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Biological Classification Test - 13

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Biological Classification Test - 13
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  • Question 1
    1 / -0

    Gram-negative cells stain pink because:

    Solution

    Their peptidoglycan layer is thin and does not retain crystal violet stain like Gram- positive bacteria do.

  • Question 2
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    Which of the following regarding protists, in general, is false?

    Solution

    Protists do not have a unifying characteristic other than being eukaryotic; they do not fit into the kingdoms of Plantae, Animalia and Fungi.

  • Question 3
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    The bacterium Bacillus thuringiensis can withstand heating, dryness, and toxic chemicals that would kill most other bacteria. This indicates that it is probably able to form:

    Solution

    Endospores are able to survive a wide range of conditions.

  • Question 4
    1 / -0

    Which of the following facts differentiates the plant virus from other viruses?

    Solution

    All viruses are characteristically obligate parasites and nucleo-protein in nature. But the nature of genetic material may vary among viruses. In plant viruses, the genetic material is characteristically RNA, except cauliflower mosaic virus, where it is DNA.

  • Question 5
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    Pseudomycelium is a characteristic feature of:

    Solution

    Pseudomycelium is characteristic feature of yeast.

  • Question 6
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    How many kingdoms contain eukaryotes in five kingdom system of classification of R.H Whittaker?

    Solution

    The kingdoms were named Monera, Protista, fungi, plantae and Animalia. Four kingdoms contain eukaryotes except kingdom Monera, which contains prokaryotes.

  • Question 7
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    The symbiotic association of fungi and algae is called:   

    Solution

    The symbiotic association of fungi and algae is called lichen.

  • Question 8
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    Common bread mold is:

    Solution

    Rhizopus (pin mould or black mould) grows on bread and hence also called bread mould.

  • Question 9
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    Plasmogamy is fusion of:

    Solution

    It is the first stage of sexual reproduction in which the cytoplasm of two sex cells fuse with each other. The nuclei of sex cells come close to each other but do not fuse. Thus, the resulting cell becomes binucleate or dikaryon.

  • Question 10
    1 / -0

    Koch's postulates are related to:

    Solution

    Robert Koch (1882) working on bacterial diseases, postulated certain fundamental laws of diseases known as Koch's postulates.

  • Question 11
    1 / -0

    Ergot is caused by:

    Solution

    Claviceps purpurea is a fungus which causes ergotism in rye (Secale cereale) and other plants. It also yields a hallucinogenic drug called LSD.

  • Question 12
    1 / -0

    Which of the following statements is not correct for viruses?

    Solution

    Virus is a small infectious agent that replicates only inside the living cells of other organisms. Viruses can infect all types of life forms, from animals and plants to microorganisms, including bacteria and archaea. Viruses can pass through bacterial proof filters as they are smaller than bacteria.

  • Question 13
    1 / -0

    The conditions which would be favoured by thermoacidophiles are:

    Solution

    Archaebacteria is a primitive group of bacteria. The three main groups of archaebacteria are methanogens, halophiles and thermoacidophiles. Methanogens are found in the musk of swamps and marshes, the rumen of cattle sewage, sludges and gut of termites. Halophiles are named so because they usually occur in salt rich substrata like salt pans, salt beds and salt marshes.

    Thermoacidophiles have dual ability to tolerate high temperature as well as high acidity. They often live in hot sulphur springs where the temperature may be as high as 80°C and pH as low as 2.

  • Question 14
    1 / -0

    If the generation time of a bacterium is 40 minutes and a culture containing \(10^7\)cells/ml is grown for 4 hours, then calculate its population after that period.

    Solution

    Generation time is 40 minutes.

    ∴ Number of divisions is \({\frac{240}{40}}\)

    Number of bacteria are

    \(2^n = 2^6\times10^7\)

    \(64\times10^7\)

  • Question 15
    1 / -0

    Oxygenic photosynthesis occurs in

    Solution

    Oscillatoria is a photosynthetic cyanobacterium. In this cyanobacterium during photosynthesis water is electron donor and oxygen is a by-product. i.e. oxygenic photosynthesis occurs.

    Rhodospirillum and Chlorabium are non-oxygenic photosynthetic, purple non-sulphur and green-sulphur bacterium.

    Chromatium is purple sulphur bacterium, also a non-oxygenic photosynthetic.

  • Question 16
    1 / -0

    The site of respiration in bacteria is

    Solution

    Mesosomes are areas in the cell membrane of prokaryotic (bacterial) cells that fold inward. They play a role in cellular respiration, the process that breaks down food to release energy. Instead, they use the mesosomes as a site for the electron transport chain.

  • Question 17
    1 / -0

    Amoebiasis is prevented by

    Solution

    Amoebiasis or amoebic dysentery is caused by protozoan parasite Entamoeba histolytica that resides in the upper part of large intestine. It spreads through contaminated water and food contaminant form (trophozoite) or cyst of Entamoeba.

    Trophozoite damages intestinal wall by engine histolysis, reaches blood capillaries and feed on RBCs, bacteria, tissue debts, resulting in abdominal. pain, acidic motions with mucus and blood. The disease can be prevented by drinking boiled and clean water and intake of fresh and hygienic food.

  • Question 18
    1 / -0

    The main difference in Gram (+) ve and Gram (-) ve bacteria residues in their

    Solution

    All bacteria possess cell wall. However, the bacteria are classified as Gram positive bacteria and Gram-negative bacteria on the basis of their cell wall. Cell wall of Gram-positive bacteria consist of multiple layer of peptidoglycan. Cell wall of Gram-negative bacteria is made up thin layer of peptidoglycan. In addition, they have one more outer layer of lipopolysaccharide (LPS).

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