Transport in Plants Test

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Transport in Plants Test - 34

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Weekly Quiz Competition

Question 1
1 / -0

If there is high amount of fertilizer present in soil and it is deficient in water, then what will be the effect?

A
Over growth

B
Under growth

C
No effect

D
Wilting of plants

Solution

Water moves from a region of high water potential to a region of low water potential. Water potential depends on the number of water molecules in the system or solution. When soil is poorly watered but rich in fertilizers, the water potential of soil will be low. The soil solution will be hyperosmotic as compared to cell sap and the roots may not absorb water. This will lead to wilting.
Question 2
1 / -0

A root hair cell under ordinary conditions have a water potential in the range of

A
1 to 4 atm

B
-1 to - 4 atm

C
1 to 2 atm

D
-1 to 2 atm

Solution

Water potential depends on the number of molecules of water in the system. More the number of water molecules more the water potential. Water potential of pure water is maximum and is zero. Water potential of all solutions is hence negative.
Water always moves from a region or solution of higher water potential to a region or solution of lower water potential. Hence, water potential of root cells cannot be more than zero or have positive value. The water potential of root cells should be less than zero, i.e., have a negative value.
So, the correct answer is '-1 to - 4 atm'
Question 3
1 / -0

Water potential ($$\psi$$) of a solution is always

A
+ Ve

B
- Ve

C
Zero

D
Variable

Solution

Water potential is the chemical potential of water and depends on the number of water molecules. When a solute has been dissolved in water, there is a relative decrease in number of solvent or water molecules. Hence, water potential decreases. The water potential of pure water has been fixed as zero. The water potential of all solutions is negative.
Question 4
1 / -0

If a plasmolysed cell is placed in distilled water then it returns to its original state and become turgid, this is called as

A
Plasmolysis

B
Exosmosis

C
Endosmosis

D
Deplasmolysis

Solution

If a cell is kept in hypertonic solution exosmosis occurs and water moves out from the cell into the solution. This process is called as exosmosis and leads to plasmolysis. In a plasmolyzed cell the cell contents or protoplasm leaves cell wall and gets shrunk. If the same cell is now placed in a hypotonic medium or distilled water, it will gain water due to endosmosis and again become turgid. This cell is now called as deplasmolysed cell. Thus, the correct answer is option D.
Question 5
1 / -0

Osmotic potential ($$\psi_S$$) of a solution is always

A
Positive

B
Negative

C
Zero

D
Variable

Solution

Osmotic potential by definition is the decrease in value of water potential, due to presence of solutes. More the concentration of dissolved solutes more the decrease in water potential and more negative the value of osmotic potential.
Question 6
1 / -0

When the solute has been added to the solution; its water potential will

A
Increase

B
Decrease

C
Remain unchanged

D
First increase then decrease

Solution

Water potential is the chemical potential of water and depends on the number of water molecules. When a solute has been dissolved in water, there is a relative decrease in number of solvent or water molecules. Hence, water potential decreases. The water potential of pure water has been fixed as zero. The water potential of all solutions is negative.
Question 7
1 / -0

Water potential is affected by

A
Osmotic potential

B
Matrix potential

C
Pressure potential

D
All of the above

Solution

Water potential is the chemical potential of water and depends on the number of water molecules. Its value is determined by osmotic potential (due to dissolved solutes), matrix potential (due to absorption of water by the protoplasm) and pressure potential (due to the pressure generated by protoplasm on cell wall due to absorption of water).
Question 8
1 / -0

Root pressure is measured by

A
Manometer

B
Potometer

C
Auxanometer

D
Osmometer

Solution

Root pressure is caused due to active absorption of mineral salts, which leads to a passive flow of water into the roots from the soil solution. Root pressure can be measured by a manometer in which a mercury filled glass column is placed on a cut plant stump. The level of mercury in glass column will reveal the root pressure magnitude.
So, the correct answer is option A.
Question 9
1 / -0

Value of water potential for pure water is

A
1

B
2

C
3

D
0

Solution

Water potential depends on the number of water molecules in a solution. It is also called as chemical potential of water. Water naturally flows from a region of high water potential to a region of low water potential. By convention water potential of pure water is assumed to be zero.
Question 10
1 / -0

Why hygroscopic water is not available to plants?

A
Because its $$\psi_\omega$$ is greatly increased

B
Because its DPD is greatly decreased

C
Because its $$\psi_\omega$$ is strongly negative

D
Because its $$\psi_\omega$$ is increased and DPD is decreased

Solution

Water flows from a region of high water potential to a region of low water potential. Hygroscopic water is the water tightly held around soil particles as a thin film. It is not available to plants, because it has very low water potential (strongly negative). In other words it has very less water molecules or it is present as an extremely thin film. Water present in capillary spaces of soil is freely available to plants.

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Re-Attempt Weekly Quiz Competition

Transport in Plants Test - 34

Result

Transport in Plants Test - 34

Score

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Rank

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SHARING IS CARING

Question 1

Over growth

Under growth

No effect

Wilting of plants

Solution

Question 2

1 to 4 atm

-1 to - 4 atm

1 to 2 atm

-1 to 2 atm

Solution

Question 3

+ Ve

- Ve

Zero

Variable

Solution

Question 4

Plasmolysis

Exosmosis

Endosmosis

Deplasmolysis

Solution

Question 5

Positive

Negative

Zero

Variable

Solution

Question 6

Increase

Decrease

Remain unchanged

First increase then decrease

Solution

Question 7

Osmotic potential

Matrix potential

Pressure potential

All of the above

Solution

Question 8

Manometer

Potometer

Auxanometer

Osmometer

Solution

Question 9

1

2

3

0

Solution

Question 10

Because its $$\psi_\omega$$ is greatly increased

Because its DPD is greatly decreased

Because its $$\psi_\omega$$ is strongly negative

Because its $$\psi_\omega$$ is increased and DPD is decreased

Solution

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