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Number Theory Test 46

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Number Theory Test 46
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  • Question 1
    1 / -0
    The real part of $$(i - \sqrt{3})^{13}$$ is
    Solution
    $$w^2=\dfrac{-1-i\sqrt3}{2}$$
    $$\Rightarrow iw^2=\dfrac{-i+\sqrt3}{2}$$
    $$\Rightarrow -2iw^2=i-\sqrt3$$
    $$\Rightarrow (-2iw^2)^{13}=(i-\sqrt3)^{13}$$
    $$\Rightarrow -2^{13}i^{13}w^{26}=(i-\sqrt3)^{13}$$
    $$\Rightarrow -2^{13}iw^2=(i-\sqrt3)^{13}$$
    $$\Rightarrow -2^{13}\left({\dfrac{-i+\sqrt3}{2}}\right)=(i-\sqrt3)^{13}$$
    $$\Rightarrow -2^{12}(-i+\sqrt3)=(i-\sqrt3)^{13}$$
    $$\therefore (i-\sqrt3)^{13}=-2^{12}\sqrt3+i2^{12}$$

  • Question 2
    1 / -0
    $$(1-\sqrt{-1})(1+\sqrt{-1})(5-\sqrt{-7})(5+\sqrt{-7})=?$$
    Solution
    Given expression 
    $$=(1-i)(1+i)(5-\sqrt 7 i)(5+\sqrt 7i)$$
    $$=(1-i^2)(25-7i^2)\\=(1+1)(25+7)\\=(2\times 32)=64$$.
  • Question 3
    1 / -0
    Mark against the correct answer in each of the following .
    $$i^{326}=$$?
    Solution
    $$i^{326}\\=(i^4)^{81}\times i^2 =(1)^{81}\times (-1)\\=1\times (-1)=-1$$
  • Question 4
    1 / -0
    If $$\mid z^2 - 3\mid = 3\mid z\mid$$ then the maximum value of $$\mid z\mid$$ is
    Solution
    $$ \mid z^{2} - 3 \mid \geq \mid z \mid^{2} - 3$$

    $$\Rightarrow 3 \mid z \mid \geq \mid z \mid ^{2} - 3$$

    $$\Rightarrow \mid z \mid ^{2} - 3 \mid z \mid -3 \leq 0$$

    $$\Rightarrow 0 < \mid z \mid \leq \dfrac{3 + \sqrt{21}}{2}$$

  • Question 5
    1 / -0
    Mark against the correct answer in each of the following .
    $$i^{91}=$$?
    Solution
    $$i^{91}\\=(1^4)^{22}\times i^3 \\=1\times i^2 \times i\\=1\times (-1)\times i\\=-i$$
  • Question 6
    1 / -0
    $$(2-3i)(-3+4i)=?$$
    Solution
    $$(2-3i)(-3+4i)\\=(-6+8i+9i-12i^2)\\=(-6+17i+12)\\=(6+17i)$$.
  • Question 7
    1 / -0
    Mark against the correct answer in each of the following .
    $$i^{273}=$$?
    Solution
    $$i^{273}=(i^4)^{68}\times i=(1)^{68}\times i=(1\times i)=i$$
  • Question 8
    1 / -0
    Compare List I with List II and choose the correct answer using codes given below:
    List I (Complex number)List II (Its modulus)
    $$(4-3i)$$$$10$$
    $$(8+6i)$$$$\dfrac{1}{5}$$
    $$\dfrac{1}{(3+4i)}$$$$1$$
    $$\dfrac{(3-4i)}{(3+4i)}$$$$5$$
    Solution

  • Question 9
    1 / -0
    Which of the following is a composite number?
    Solution
    (a) $$23$$
    Since it cannot be broken into factors
    Hence $$23$$ is not a composite number
    (b) $$29$$
    Since it cannot be broken into factors
    Hence $$29$$ is not a composite number
    (c) $$32$$
    Since it can be broken into factors i.e.$$2 \times 2 \times 2 \times 2 \times 2$$
    Hence $$32$$ is a composite number
    Option (c) is the correct answer
  • Question 10
    1 / -0
    Which of the following is an odd composite number ?
    Solution
    $$ 9 = 3 \times 3 $$ , is an odd composite number.
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