Self Studies

Biomolecules Test - 10

Result Self Studies

Biomolecules Test - 10
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Which one of the following is the sweetest sugar?

    Solution

    Fructose is the sweetest of the naturally-occurring sugars.

    Fructose is a ‘monosaccharide’, meaning it is one of the simplest forms of sugar, i.e. it can’t be broken down into more basic sugar units. Other common monosaccharides are glucose and galactose.

  • Question 2
    1 / -0

    Starch and cellulose are the compounds made up of many units of

    Solution

    Starch and cellulose both belongs to polysaccharides i. e. they are compounds of simple sugar. Starch consists of two components amylose and amylopectin.

    Both amylose and amylopectin are formed by the condensation of α - D - glucose.

    A chain of cellulose molecule contains 6000 or more glucose residues. The successive glucose residues are joined together by 1 - 4 β-linkages

  • Question 3
    1 / -0

    Insulin found in plant cell is a

    Solution

    Insulin found in plant cell is a polysaccharide. Insulin is a natural polysaccharide produced by many plants. Insulin structurally belongs to class dietary fibers these are also called as fructans. Insulin is the major energy source and is found in roots or rhizomes of plants.

  • Question 4
    1 / -0

    Which is non-reducing sugar?

    Solution

    Reducing sugars are sugars where the anomeric carbon has an OH group attached that can reduce other compounds. All monosaccharide such as glucose are reducing sugars.

    A disaccharide can be a reducing sugar or a non-reducing sugar. Maltose and lactose are reducing sugars, while sucrose is a non-reducing sugar.

  • Question 5
    1 / -0

    Glycoproteins contain

    Solution

    Carbohydrates can be attached to proteins to form glycoprotein. In glycoprotein’s, the carbohydrate chains are either attached to the nitrogen atom in the side chain of asparagines (N-linkage) or to the oxygen in the side chain or serine or threonine (O-linkage.)

  • Question 6
    1 / -0

    Proteins consist of

    Solution

    Protein consists of carbon, hydrogen, oxygen, and nitrogen. The addition of nitrogen gives protein its unique distinction from carbohydrate and fat, along with establishing the signature name, amino acid.

  • Question 7
    1 / -0

    Maltose consists of which one of the following

    Solution

    Maltose consists of two molecules of glucose that are linked by α-(1, 4’) glycosidic bond. Maltose results from the enzymatic hydrolysis of amylose, a homopolysaccharide (by the enzyme amylase.

    Maltose is converted to two molecules of glucose by the enzyme maltase, which hydrolyzes the glycosidic bond.

  • Question 8
    1 / -0

    Which of the following amino acids is not optically active?

    Solution

    The simplest amino acid Glycine (gly or G), has H as an R group, meaning that it has only 3 different groups (carboxylate, amine, but 2 hydrogen) there are no 4 different groups attached to the alpha carbon and therefore Glycine is not chiral and cannot be optically active (possess optical chirality)

    \(H_2N - \underset{\overset{|}{H}}{\stackrel{\overset{H}{|}}{C}} - COOH\)

             glycine

  • Question 9
    1 / -0

    The ground substance of connective tissue is basically composed of:

    Solution

    The intercellular substance (extracellular matrix) in connective tissues is usually abundant. That is why, the cells are widely spaced. It consists of fibres and a large amount of an amorphous ground substance.

    This ground substance is mainly composed of acidic mucopolysaccharides bound with proteins to form hyaluronic acid.

  • Question 10
    1 / -0

    The base pairs of DNA are correctly shown as:

    Solution

    The base pairs of DNA are A = T and C = G.

  • Question 11
    1 / -0

    Which of the following is incorrectly matched?

    Solution

    Ribozymes (ribonucleic acid enzymes) are also called catalytic RNA. They are RNA molecules capable of catalysing specific biochemical reactions, similar to the act of protein enzymes.

    Ribozymes, discovered in 1982, demonstrated that RNA can be both genetic material (like DNA) and a biological catalyst (like protein enzymes). Examples of ribozymes include the hammerhead ribozyme, the VS ribozyme, Leadzyme and the hairpin ribozyme.

  • Question 12
    1 / -0

    Raffinose is a:

    Solution

    Raffinose is a Trisaccharide. It is made up of three molecules of glucose, i.e., glucose, fructose and galactose.

  • Question 13
    1 / -0

    Denaturation of DNA

    Solution

    Ligase enzyme is used for joining bits of DNA.

  • Question 14
    1 / -0

    The set of three elements included in micronutrients is:

    Solution

    The set of three elements included in micronutrients is Fe, Zn, and Cu.

  • Question 15
    1 / -0

    Which one of the following vegetable oils has a very low content of PUFA (polyunsaturated fatty acid)?

    Solution

    Fat is made up of smaller molecules called fatty acids, and there are several types of saturated fatty acids in coconut oil. The predominant type is lauric acid (47%), with myristic and palmitic acids present in smaller amounts, which have been shown in research to raise harmful LDL levels. Coconut oil has a very low content of PUFA

  • Question 16
    1 / -0

    Which of the following is not a wax?

    Solution

    Waxes are esters formed between a long chain alcohol and saturated fatty acids. Tripalmitin is a triglyceride.

  • Question 17
    1 / -0

    Which of the following mineral is essential for the normal excitability of cardiac muscles?

    Solution

    Proper balance of calcium, potassium, and magnesium ions is essential for the normal excitability of muscles, especially cardiac muscles.

  • Question 18
    1 / -0

    In an experiment it was found that adenine constitutes 31% and guanine 19%. The quantity of cytosine in this DNA is likely to be:

    Solution

    According to Chargaff's rule,

    A + G = T + C

    (No. of purine = no. of pyrimidines) in dsDNA

    We know A = T as they are complementary to each other

    Similar,  C = G from this we can find out, if A = 31, then A + T = 62

    100 – 62 = 38

    38 = C + G

    C = G = 19

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now