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Number Theory Test 10

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Number Theory Test 10
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  • Question 1
    1 / -0
    The smallest 3 digit prime number is:
    Solution
    The smallest 3-digit number is $$100$$, which is divisible by $$2$$.
    $$\therefore$$ $$100$$ is not a prime number.
    $$\sqrt{100}< 11$$ and $$101$$ is not divisible by any of the prime numbers $$2,3,5,7,11$$.
    $$\therefore$$ $$101$$ is a prime number.
    Hence $$101$$ is the smallest 3-digit prime number.
  • Question 2
    1 / -0
    What is the value of $$x$$ for which $$x, x + 1, x + 3$$ are all prime numbers?
    Solution
    Option $$A :$$ Substitute $$x=0,$$
    $$x,x+1,x+3=0,1,3$$ are not prime numbers.

    Option $$B :$$ Substitute $$x=1,$$
    $$x,x+1,x+3=1,2,4$$ are not prime numbers. 

    Option $$C :$$ Substitute $$x=2,$$
    $$x, x + 1, x + 3=2,3,5$$ which are all prime numbers.

    Hence, option $$C$$ is correct.
  • Question 3
    1 / -0
    Which of the following number is a prime?
    Solution
    $$667$$ is divisible by $$23$$
    $$861$$ is divisible by $$3$$
    $$481$$ is divisible by $$13$$
    $$331$$ is divisible only by $$1$$ and $$331$$.
    $$\therefore 331$$ is a prime number.
  • Question 4
    1 / -0
    What is the modulus of $$\cfrac { \sqrt { 2 } +i }{ \sqrt { 2 } -i } $$ where $$i=\sqrt { -1 } $$
    Solution
    $$\left| \dfrac { \sqrt { 2 } +i }{ \sqrt { 2 } -i }  \right| =\dfrac { \sqrt { ({ \sqrt { 2 }  })^{2}+{ 1 }^{ 2 } }  }{ \sqrt { (\sqrt { 2 })^{ 2 }+(-1)^{ 2 } }  } =1$$
    Hence, option C is correct.
  • Question 5
    1 / -0
    Consider the following numbers.
    1. $$247$$
    2. $$203$$
    Which of the above number is/are prime?
    Solution
    A number which is divisible by itself and $$1$$ are prime numbers.
    1. $$247 = 13\times 19$$
    2. $$203 = 7\times 79$$
    Here both the numbers have some divisors. 
    So, none of the two are prime.
  • Question 6
    1 / -0
    Which one of the following is a prime number?
    Solution
    $$184 = 23\times 8$$ 
    Therefore, cannot be prime
    $$171 = 19\times 9$$ 
    Therefore,cannot be prime
    $$221 = 17\times 13$$
    Therefore, cannot be prime
    Hence, by elimination we have $$173$$ as a prime number.
  • Question 7
    1 / -0
    If $$\cos { \left( \log { { i }^{ 4i } }  \right)  } =a+ib$$, then
    Solution
    Given, $$a+ib=\cos { \left( \log { { i }^{ 4i } }  \right)  } $$
    $$=\cos { \left[ 4i\log { i }  \right]  } =\cos { \left[ 4i\log { \left( { e }^{ i\cfrac { \pi  }{ 2 }  } \right)  }  \right]  } =\cos { \left[ \left( 4i \right) \left( i\cfrac { \pi  }{ 2 }  \right)  \right]  } =\cos { \left( -2\pi  \right)  } =1$$
    $$\therefore a=1;b=0$$
  • Question 8
    1 / -0
    Which of the following numbers is prime?
    Solution
    $$119$$ is divisible by $$7$$
    $$187$$ is divissible by $$11$$
    $$247$$ is divisible by $$13$$
    Bt $$179$$ is not divisible by any number.
    Hence $$179$$ is a prime number.
  • Question 9
    1 / -0
    $$( 7 \times 11 \times 13 + 13 )$$ is a/an
    Solution
    $$(7\times 11\times 13+13)=13\{(7\times11)+1\}=13\times 78=1014$$
    Since, $$1014$$ is divided by $$13,78$$ which is other than $$1$$ and the number itself, so it is a composite number.
  • Question 10
    1 / -0
    The reciprocal of the smallest prime number is _______.
    Solution
    Prime no. are those which has only two factors. 
    One and the number itself.
    $$Note:$$ $$1$$ is neither prime nor composite.
    So, the smallest prime number is $$2$$.
    Hence, reciprocal of $$2$$ $$= \dfrac{1}{2}$$
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