Morphology of Flowering Plants Test 62

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Morphology of Flowering Plants Test 62

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Weekly Quiz Competition

Question 1
1 / -0

A seed in which micropyle and hilum cannot be traced is

A
Pea

B
Gram

C
Castor

D
Maize

Solution

A seed in which micropyle and hilum cannot be traced is maize. In maize, the pericarp of the fruit is fused with the seed coat referred to as caryopsis, typical of the grasses, and the entire kernel is often referred to as the seed. The cob is close to a multiple fruit in structure, except that the individual fruits, the kernels never fuse into a single mass.
Question 2
1 / -0

From which one of the following a drug is obtained from roots to cure mental disorders?

A
Nepenthes

B
Marigold

C
Rauwolfia

D
Riccinus

Solution

The roots of the plant Rauwolfia serpentina or sarpagandha is used to treat hypertension and mental disorders. The roots of the plant are dried to extract the alkaloid resperine from the plant, which is used for medicinal purposes.
Reserpine, was used to treat high blood pressure and mental disorders, including schizophrenia.
Question 3
1 / -0

Three floral diagrams are given here. Their respective families are assigned in the answer key. Find out the families to which these diagrams belong to

A
a - Liliaceae, b - Asteraceae, c - Solanaceae

B
a - Asteraceae, b - Solanaceae, c - Brassicaceae

C
a - Asteraceae, b - Fabiaceae, c - Poaceae

D
a - Solanaceae. b - Poaceac, c - Fabaceae

Solution

Diagram a is showing,
small 5 sepals, 5 petals in valvate aestavation, 5 stamens in epipetalous condition (stamens are fused with petals) and ovary with basal placentation. These characteristics match with flower of family Asteraceae.
Diagram b is showing,
large 5 united sepals in valvate aestivation, 5 united petals in valvate aestivation, 5 stamens in epipetalous condition (stamens are fused with petals), bicarpellary ovary with many ovules. These characteristics match with flower of family Solanaceae.
Diagram c is showing,
4 sepals in two whorls with imbricate aestivation, 4 petals in valvate aestivation, 6 stamens in two whorls in tetradynamous condition (4 stamens longer than other two), bicarpellary ovary with false septation showing two locules. These characteristics match with flower of family Brassicaceae.
Therefore, the correct option is B.
Question 4
1 / -0

One of the following is the typical floral formula of Brassicaceae (Cruciferae).

A
$$K_{2+2}C_4A_{2+4}\underline{G}_{(2)}$$

B
$$K_4C_{2+2}A_{3+3}\overline{G}_{(2)}$$

C
$$K_{2+2}C_{2+2}A_6\underline{G}_{(1)}$$

D
$$K_4C_4A_6\underline{G}_{(2)}$$

Solution

Brassicaceae family has flower with 4 sepals in two whorls with imbricate aestivation, 4 petals in valvate aestivation, 6 stamens in two whorls in tetradynamous condition (4 stamens longer than other two), bicarpellary ovary with false septation showing two locules.
Thus, the correct answer is option A.
Question 5
1 / -0

Desmodium, 'Indian telegraph plant' belongs to the family

A
Liliaceae

B
Papilionaceae

C
Malvaceae

D
Solanceae

Solution

Some plants show spontaneous to and fro movements of their leaflets. Such movements are observed in many plants. They are generally driven by temperature, touch, light, humidity, chemicals, etc. Desmodium, which is also called as Indian telegraph plant consists of two lateral leaflets and terminal leaflets.
Leaflets of Desmodium oscillates autonomously depending upon the temperature. Such oscillations are believed to be due to rhythmic swelling and shrinking of motor cells located in the pulvinus leaflet base. This movement of leaflets is similar to telegraphic signals.
Hence, it is also called as Indian telegraph plant. Desmodium, Indian telegraph plant belongs to family Papilionaceae as it possesses legumes, brightly colored papilionaceous flowers.
So, the correct answer is option B.
Question 6
1 / -0

Immature gular fruit is

A
Berry

B
Samara fruit

C
Hypanthodium inflorescence

D
Swollen twig tip

Solution

Immature gular fruit is a hypanthodium inflorescence. Hypanthodium inflorescence is formed by an enlarged, fleshy, hollow receptacle with multiple ovaries on the inside surface. In essence, it is really a fleshy stem with a number of flowers, so, it is considered both a multiple and accessory fruit. Here, the receptacle is fleshy and forms hollow ball like structure with an apical opening. Three types of flowers develop on the inner surface of the receptacle.The female flowers are towards the base, male flowers are towards the orifice and short styled sterile female flowers are in between.
Question 7
1 / -0

The seeds of orchids and Alisma are exceptional monocots because they

A
Lack pericarp

B
Are exalbuminous

C
Lack cotyledons

D
None of the above

Solution

Seeds of flowering plants are either dicotyledonous or monocotyledonous. While, the dicotyledons are characterized by two kidney shaped cotyledons, these are either non-endospermic exalbumnous or endospermic depending on the presence of endosperm and food storage areas. The monocotyledons with a single cotyledons are also differentiated as endospermic and non-endospermic based on the presence of endosperms. In case of Alisma and orchids, the seeds are extremely small with an undifferentiated embryo that lacks endosperm. They are referred to as acotyledons or exceptional monocots.
Thus, the correct answer is option C.
Question 8
1 / -0

Monocot seeds are mostly endospermic, which of the following is a monocot non -endospermic seed?

A
Oryza

B
Castor

C
Alisma

D
Avena

Solution

Monocot seeds are mostly endospermic, but Alisma is a monocot non -endospermic seed. In most monocotyledons the seeds are endospermic. The embryo is embedded in the endosperm which the seedling will use upon germination. In few they are non-endospermic seeds like that of dicotylednous plants where the endosperm is absorbed by the embryo as the latter grows within the developing seed and the cotyledons of the embryo become filled with stored food.
Therefore, the correct answer is option C.
Question 9
1 / -0

Which of the following are not characteristic features of the family Fabaceae?

A
Tap root system, compound leaves and raceme inflorescence

B
Flowers actinomorphic, twisted aestivation and gamopetalous

C
Stamens ten, introse, basifixed and dithecous

D
Monocarpellary, ovary, superior and bent stigma

E
Fruit is legume

Solution

Characteristic features of the family Fabaceae are -
1. Leaves are usually alternate and compound.
2. The flowers are zygomorphic and in general, have five fused sepals.
3. The petals are also five free.
4. The presence of having a short usually cup-shaped hypanthium.
5. Stamens ten in number, superior ovary and curved style.
6. Placentation marginal.
Flowers of Fabaceae do not show actinomorphic nature, twisted aestivation and gamopetaly. Thus, the correct answer is option B.
Question 10
1 / -0

These are three examples of family Fabaceae. Answer the following.
What is the criterion of their classification?

A
Nature of aestivation and androecium

B
Nature of seed

C
Nature of stem

D
Nature of leaf

Solution

Family Fabaceae is subdivided into 3 sub-families as Papilionoideae, Caesalpinoideae and Mimosoideae. These 3 sub-families are easily identifiable by their flowers.
Papilionoideae flower shows zygomorphic flower (of which symmetry remains intact when it is cut into two equal halves only through one particular vertical plane passing though the center) with 5 petals with 2 banner petal, 2 wing petals and 2 petals which partially fuse together to form boat shaped keel. It possess 10 distinct or fused or diadelphous stamens (stamens with united filaments).
Caesalpinoideae flower shows slightly zygomorphic flower with 5 petals which are not differentiated into banner, wing and keel. 10 or less stamens which are visible externally.
Mimosoideae flower are actinomorphic (A flower when cut through any vertical plane passing though the axis then two equal halves are formed and its symmetry remains undisturbed. Such flower is called as an actinomorphic flower). Flowers are small and are crowded together to form pom-pom like structure. Stamens are 10 to many and extend beyond corolla.
Therefore, the correct option is A.

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Re-Attempt Weekly Quiz Competition

Morphology of Flowering Plants Test 62

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Morphology of Flowering Plants Test 62

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SHARING IS CARING

Question 1

Pea

Gram

Castor

Maize

Solution

Question 2

Nepenthes

Marigold

Rauwolfia

Riccinus

Solution

Question 3

a - Liliaceae, b - Asteraceae, c - Solanaceae

a - Asteraceae, b - Solanaceae, c - Brassicaceae

a - Asteraceae, b - Fabiaceae, c - Poaceae

a - Solanaceae. b - Poaceac, c - Fabaceae

Solution

Question 4

$$K_{2+2}C_4A_{2+4}\underline{G}_{(2)}$$

$$K_4C_{2+2}A_{3+3}\overline{G}_{(2)}$$

$$K_{2+2}C_{2+2}A_6\underline{G}_{(1)}$$

$$K_4C_4A_6\underline{G}_{(2)}$$

Solution

Question 5

Liliaceae

Papilionaceae

Malvaceae

Solanceae

Solution

Question 6

Berry

Samara fruit

Hypanthodium inflorescence

Swollen twig tip

Solution

Question 7

Lack pericarp

Are exalbuminous

Lack cotyledons

None of the above

Solution

Question 8

Oryza

Castor

Alisma

Avena

Solution

Question 9

Tap root system, compound leaves and raceme inflorescence

Flowers actinomorphic, twisted aestivation and gamopetalous

Stamens ten, introse, basifixed and dithecous

Monocarpellary, ovary, superior and bent stigma

Fruit is legume

Solution

Question 10

Nature of aestivation and androecium

Nature of seed

Nature of stem

Nature of leaf

Solution

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