Transport in Plants Test

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Transport in Plants Test - 66

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Question 1
1 / -0

The two chambers, A and B, containing solution are separated by a semipermeable membrane.
In which direction will osmosis occur?

A
A $$\rightarrow$$ B

B
B $$\rightarrow$$ A

C
Osmosis will not occur

D
Cannot be determined
Solution
- Osmosis is a process in which solvent passes through a semipermeable membrane from an area of less concentration to the area of more concentration of solute.
- In the given example, chamber A contains a high concentration of solutes as compared to chamber B. Hence, the solution will move from B to A through the semipermeable membrane until an equilibrium is attained.
Thus, the correct answer is 'B → A.'
Question 2
1 / -0

Which relationship is considered correct for a solution in beaker?

A
$${ \Psi }_{ w }={ \Psi }_{ s }+{ \Psi }_{ p }$$

B
$${ \Psi }_{ s }={ \Psi }_{ w }+{ \Psi }_{ p }$$

C
$${ \Psi }_{ w }={ \Psi }_{ s }$$

D
$${ \Psi }_{ p }={ \Psi }_{ w }$$

Solution

Water potential is the potential energy of water in a system compared to pure water when both temperature and pressure are kept the same. It can also be described as a measure of how freely water molecules can move in a particular environment or system. It is measured in kilopascals (kPa) and is represented by the Greek letter Psi (Ψ).
The formula used to calculate Ψ is the following:
Ψ = Ψs + Ψp
Here, Ψs stands for solute potential, Ψp for pressure potential.
So the answer is option A ' Ψw=Ψs+Ψp'.
Question 3
1 / -0

What will be the direction of movement of solvent according to following diagram?

A
A to B

B
B to A

C
Hypertonic solution to hypotonic solution

D
No movement

Solution

Water potential is the potential energy of water per unit volume relative to pure water. Pure water has a water potential of zero. Solutes reduce water potential. Solution B has a higher water potential of -4 bars. Solution A has a lower water potential of -9 bars.
Hence, the solvent will move from chamber B to A in order to attain equilibrium. At equilibrium, both the chambers will have the same water potential.
Thus, the correct answer is option B.
Question 4
1 / -0

The two chambers, A and B, containing solution are separated by a semipermeable membrane.
The solution of which chamber has a lower water potential?

A
A

B
B

C
Both has the same water potential

D
Cannot be determined

Solution

Water potential is the potential energy of water per unit volume relative to pure water. Pure water has water potential of zero. Solutes reduce water potential. Hence, solution A has lower water potential due to the presence of high amount of solutes as compared to that in solution B.
Thus, the correct answer is 'A.'
Question 5
1 / -0

Which of the following is an incorrect match

A
Osmometer = measure rate of osmosis

B
Potometer = measure rate of transpiration

C
Porometer = measure area of stomata on leaf

D
Cobalt- chloride test = comparision of transpiration by two surface of a leaf

Solution

A. Osmometer= measure osmotic pressure not the rate of osmosis
B. Potometer= measure rate of transpiration
C. Porometer= measure area of stomata on leaf
D. Cobalt- chloride test= comparison of transpiration by two surfaces of a leaf
So, the correct option is A.
Question 6
1 / -0

The two chambers, A and B, containing solution are separated by a semipermeable membrane.
Which solution has a higher solute potential?

A
A

B
B

C
Both has the same solute potential

D
Cannot be determined
Solution
- Solute potential is also called as osmotic potential. It is the potential of a solution which allows the water to enter in it by diffusion or osmosis due to the presence of the solute material.
- Since solution A has higher solute concentration as compared to that in solution B, solution A has higher solute potential.
Thus, the correct answer is 'A.'
Question 7
1 / -0

Water channel consists of how many type of aquaporins?

A
1

B
80

C
8

D
9
Solution
The porins are proteins that form huge pores in the outer membranes of the plastids, mitochondria, and some bacteria allowing molecules up to the size of small proteins to pass through an extracellular molecule bound to the transport protein (the transport protein then rotates and releases the molecule inside the cell). For example, water channels – made up of eight different types of aquaporins.
So, the correct answer is '8'.
Question 8
1 / -0

In 0.1 M solution of a non-electolyte , $$\psi$$$$_w$$ (water potential) value will be

A
zero bar

B
+ 2.3 bar

C
-2.3 bar

D
-22.4 bar

Solution

Water potential of pure water is zero.
As a solute is added, water potential decreases and becomes negative.
Water potential can be calculated as:
ψ (water potential) = ψ P (pressure potential) + ψ S (solute potential)
For the 0.1 M solution of a non electrolyte, ψ P is 0 bar and is ψ S is -2.3 bar
So,
ψ = 0 bar + (-2.3 bar)
ψ = -2.3 bar
So, the correct answer is '-2.3 bar'.
Question 9
1 / -0

When a cell is plasmolysed, it becomes

A
Flaccid and its TP becomes zero

B
Turgid and its TP becomes zero

C
Turgid and TP becomes equal to OP

D
Flaccid and DPD becomes zero

Solution

When a cell is placed in a hypertonic solution, the water moves from the cell to the outside. This results in the shrinkage of the cytoplasm. This cell is called as plasmolylsed cell. The cell becomes flaccid. Cell which has lost water and there is a gap between cell wall and protoplasm is called as flaccid cell. In this condition, the turgor pressure (TP) becomes zero. Turgor pressure is a pressure that pushes plasma membrane against the cell wall.
Thus, the correct answer is 'Flaccid and its TP becomes zero.'
Question 10
1 / -0

The diagram below shows two solutions that are separated by a semi-permeable membrane. In which direction will most water molecules move?

A
From X to Y, decreasing the concentration gradient of sucrose

B
From X to Y, increasing the concentration gradient of sucrose

C
From Y to X, decreasing the concentration gradient of sucrose

D
From Y to X, increasing the concentration gradient of sucrose

Solution

Most water molecular move from x to y decreasing the concentration gradient of sucrose. The solution will always move down the concentration gradient.
This means the water always move from this is more water to where there is less water.
Therefore, water will move from a hypotonic solution to the hypertonic solution.