Transport in Plants Test

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Transport in Plants Test - 77

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Weekly Quiz Competition

Question 1
1 / -0

In a flaccid cell, which condition does not occur?

A
TP = 1

B
SP = 0

C
SP=OP

D
None of the above

Solution

A cell is said to be flaccid when it is placed in a hypertonic solution and cell sap and moved out of it via the process of exosmosis. This causes an increase in the diffusion pressure deficit, such that the DPD becomes equal to the osmotic potential and the turgor pressure becomes zero. The turgor pressure is the pressure exerted by the tonoplast against the cell wall. It is maximum in the turgid cell and zero in the flaccid cell.
Hence, the correct answer is 'TP=1'
Question 2
1 / -0

In 0.1 M solution of a non electrolyte, $$\Psi w$$ value will be

A
Zero bar

B
+ 2.3 bar

C
- 24.7 bar

D
- 22.4 bar

Solution

Water potential is the potential due to water molecules in the solution. More the number of water molecules greater the water potential. By convention, water potential of pure water is fixed at zero which is its maximum value. Hence, water potential of all solutions is negative.
Water potential of a solution can be calculated using the equation PV = nRT. Substitute 0.1 for n; 298 for T; 0.832 for R and unity for volume.
On solving we get the value of P as 24.7 bars.
The important point to note is the term "non electrolyte" because non electrolytes do not ionize, the number of moles do not change.
Hence, we could directly substitute the value of molarity in place of n. Otherwise we would have to suitably modify the value of n depending on whether each molecule of electrolyte ionises to give two or three ions or more ions.
Question 3
1 / -0

The right sequence for imbibition is

A
Agar agar > cellulose > protein

B
Protein > cellulose > agar agar

C
Agar agar > protein > cellulose

D
Cellulose > agar agar > protein

Solution

Imbibition is the process of absorbing water by the solid particles without forming a solution. In this agar agar is the most powerful imbibant as it absorbs 99% more water than its weight and proteins absorb 15% then comes the cellulose the weakest imbibant. Thus, the correct answer is option C.
Question 4
1 / -0

If the OP of any osmotic system is 35 atm and its turgor pressure 9 units. Find out water potential present in the osmotic system.

A
- 44 unit

B
- 26 unit

C
26 unit

D
- 3.88 unit

Solution

Water potential of a solution is the algebraic sum of osmotic potential, pressure potential and matrix potential. The osmotic potential is equal to magnitude to osmotic pressure. It has a negative sign. The pressure potential has a positive sign and it is equal in magnitude to the turgor pressure.
In the question the value of water potential will be = (-35+9) = -26 units.
Question 5
1 / -0

If in a cell suction pressure value is 30 atm, while osmotic pressure 42 atm, then calculate the turgidity developed in form of TP in the cell.

A
45 atm

B
72 atm

C
12 atm

D
1.4 atm

Solution

Since Turgor Pressure (TP) = Osmotic pressure (OP) – Suction pressure (SP); Here, Osmotic pressure= 42 atm and Suction pressure=30 atm
Hence, Turgor Pressure= 42-30= 12 atm. Correct answer is C.
Question 6
1 / -0

The accurate equation for presenting water potential is

A
$$\Psi \omega \, = \Psi s\, +\,\Psi p\, +\, \Psi m$$

B
$$\Psi s = \Psi \omega \, +\,\Psi p\, +\, \Psi m$$

C
$$\Psi \omega = \Psi s \, -\,\Psi p\, -\, \Psi m$$

D
$$\Psi \omega = - \Psi s \, -\,\Psi p\, -\, \Psi m$$

Solution

Water potential is the chemical potential of water. It depends on the number of water molecules in the system. By convention water potential of pure water has been fixed at zero. Water potential of all solutions is thus negative and is given by algebraic sum of solute potential, pressure potential and matrix potential.
Question 7
1 / -0

In plant relations, $$\Psi$$ indicates

A
DPD

B
Solute potential

C
Water potential

D
Suction pressure
Solution
- Water potential is denoted by the Greek letter psi (Ψ) and is measured in bars. Thus, water potential is the chemical potential of water.
- By convention the water potential of pure water is given the value ZERO.
- Because pure water has the highest concentration of water molecules, and thus the highest water potential, the water potential of all other solutions must be lower than zero i.e., negative.
Therefore, the correct answer is option C.
Question 8
1 / -0

Osmotic pressure is highest in

A
Atriplex confertifolia

B
Salsola foetida

C
Rhizophora

D
Chenopodium
Question 9
1 / -0

The most powerful imbibant is

A
Agar agar

B
Proteins

C
Cellulose

D
Lignin

Solution

Imbibition is the process of absorbing water by the solid particles without forming a solution. Agar agar is the solidifying agent that are used to form solid culture media. It is also called as powerful imbibant as it absorbs 99% more water than its weight and proteins absorb 15% then comes the cellulose the weakest imbibant. Thus, the correct answer is option A.
Question 10
1 / -0

" Non - osmotic" theory for an active absorption of water was given by

A
Thimann and Kramer

B
Atkin and Priestley

C
J. C. Bose

D
O. Hertig

Solution

Non-osmotic active water absorption was proposed by Thimann. This theory was given by Thimann (1951) and Kramer (1959). According to the theory, sometimes water is absorbed against the concentration gradient. This requires an expenditure of metabolic energy released from respiration of root cells.

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Re-Attempt Weekly Quiz Competition

Transport in Plants Test - 77

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Transport in Plants Test - 77

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SHARING IS CARING

Question 1

TP = 1

SP = 0

SP=OP

None of the above

Solution

Question 2

Zero bar

+ 2.3 bar

- 24.7 bar

- 22.4 bar

Solution

Question 3

Agar agar > cellulose > protein

Protein > cellulose > agar agar

Agar agar > protein > cellulose

Cellulose > agar agar > protein

Solution

Question 4

- 44 unit

- 26 unit

26 unit

- 3.88 unit

Solution

Question 5

45 atm

72 atm

12 atm

1.4 atm

Solution

Question 6

$$\Psi \omega \, = \Psi s\, +\,\Psi p\, +\, \Psi m$$

$$\Psi s = \Psi \omega \, +\,\Psi p\, +\, \Psi m$$

$$\Psi \omega = \Psi s \, -\,\Psi p\, -\, \Psi m$$

$$\Psi \omega = - \Psi s \, -\,\Psi p\, -\, \Psi m$$

Solution

Question 7

DPD

Solute potential

Water potential

Suction pressure

Solution

Question 8

Atriplex confertifolia

Salsola foetida

Rhizophora

Chenopodium

Question 9

Agar agar

Proteins

Cellulose

Lignin

Solution

Question 10

Thimann and Kramer

Atkin and Priestley

J. C. Bose

O. Hertig

Solution

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