Self Studies

Set Theory Test 13

Result Self Studies

Set Theory Test 13
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    The solution set of $$3 x - 4 < 8$$ over the set of non-negative square numbers is 
    Solution
    $$3x-4<8$$
    $$3x<12$$
    $$x<4$$
    Hence set of non-negative square numbers belonging to the above set is 
    $$\{1\}$$.
  • Question 2
    1 / -0
    Let $$P$$ and $$Q$$ be two sets then what is $$\displaystyle (P\cap Q')\cup (P\cup Q)'$$ equal to ?
    Solution
    $$\displaystyle (P\cap Q')\cup (P\cup Q)'=(P\cap Q')\cup (P'\cap Q') $$
    $$=$$$$\displaystyle (P\cup P')\cap (P\cup Q')\cap (Q'\cup P')\cap (Q'\cup Q')$$
    $$=$$$$\displaystyle \xi \cap \left \{ Q'\cup (P\cap P') \right \}\cap Q'$$
    $$=\displaystyle \xi \cap \{Q'\cup \xi )\cap Q'$$
    $$=$$$$\displaystyle \xi \cap  Q'\cap Q'=\xi \cap Q'=\xi$$
  • Question 3
    1 / -0
    If $$A$$ and $$B$$ are finite sets which of the following is the correct statement?
    Solution

  • Question 4
    1 / -0
    U is a universal set and n(U) = 160. A, B and C are subset of U. If n(A) = 50, n(B) = 70, $$\displaystyle n\left ( B\cup C \right )=\Phi $$, $$\displaystyle n\left ( B\cap  C \right )=15 $$ and $$\displaystyle A\cup B\cup C=U $$. then n(C) equals
  • Question 5
    1 / -0
    If $$n (A) = 115, n(B) = 326, n(A - B) = 47$$, then $$\displaystyle n(A+B)$$ is equal to 
    Solution
    $$n(A-B)=47\Rightarrow n(A)-n(A\cap B) = 47\Rightarrow n(A\cap B)=115-47=68$$

    Hence $$n(A+B)=115+326-68=373$$
  • Question 6
    1 / -0
    If A and B are two disjoint sets and N is the universal set then $$\displaystyle A^{c}\cup \left [ \left ( A\cup B \right )\cap B^{c} \right ]$$ is
    Solution
    Since $$A$$ and $$B$$ are disjoint sets $$B^c\cap(A\cup B)$$ will be only $$A$$ as there is no intersection between $$A$$ and $$B$$.

    Of course $$A^c\cup A=N$$
  • Question 7
    1 / -0
    Suppose $$\displaystyle A_{1},A_{2},....,A_{30}$$ are thirty sets each having 5 elements and $$\displaystyle B_{1},B_{2},....,B_{n}$$ are n sets each with 3 elements. Let $$\displaystyle \bigcup_{i=1}^{30}A_{i} = \bigcup_{j=1}^{n}B_{j}=S $$ and each elements of S belongs to exactly 10 of the $$\displaystyle A_{i}$$ and exactly 9 of the $$\displaystyle B_{j}$$. Then n is equal to-
    Solution
    $$A_0,A_1,.............,A_{30}\implies$$ each of 5 elements
    $$B_1,B_2,B_3...........n\implies$$ each of 3 elements
    The number of elements in the union of the A sets is $$5(30)-r$$ where 'r' is the number repeats likewise the number of elements in the B sets $$3n-rB$$
    Each element in the union (in5) is repeated 10 times in A which means if x was the real number of elements in A (not counting repeats) then q out of those 10 should be thrown away or 9x .likewise on the B side 8x of those elements should be thrown away So, $$\implies 150-9x=3n-8x$$
    $$n=50-3x$$
    Now in figure out what x is we need to use the fact that the union of a group of sets contains every member of each sets . If every element in 'S' is repeated 10 times that means every element in the union of the n's is repeated 10 times .
    This means that  $$10/10\implies 15$$ is the number of in the A's without repeats counted (same for the B's aswell ) So now 
    $$\cfrac{50-15}{3}=n$$
    $$n=45$$
    Subset:- A proper subset is nothing but it contain atleast one more element of main set .
    Ex:$$\{3,4,5\}$$  is a set then the possible subsets are 
    $$\{3\},\{4\},\{5\},\{1,5\},\{3,4\}$$
  • Question 8
    1 / -0
    Suppose $$\displaystyle A_{1},A_{2}.....A_{30}$$ are thirty sets having 5 elements and $$\displaystyle B_{1},B_{2}....B_{n}$$ are n sets each with 3 elements. Let $$\displaystyle \bigcup_{i=1}^{30}Ai=\bigcup_{i=1}^{n}Bj=S$$ and each elements of S belongs to exactly 10 of the Ai's and exactly 9 of the Bj's. Then n is equal to 
    Solution
    Since each element of S belongs to $$10$$ $$ A_{i}s$$, there are only $$15 $$elements in S $$\left[\dfrac{30\times 5}{10}\right]$$

    Since each of the $$15$$ elements belongs to 9 $$B_j s$$ there are 135 elements in the second union.

    No. of sets $$=\dfrac{135}{3}=45$$
  • Question 9
    1 / -0
    S = {1, 2, 3, 5, 8, 13, 21, 34}. Find $$\displaystyle \sum max\left ( A \right )$$ where the sum is taken over all 28 two elements subsets A to S
    Solution

  • Question 10
    1 / -0
    Given n(A) = 11, n(B) = 13, n(C) = 16, $$\displaystyle n\left ( A\cap B \right )=3,n\left ( B\cap C \right )=6,n\left ( A\cap C \right )=5\: \: and\: \: n\left ( A\cap B\cap C \right )=2$$ then the value of $$\displaystyle n [ A\cup B \cup C ]=$$
    Solution
    We know,
    $$n(A\cup B\cup C)= n(A) +n(B) +n(C)-n(A\cap B)-n(B\cap C) -n(C\cap A) + n(A\cap B \cap C)$$

    $$=11+13+16-3-6-5+2=28$$
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now