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Transport in Plants Test - 73

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Transport in Plants Test - 73
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  • Question 1
    1 / -0
    Transpiration is defined as:
    Solution
    Transpiration is the loss of water vapour from the aerial part (leaves) of a plant.
    Thus, the correct answer is (C).
  • Question 2
    1 / -0
    Where does maximum transpiration occur from?
    Solution
    Stomata are primary structures for gaseous exchange and release of water in the form of water vapour or transpiration. Stomata are present in large number on the abaxial surface in dicots leaves and equally distributed on both surfaces in monocot leaf.
    Lenticels and Cuticle are additional structures of transpiration, while hydathodes exude water droplets.
    So, the correct answer is 'Stomata.'

  • Question 3
    1 / -0
    Raisins swell when put in:
    Solution
    Raisins swell because of the process of osmosis (Solvent tend to pass through a semipermeable membrane from a less concentrated solution into a more concentrated one). 
    When raisins put into water (solvent) with less amount of salt (e.g. Rainwater).
    Thus, the correct answer Rainwater from the given above options.
  • Question 4
    1 / -0
    An ideal molar solution at $$0^{0}C$$ will have an osmotic pressure of
    Solution

    Osmotic pressure refers to the minimum pressure that needs to be applied to a solution to prevent the inward flow of water in a semipermeable membrane. Jacobus Van't Hoff proposed the law which relates the osmotic pressure to solute concentration which states that osmotic pressure is simply proportional to the solute concentration and when the solute concentration is sufficiently low that the solution is considered as the ideal solution. According to the Van't Hoff equation, an ideal solution that contains 1 mole of dissolved particles per litre of solvent at 0° C will have an osmotic pressure of 22.4 atm.
  • Question 5
    1 / -0
    If a potted plant is covered with a glass jar, water vapours appear on the wall of the glass jar. This phenomenon occurs .............
    Solution
    It occurs due to transpiration. Transpiration is the process by which moisture is carried through plants from roots to small pores on the underside of leaves, where it changes to vapor and is released to the atmosphere. Transpiration is essentially evaporation of water from plant leaves.
    Therefore, the correct answer is option A.
  • Question 6
    1 / -0
    Dry wooden stakes, if driven into a small crack in a rock and then soaked, can develop enough pressure to split the rock. Such pressure is build up through the phenomenon of
    Solution
    Imbibition is a physical process in which a dry surface absorbs water. In rocks, the dead material absorbs water resulting in an increase in volume, which splits the rock. This process is the primary force responsible for the cracking of rocks in nature and leads to weathering of rocks. Weathering of rocks is an important step in soil formation.
    So, the correct answer is option A.
  • Question 7
    1 / -0
    The osmotic potential and pressure potential of three cells (A,B,C) located in different parts of an actively transpiring plant are given below.
    Cell
    Osmotic potential
            (mpa)
    Pressure potential
           (mpa)
    A
    -0.87
    0.44
    B
    -0.92
    0.34
    C
    -0.68
    0.27
    Identify these three cells as root hair, root cortical and leaf mesophyll cells respectively.
    Solution
    Water potential is calculated by the sum of osmotic potential and pressure potential. Further water moves from higher water potential to lower water potential. The calculated values of water potential for three cells A, B and C are -0.43, -0.58 and -0.41. Thus water will flow from C to A to B. This indicates that cell C must be root hair, A must be root cortex and B must be leaf mesophyll.
    So, the correct answer is 'C, A, B'
  • Question 8
    1 / -0
    The ratio of osmotic pressure exerted by 1 M sucrose and 1 M $$NaCl$$ solution will be
    Solution
    • The osmotic pressure depends on the concentration of solute molecules in the solution.
    • A molecule of sodium chloride will break up into two ions of sodium and chloride after dissolving in water.
    • While a molecule of sucrose will not break up into separate ions. 
    • Since the no. of solutes will be double in the case of $$NaCl$$ solution then the solution of sucrose, the ratio of osmotic pressure exerted by the solution of an equal concentration of sucrose and sodium chloride will be 1:2, i.e. - 0.5.

    So, the correct answer is 'option D'.
  • Question 9
    1 / -0
    When osmotic potential is either zero or negative and pressure potential is positive, then the water potential will be
    Solution
    Water potential of a solution is always negative because by convention water potential of pure water is assumed to be zero. When solutes are dissolved in water, then water potential decreases. But for a cell the formula to calculate water potential is that water potential is algebraic sum of osmotic potential (which may be zero or negative) and pressure potential which is always positive. Hence, depending on the relative magnitudes of osmotic potential and pressure potential; the value of water potential can be negative or positive.
  • Question 10
    1 / -0
    A cell will swell up if
    Solution
    Correct option: B
    Explanation:
    • Endosmois is the process by which water from the surroundings gets into the cells as the water content outside the cell is higher.
    • As a result, the cell swells up.
    • Exosmois is the process in which water molecules move out from the cell as its content is higher inside the cell.
    • As a result, the cell shrinks.
    • And if the water content on either side remains the same there is no change in the shape of the cell.
    • The concentration of water molecules determines the movement of water.
    Hence, a cell will swell up if "the concentration of water molecules in surrounding medium is higher than water molecules concentration in the cell".
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