Transport in Plants Test

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Transport in Plants Test - 74

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Weekly Quiz Competition

Question 1
1 / -0

Which plant is used for demonstrating plasmolysis in the laboratory?

A
Tropaeolum

B
Impatiens balsam

C
Tradescantia

D
All of the above

Solution

Plasmolysis is the process in which cells lose water in a hypertonic solution.
Plasmolysis only occurs in extreme conditions and rarely happens in nature. It is induced in the laboratory by immersing cells in strong saline or sugar (sucrose) solutions to cause exosmosis, often using Tradescantia, which has pink colored cell sap so that the process is clearly visible.
So, the correct answer is 'Tradescantia'
Question 2
1 / -0

Which of the following seeds will show more imbibition pressure?

A
Sesame seeds

B
Gram seeds

C
Wheat seeds

D
Rice seeds

Solution

Gram seeds are rich in proteins. Proteins imbibe more water as compared to starch or fats. Hence, seeds rich in proteins like gram and chickpea will imbibe more water. Hence, if we soak dry seeds of gram or chickpea in water, they will show more increase in volume as compared to seeds storing starch like wheat and rice or fats like sesame seeds.
Question 3
1 / -0

0.1M solution of a solute has a water potential of

A
-2.3bars

B
0 bar

C
22.4 bars

D
+ 2.3 bars
Solution
- Assuming pressure potential to be zero i.e. the cell was flaccid initially, the water potential will be equal to the osmotic potential created by addition of solute to a final concentration of 0.1 M.
- The osmotic potential created due to 0.1 M solute will be = M R T. Where R is universal gas constant, whose value is 0.083145 bar per kelvin per litre and T is absolute temperature in Kelvin. Substituting the values in this formula we get -0.1*0.083145*298 = $$-2.3 bars$$.
So, the correct answer is option A.
Question 4
1 / -0

Sohan soaked 2 g raisins each of exactly equal mass in three beakers A, B and C each
containing same amount of tap water at the room temperature. After 30 minutes he
removed raisins from beaker A after 60 minutes from beaker B and after 90 minutes
from beaker C He calculated the percentage absorption of water in each case. If $$P_{A}, P_{B}$$
and $$P_{C}$$ denote percentage absorption, then on the basis of observation made by Sohan,
the correct representation of the conclusion should be :

A
$$P_{A}>P_{B}>P_{C}$$

B
$$P_{A}=P_{B}=P_{C}$$

C
$$P_{A} < P_{B} < P_{C}$$

D
$$P_{A} < P_{C} > P_{B}$$

Solution

C. Pa <Pb<Pc
Solution : As we know due to endosmosis the water moves into the cells of the raisins when placed in water. The raisins that are present in the water for the longest time will also absorb the highest and weigh the highest.
So the correct answer is "Pa <Pb<Pc".
Question 5
1 / -0

What is true about the water potential of vessels and tracheids, which are by and large filled with water? Their water potential

A
Is less than root hairs and more than cortex

B
Is more than root hair and less than cortex

C
Is less than root hair and cortex

D
Is more than root hair and cortex

Solution

Water potential of pure water is maximum and its value is zero. Hence, water potential of all solutions is negative. Water flows from a region of higher water potential to a region of lower water potential because a region having higher water potential has more number of water molecules as compared to the region having lesser water potential. Water potential in vascular tissues will be less than the water potential of cortex cells, then only water will flow from cortex to cells of vascular tissues.
Question 6
1 / -0

What happens if dry apricots are left for some time in the pure water and later transferred to sugar solution?

A
First it swells due to endosmosis and then exosmosis occurs and it shrinks.

B
First it shrinks due to endosmosis and then exosmosis occurs and it swells.

C
No change.

D
Apricot will be burst out.

Solution

Dry apricots have more solutes than pure water. Hence, endosmosis, i.e., water molecules will move from outside to inside of the apricot through wall of apricot takes place. Due to this, apricots will swell eventually.
When such apricots are then transferred to sugar solution, then the solution will be hypertonic bearing high amount of solute. Hence, exosmosis, i.e., water will move from inside to outside of apricot through apricot wall. Due to this, apricot will shrink.
Question 7
1 / -0

If cell A with $$OP=5$$ and $$TP=4$$ is surrounded by cells with OP and $$TP=1$$, what will be the action of water movement?

A
Water will not move up

B
From other cells to cell A

C
From cell A to other cells

D
None of the above
Question 8
1 / -0

In active non-osmotic absorption of water the OP of the cell sap of root hairs is .............. than / to OP of the soil water.

A
Higher

B
Lower

C
Both A and B

D
Equal

Solution

Active absorption means absorption against the concentration gradient, i.e., movement of water molecules from a region of lower concentration (higher OP) to a region of higher concentration of water molecules (lower OP). In this case, the cell sap of root hair cells will be lower and they will be having lesser OP as compared to the soil solution. However, lost of the water absorbed by plant roots is through passive absorption under the influence of transpiratory loss of water.
Question 9
1 / -0

The phenomenon of osmosis was first introduced by

A
Sachs

B
Pfeffer

C
Nollet

D
Strasburger

Solution

Jean-Antoine Nollet first introduced the phenomenon of osmosis. His experiment showed the movement of water without the input of any external energy. Osmosis is the movement of water through a semi-permeable membrane from a region of lower solute concentration into a region of higher solute concentration.
Thus, the correct answer is option C.
Question 10
1 / -0

If a cell has equal water concentration to its surrounding medium, .......... will be observed.

A
No effect

B
Endosmosis

C
Passage of water inward and outward

D
Cell will burst out

Solution

When a cell is kept in hypotonic solution that has a lower concentration of solutes than the cell does, the solution will move from outside to inside. This is known as endosmosis. Cell may burst due to excess water inside the cell during endosmosis. During diffusion, there is free inward and outward passage of water across the cell. When cell is kept in isotonic solution that has equal water concentration as that of cell, there is no net movement of water.
Thus, the correct answer is option A.

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Re-Attempt Weekly Quiz Competition

Transport in Plants Test - 74

Result

Transport in Plants Test - 74

Score

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Rank

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SHARING IS CARING

Question 1

Tropaeolum

Impatiens balsam

Tradescantia

All of the above

Solution

Question 2

Sesame seeds

Gram seeds

Wheat seeds

Rice seeds

Solution

Question 3

-2.3bars

0 bar

22.4 bars

+ 2.3 bars

Solution

Question 4

$$P_{A}>P_{B}>P_{C}$$

$$P_{A}=P_{B}=P_{C}$$

$$P_{A} < P_{B} < P_{C}$$

$$P_{A} < P_{C} > P_{B}$$

Solution

Question 5

Is less than root hairs and more than cortex

Is more than root hair and less than cortex

Is less than root hair and cortex

Is more than root hair and cortex

Solution

Question 6

First it swells due to endosmosis and then exosmosis occurs and it shrinks.

First it shrinks due to endosmosis and then exosmosis occurs and it swells.

No change.

Apricot will be burst out.

Solution

Question 7

Water will not move up

From other cells to cell A

From cell A to other cells

None of the above

Question 8

Higher

Lower

Both A and B

Equal

Solution

Question 9

Sachs

Pfeffer

Nollet

Strasburger

Solution

Question 10

No effect

Endosmosis

Passage of water inward and outward

Cell will burst out

Solution

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