Logarithm and A...

Approximate of $$\log_{11}21$$ is

$$2^{1/4}4^{1/8}8^{1/16}16^{1/32}$$....... is equal to

If $$\log_{10} 2 = 0.3010$$, then the number of digits in $$2^{64}$$ is

Evaluate using logarithm table: $$\dfrac {28.45 \times \sqrt [3] {0.3254}}{32.43 \times \sqrt [5] {0.3046}}$$

If $$\dfrac{\log_{2}a}{4} = \dfrac{\log_{2}b}{6} = \dfrac{\log_{2}c}{3p}$$ and also $$a^{3}b^{2}c = 1$$, then the value of $$p$$ is equal to

Given $$log_3(a) = c$$ and $$log_3(b)=2c, a =$$

The number $$ N=6 \log_{10}2+\log_{10}31$$ lies between two successive integers, whose sum is equal to

Let $$a = \log_3\log_32$$. An integer k satisfying  $$1< 2^{(-k+3^{-a})} < 2,$$  must be less than _____.

If $$log_AD= a, $$ then value of $$log_612$$ is (in terms of a)

If $$x=198!$$ then value of the expression $$\dfrac {1}{\log_{2}x}+\dfrac {3}{\log_{2}x}+...\dfrac {198}{\log_{2}x}$$ equals ?