Transport in Plants Test

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Transport in Plants Test - 82

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is the life support of sieve tube in phloem?

A
Phloem fibres

B
Tracheids

C
Vessels

D
Companion cells

Solution

Sieve cells are tube like elongated cells in the phloem. These are the main conducting elements in the phloem tissue. The sieve tubes are the cells with no nuclei or the nuclei is fragmented. There are companion cells which are present adjacent to the sieve tube cells. These are the cells have a nucleus. The nucleus of the companion cells performs the functions for both the cells. Hence, the companion cells are called as life support cells for the sieve tubes.
Thus, the correct answer is option D.
Question 2
1 / -0

Phloem transports sugar in the form of

A
Glucose

B
Sucrose

C
Cellulose

D
Starch

Solution

Sugars are synthesized as glucose and fructose, translocated as sucrose and stored as starch for long-term storage in plants. Translocation of organic nutrients from the region of source or supply to the region of utilization is mostly in the form of sucrose. Sucrose is water soluble and more efficient in energy storage as compared to the glucose and fructose as well as glucose is more reactive and hence, phloem transports sugar in the form of sucrose.
Thus, the correct answer is option B.
Question 3
1 / -0

Read the given passage and answer the following question.

Wet mounts of three living samples of Elodea cells are prepared for viewing under the light microscope. Each slide is mounted with a different solution and viewed after 5 minutes.
Sample A - Elodea + 5 drops of 10% NaCl
Sample B - Elodea + 5 drops of Isotonic saline
Sample C - Elodea + 5 drops of distilled water

Choose the correct statement about the experiment.

A
The movement of salt is the dependent variable.

B
The elodea cells in sample C are in a hypotonic solution.

C
There is no passage of water in either direction in sample B.

D
NaCl is a toxin that would destroy any cell, no matter the concentration.

E
You cannot predict with any certainty what would happen to these cells as they are living organisms.

Solution

The movement of water is dependent on concentration difference. The presence of metabolites and salts makes the cell’s interior hypertonic as compared to distilled water. So, cells in sample C are placed in hypotonic solution. Cells in isotonic solution exhibit same passage of water in either direction and are in equilibrium. NaCl is a salt, not the toxin and osmosis is exhibited by living cells. Thus, the correct answer is option B.
Question 4
1 / -0

Which one of the following statements is wrong?

A
Water potential is the chemical potential of the water.

B
Solute potential is always negative.

C
Pressure potential is zero in a flaccid cell.

D
Water potential equals solute potential in a fully turgid cell.

E
Pressure potential is negative in a plasmolyzed cell.

Solution

Water potential is the chemical potential of water, whose value depends on the number of water molecules in the system. Water potential is calculated by the sum of solute potential and pressure potential. Solute potential is negative and pressure potential is positive. In a fully turgid cell, solute potential is equal to pressure potential and consequently water potential is zero. Thus, no water can enter inside a fully turgid cell.
Question 5
1 / -0

Plant transfers glucose in the form of sucrose in order to

A
Increase energy storage

B
Provide efficient energy transfer

C
Remove it in between reactions

D
All of the above

Solution

Starch and sucrose are more efficient forms in which the energy can be stored when compared to glucose. The starch is not soluble in water. Hence, the sucrose which is soluble in water is the form which is used for transport. This structural form increases the efficient energy transfer. Sucrose is not as reactive as glucose. This helps to prevent the chemical reactions which can convert the sucrose while transport.
Thus, the correct answer is option D.
Question 6
1 / -0

Predict the result of the following protocol.
Potato cores with an osmolarity of 0.5M are placed in a 1.0M solution of sucrose water overnight.

A
The potato cores will gain mass.

B
The potato cores will lose mass.

C
The potato cores will neither gain nor lose mass.

D
There isn't enough information to determine the outcome.

Solution

Potato cores with an osmolarity of 0.5 M are placed in a 1.0 M solution of sucrose water overnight. In this case, the osmolarity of potato core is less than the solution present outside, which means the solution is hypertonic as compared to potato cores. Thus water will move from a higher concentration of solvent i.e. potato core to lower concentration i.e. outside solution. Thus potato cores will lose mass. Therefore, option B is the correct answer.
Question 7
1 / -0

Jute is an example of

A
Xylem fibre

B
Xylem vessels

C
Phloem fibres

D
Sieve tubes

Solution

Jute is a natural vegetable fibre. It is also called as golden fibre. It is very easy and cheap to produce. It belongs to phloem (bast) fiber category. Bast fibers are those fibers which are collected from the bast or skin from the secondary phloem of the plant. These are the sclerenchymatous cells in the phloem. It is mainly composed cellulose and lignin.
Thus, the correct answer is 'Phloem fibres'.
Question 8
1 / -0

Read the given passage and answer the following question.

Wet mounts of three living samples of Elodea cells are prepared for viewing under the light microscope. Each slide is mounted with a different solution and viewed after 5 minutes.
Sample A - Elodea + 5 drops of 10% NaCl
Sample B - Elodea + 5 drops of Isotonic saline
Sample C - Elodea + 5 drops of distilled water

The cell structure that was not visible in sample A before it became exposed to 10% NaCl is

A
Nucleus

B
Plasma membrane

C
Mitochondria

D
Golgi body

E
Chloroplasts

Solution

Cells in sample A were placed in hypertonic solution and would loose water as water will move from cell to surrounding hypertonic medium by the process of osmosis causing plasmolysis of the cell. Plasmolysis causes shrinking of protoplasm away from the cell wall and makes the plasma membrane visible which is otherwise not visible. Thus, the correct answer is B.
Question 9
1 / -0

Identify the transfer cell of phloem.

A
Companion cells

B
Sieve tube

C
Phloem fibres

D
Phloem parenchyma

Solution

The parenchyma cells in the phloem tissue are known as phloem parenchyma. There are different types of phloem parenchyma cells, companion cells, albuminous and other parenchyma cells. The transfer cells are a type of companion cells. These are the cells which have folded cell wall surface. This helps to increase the transfer of the sugar in the lateral sides. They also help in scavenging the solutes which require ATP to move across the membranes.
Thus, the correct answer is option D.
Question 10
1 / -0

In which season, sugar in the leaves will be readily consumed?

A
Autumn

B
Spring

C
Winter

D
None of the above

Solution

Spring is considered as the flowering season. This is the period when there is growth of the floral buds which are formed at the apex of the vegetative shoots. Generally, there is a flow of sugar from the source (leaves) to sink end (roots). Due to the increase in the activity in the apex regions of the plant, there is consumption of food in the leaves. Hence, the food to the flower buds is supplied by the roots.
Thus, the correct answer is option B.

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Transport in Plants Test - 82

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Transport in Plants Test - 82

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SHARING IS CARING

Question 1

Phloem fibres

Tracheids

Vessels

Companion cells

Solution

Question 2

Glucose

Sucrose

Cellulose

Starch

Solution

Question 3

The movement of salt is the dependent variable.

The elodea cells in sample C are in a hypotonic solution.

There is no passage of water in either direction in sample B.

NaCl is a toxin that would destroy any cell, no matter the concentration.

You cannot predict with any certainty what would happen to these cells as they are living organisms.

Solution

Question 4

Water potential is the chemical potential of the water.

Solute potential is always negative.

Pressure potential is zero in a flaccid cell.

Water potential equals solute potential in a fully turgid cell.

Pressure potential is negative in a plasmolyzed cell.

Solution

Question 5

Increase energy storage

Provide efficient energy transfer

Remove it in between reactions

All of the above

Solution

Question 6

The potato cores will gain mass.

The potato cores will lose mass.

The potato cores will neither gain nor lose mass.

There isn't enough information to determine the outcome.

Solution

Question 7

Xylem fibre

Xylem vessels

Phloem fibres

Sieve tubes

Solution

Question 8

Nucleus

Plasma membrane

Mitochondria

Golgi body

Chloroplasts

Solution

Question 9

Companion cells

Sieve tube

Phloem fibres

Phloem parenchyma

Solution

Question 10

Autumn

Spring

Winter

None of the above

Solution

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