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Relations Test 2

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Relations Test 2
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Weekly Quiz Competition
  • Question 1
    1 / -0
    If X is brother of the son of Y's son. How is X related to Y?
    Solution
    Son of Y's Son- Grandson, Brother of Y's Grandson- Y's Grandson
    Option D is correct.
  • Question 2
    1 / -0
    If $$A=\left \{x:x^2-3x+2=0\right \}$$ and $$B=\left \{x:x^2+4x-5=0\right \}$$ then the value of A-B is
    Solution
    $$A=\left \{x:x^2-3x+2=0\right \}\Rightarrow A=\left \{1, 2\right \}$$
    $$B=\left \{x:x^2+4x-5=0\right \}\Rightarrow A=\left \{1, -5\right \}$$
    $$\therefore A-B=\left \{2\right \}$$
  • Question 3
    1 / -0
    Suppose y is equal to the sum of two quantities of which one varies directly as x and the other inversely as x If y = 6 when x = 4 and $$\displaystyle y=\frac{10}{3}$$ when x = 3 then what is the relation between x and y?
    Solution
    (A)If$$y=X+\frac{4}{x}\Rightarrow 4+\frac{4}{4}=3 \neq 6=6$$
    (B)$$y+2x=\frac{4}{x}\Rightarrow 6+2(4)=\frac{4}{4}\Rightarrow 6+8\neq 1$$
    (C)$$y=2x+\frac{8}{x}\Rightarrow 6=2(4)+\frac{8}{4}\Rightarrow 6\neq 8+2$$
    (D)$$y=2x-\frac{8}{x}\Rightarrow 6=2(4)-\frac{8}{4}=8-2=6$$ If x=4 and y=6
    $$y=2x-\frac{8}{x}\Rightarrow \frac{10}{3}=2\times 3-\frac{8}{3}\Rightarrow \frac{10}{3}=\frac{10}{3}$$ If x=3 and y=$$y=\frac{10}{3}$$
    Then option (D)  $$Y=2x-\frac{8}{x}$$
  • Question 4
    1 / -0
    x varies directly as y and inversely as the square of z. When y = 4 and z is 14 x = 10. If y = 16 and z = 7 what is x?
    Solution
    Given x varies directly as y and inversely as the square of z. When y = 4 and z is 14 x = 10. If y = 16 and z = 7 
    Then $$x=k\frac{y}{z^{2}}$$
    $$\Rightarrow 10=k\times \frac{4}{14\times14}$$
    $$\Rightarrow k=490$$
    Thus $$x=490\times \frac{16}{7\times 7}=160$$
  • Question 5
    1 / -0
    The number of reflexive relations of a set with four elements is equal to
    Solution
    Total number of reflexive relations in a set with n elements = 2$$^n$$ Therefore, total number of reflexive relations set with 4 elements = 2$$^4$$
  • Question 6
    1 / -0
    If R={$$(x,y)/3x+2y=15$$ and x,y $$\displaystyle \epsilon $$ N}, the range of the relation R is________
    Solution
    Given, $$ 3x + 2y = 15 $$

    $$ => y = \dfrac {15-3x}{2} $$
    As both $$ x , y $$ are natural numbers, we should find $$ x $$ such that $$ 15-3x $$ is divisible by $$ 2 $$

    We can see that when $$ x =1$$  or $$3 $$, we get $$ y = 6$$  or  $$3 $$

    Hence, the range is $$ {3,6} $$
  • Question 7
    1 / -0
    Let $$R$$ be the relation in the set $$N$$ given by $$R=\left\{(a, b): a=b-2, b>6\right\}$$. Choose the correct answer.
    Solution
    $$R=\left\{(a, b):a=b-2, b>6\right\}$$
    Now, since $$b>6, (2, 4)\notin R$$
    Also, as $$3\neq 8-2, (3, 8)\notin R$$
    And, as $$8\neq 7-2$$
    $$\therefore (8, 7)\notin R$$
    Now, consider $$(6, 8)$$.
    We have $$8 > 6$$ and also, $$6=8-2$$.
    $$\therefore (6, 8)\in R$$
    Hence the correct answer is C.
  • Question 8
    1 / -0
    If ordered pair $$(a, b)$$ is given as $$(-2, 0)$$, then $$a =$$
    Solution
    $$a$$ will be first entry in ordered pair $$(a, b).$$
    So, option A is correct.
  • Question 9
    1 / -0
    If $$x$$ co-ordinate of a point is $$2$$ and $$y$$ co-ordinate is $$0$$, then ordered pair for its coordinate on $$XY$$ plane is
    Solution
    Ordered pair for co-ordinate of a point in $$XY$$ plane is written as $$(x, y).$$
    So, option D is correct.
  • Question 10
    1 / -0
    What are the ways of representing a relation?
    Solution
    Relation can be represented in set builder form, roster form and Arrow diagram.
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