \Uparrow \quad \Uparrow$$  Number represented by figure is ____, if each symbol represents 5 houses.
    Solution
    Answer:- one $$\Uparrow$$ represents $$5$$ houses.
    There are total $$4$$ such symbols .
    $$ \therefore \Uparrow \Uparrow \Uparrow \Uparrow \; represents \;4\times 5=20 $$
    B) $$20$$
  • Question 2
    1 / -0
    .

    Solution
    Given that one man symbol represents $$12$$ men.
    Therefore, $$5$$ symbols represents $$12\times 5=60$$ men.
  • Question 3
    1 / -0
    Variance of the distribution $$73, 77, 81, 85,..., 113$$ is
    Solution
    $$73,77,81...113$$ are in A.P

    where $$a=73,d=4$$

    $$\therefore 113=a+\left( n-1 \right) d\Rightarrow 113=73+\left( n-1 \right) 4\\ \Rightarrow 40=\left( n-1 \right) 4\Rightarrow 10=n-1\Rightarrow n=11$$

    $$\displaystyle S=\frac { 11 }{ 2 } \left( 73+113 \right) =1023$$

    $$\displaystyle \overline { x } =\frac { 1023 }{ 11 } =93$$

    Therefore variance $$\displaystyle \frac { \sum { { \left( x-\overline { x }  \right)  }^{ 2 } }  }{ N } =161$$
  • Question 4
    1 / -0

    Directions For Questions

     Answer the following set of questions by reading the above pictograph.

    ...view full instructions

    Number of TV sets sold in the year 1980 is

    Solution
    Answer:- Converting the whole pictograph into frequency distribution table-

     YearNo. of TV sets sold
    $$ \left( in symbol \right) $$
    $$ \left( f_i \right) $$ 
    Actual no. of T sets sold
    $$ \left( f_i \times 500 \right) $$ 
    1980 21000 
    19852500 
    1990 31500 
    19951500 
    2000 2500
    No. of TV sets sold in year 1980 = 1000
    A) 1000
  • Question 5
    1 / -0
    A symbol is used to represent $$10$$ flowers. Number of symbols to be drawn to show $$60$$ flowers is ___
    Solution
    A symbol is used to represent $$10$$ flowers
    Number of symbols to be drawn to represent $$60$$ flowers $$=\dfrac{60}{10}=6$$
  • Question 6
    1 / -0

    Directions For Questions

     Answer the following set of questions by reading the above pictograph.

    ...view full instructions

    $$1000$$ TV sets were sold in the year

    Solution
    Answer:- Converting the whole pictograph into frequency distribution table-

     YearNo. of TV sets sold
    $$ \left( in symbol \right) $$
    $$ \left( f_i \right) $$ 
    Actual no. of T sets sold
    $$ \left( f_i \times 500 \right) $$ 
    $$1980$$ $$2$$$$1000$$ 
    $$1985$$$$5$$ $$2500$$ 
    $$1990$$ $$3$$$$1500$$ 
    $$1995$$$$1$$$$500$$ 
    $$2000$$$$5$$  $$2500$$
    $$1000$$ TV sets sold in year $$1980$$.
    $$C) 1980$$
  • Question 7
    1 / -0
    The line graph shows the monthly expenditure of Vasu family. The total expenditure over the first $$3$$ months is

    Solution
    In the graph, 1 unit on y-axis $$=Rs.100$$

    The monthly expenses of Basu family in the month of

    In January, the expenditure is marked upto $$5$$ units $$=Rs.500$$

    In February, the expenditure is marked upto $$6$$ units $$=Rs.600$$

    In March, the expenditure is marked upto $$3$$ units $$=Rs.300$$

    $$\therefore $$ The total expenditure over the first $$3$$ months $$=Rs.(500+600+300)$$

                                                                                    $$=Rs.1400$$
  • Question 8
    1 / -0

    Directions For Questions

    Answer the following set of questions by reading the above pitctograph.

    ...view full instructions

    Answer the following question by reading the given pictograph.
    Number of TV sets sold in the year 2000 is

    Solution
    From the given pictograph, $$2000$$ has three tv symbol.
    Given that one symbol represents $$500$$ tv sets.
    Therefore the $$2000$$ has $$3\times500= 1500$$ tv sets.
  • Question 9
    1 / -0
    The variance of first n natural numbers is
    Solution

    $$\textbf{Step - 1: Finding the mean}$$

                       $$\text{The } n \text{ natural numbers are } 1, 2, 3,..., n$$

                       $$\text{The Sum of } n \text{ natural number is } \dfrac{{n(n+1)}}{{2}}$$

                       $$\text{Mean} = \dfrac{ \dfrac{{n(n+1)}}{{2}}}{n} = \dfrac{{n+1}}{{2}}$$

    $$\textbf{Step - 2: Finding the Variance}$$

                       $$\text{Variance} = \dfrac{{\sum(x_i)^2}}{{n}} - (\text{Mean})^2$$

                       $$ \sum(x_i)^2 = \dfrac{{1^2 +2^2 + ...+ n^2}}{{n}}$$

                       $$\text{Since } 1^2 +2^2 + ...+ n^2 = \dfrac{{n(n+1)(2n+1)}}{{6}}$$

                       $$\dfrac{{\sum(x_i)^2}}{{n}} = \dfrac{{n(n+1)(2n+1)}}{{6n}}$$

                       $$\text{Variance} =  \dfrac{{n(n+1)(2n+1)}}{{6n}} - (\dfrac{{n+1}}{{2}})^2$$

                       $$=\dfrac{{(n+1)}}{{2}}\times(\dfrac{{2n+1}}{{3}}-\dfrac{{n+1}}{{2}})$$

                       $$= \dfrac{{(n+1)}}{{2}}(\dfrac{{4n+2-3n-3}}{{6}})$$

                       $$=\dfrac{{n+1}}{{2}}\times\dfrac{{n-1}}{{6}}$$

                       $$= \dfrac{{n^2 - 1}}{{12}}$$

    $${\textbf{Hence, the correct answer is Option B}.}$$

  • Question 10
    1 / -0
    The formula of standard deviation of a grouped frequency distribution is
    Solution
    Formula to calculate Standard deviation of a grouped frequency distribution is $$ \sqrt { \frac { \sum { { (x }_{ i }-\bar { x } )^{ 2 } } { f }_{ i } }{ N }  } $$
    where $$ f_1 $$ is the frequency of observation $$ x_i $$ ;
    $$ bar {x} $$ is the mean of the frequency distribution
    $$ N $$ is the sum of all frequencies
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