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Transport in Plants Test - 85

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Transport in Plants Test - 85
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  • Question 1
    1 / -0
    Mass flow hypothesis was put forward by
    Solution
    Mass flow hypothesis is also known as pressure flow hypothesis it is the best-supported theory to explain the movement of sap through the phloem. It was discovered by the scientist by Ernst Munch in 1930, He was the German plant physiologist. This creates the hydrostatic pressure in the phloem of the plant.
    So, the correct option is B.
  • Question 2
    1 / -0
    A negative effect of transpiration is
    Solution
    Transpiration is the process of loss of water through the aerial parts of the plant. It depends upon the amount of humidity level of the atmosphere.
    When there is a high level of moisture then there is no concentration gradient between leaf and the atmosphere there is a minimum loss of water through transpiration. It is a necessary evil as it develops water stress.
    So, the correct answer is 'Development of water stress'.
  • Question 3
    1 / -0
    What happens when the concentration of solutes decrease in the guard cells?
    Solution
    The guard cells contain chloroplasts, so they can manufacture food by photosynthesis. It synthesizes glucose during the day time by the process of photosynthesis and so its water potential decreases and it withdraws water from the epidermal cell and turns turgid and the stomata opens and transpiration takes place.
    At night, when there is no light the amount of solute decreases in guard cell which leads to increase its water potential. The guard cell loses water and turns flaccid and the stomata closes, so the transpiration stops.
    So, the correct answer is option B.
  • Question 4
    1 / -0
    Apoplast is the system of adjacent cell walls that is continuous throughout the plant except at the 
    Solution
    The apoplast is the free dimensional space outside the plasma membrane through which the material can diffuse freely. The water and minerals travel along the cell walls of the root hairs, cortical cells and endodermis. Most of the water flow in root occurs via apoplast as their cortical cells are loosely arranged and hence offer no resistance to water movement, but sometimes it is interrupted by Casparian strips in roots. Casparian strips are the thick waterproof band are of impermeable suberin which is present in the endodermis of the cells. 
    So, the correct answer is option C.
  • Question 5
    1 / -0
    During its life, a potato plant transpires water
    Solution
    Transpiration is a process of losing large amounts of water by plant. The water transpired by plant is not used by plants for its activities and processes. Loss of water occurs through stomata. On an average, potato plant transpires 90 liters of water in its life.
    Thus, the correct answer is option B.
  • Question 6
    1 / -0
    Value of osmotic potential $$ ( \pi ) $$ and pressure potential (p) of cells a, b, c, d are given: 
    Cell$$ \pi $$p
    a1.00.5
    b0.60.3 
    c1.20.6
    d0.80.4
    Identify the correct sequence for movement of water.
    Solution
    Osmotic pressure is the movement of a solute particle from low concentration to high concentration through a semi-permeable membrane.
    So, the water will move from a higher concentration to a lower concentration.
    So, the correct option is 'b,d,a,c'.
  • Question 7
    1 / -0
    The phenomenon of osmosis is involved in the diffusion of water from
    Solution
    Osmosis is the process of flow of fluid from higher to lower concentration through the semi-permeable membrane. The wall of xylem vessels behaves as the semi-permeable membrane so diffusion of water from one xylem vessel to another xylem vessel can be called the phenomenon of osmosis.
    In all other three cases, there is no presence of semi-permeable membrane so, it is the simple diffusion process.
    So, the correct answer is the 'xylem vessel to xylem vessel'.
  • Question 8
    1 / -0
    Solution A has $$ \Psi_s = -30 $$ bars and $$ \Psi_p = 5 $$ bars. Solution B has $$ \Psi_s = -10 $$ bars and $$ \Psi_p = 0 $$ atm. The two are separated by semipermeable membrane. Flow of water will be 
    Solution
    This question depicts Water Potential. Water potential is denoted by the Greek letter ψ (psi). It is the measure of the relative tendency of water to move from one area to another and are measured in the terms of bars. It is the difference between the free energy of water molecules in pure water and solution. Water potential can be measured using the formula, ψ = ψs + ψp where ψs = Solute Potential or Osmotic Potential and ψp = Pressure Potential or Turgor Potential. Here, the water movement across the concentration gradient will be higher water potential to lower water potential.
    In the above question it is given as follows,
    Solution A : ψs = -30 bars, 
                        ψp  = 5 bars and 
                        ψ = ψs + ψp = -30 + 5 = -25 bars. 
    Solution B  : ψs = -10 bars,
                         ψp = 0 bars and 
                          ψ = ψs + ψp = -10 + 0 = -10 bars.

    Therefore, Solution A Water Potential (ψ) = -25 bars,
                       Solution B Water Potential (ψ) = -10 bars,
    In the case of water Potential (ψ), water movement will be higher water potential to lower water potential. i.e, from the Solution B to Solution A.
    So, the correct answer is option A.
  • Question 9
    1 / -0
    Water potential in closely placed cell (p, q, r) is given below. Find out correct direction of water movement : 
    CellOsmotic Potential
    (MPa)
    Pressure potential
    p-0.210.05
    q-0.220.02
    r-0.230..05
    (a) p $$\longrightarrow $$ q
    (b) q $$\longrightarrow $$ r
    (c) r $$\longrightarrow $$ p
    (d) r $$\longrightarrow $$ q
    Solution
    • Water potential is the measure of the relative tendency of water to move inside or outside the cell.
    • Movement of water will be from high to low concentration.
    • This term was first coined by Slatyer and Taylor in the year 1818.
    So, the correct answer is 'a,d'.
  • Question 10
    1 / -0
    Cell a and cell b are adjacent plant cells. In cell a $$ \Psi_s = -20 $$ bars and $$ \Psi_p = 8 $$ barsIn cell b $$ \Psi_s = -12 $$ bars and $$ \Psi_p = 2 $$ bars. Then:
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