Biomolecules Test

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Biomolecules Test - 67

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Weekly Quiz Competition

Question 1
1 / -0

Enzyme facilitates a reaction through

A
Reduction in activation energy

B
Increase in activation energy

C
Altering pH

D
Altering temperature

Solution

Enzymes are proteins which accelerate the rate of the reaction. The substrate and product have different energy state. The energy gap between the substrate and the product is known as activation energy which is the minimum energy required to initiate a reaction. The enzymes lower the activation energy and lead to the faster conversion of substrate to the product.
So, the correct answer is option A.
Question 2
1 / -0

Enzymes enhance rate of reaction by

A
Combining with product

B
Forming reactant-product complex

C
Changing equilibrium of reaction

D
Lowering activation energy

Solution

Enzymes are proteins which accelerate the rate of the reaction. The substrate and product have different energy state. The energy gap between the substrate and the product is known as activation energy which is the minimum energy required to initiate a reaction. The enzymes lower the activation energy and lead to the faster conversion of substrate to the product.
So, the correct answer is option D.
Question 3
1 / -0

ATP was discovered by

A
Lipmann

B
Lohmann

C
Blackman

D
Bowman

Solution

ATP is known as energy currency of the cell and it is a nucleotide formed by the combination of adenine as a nitrogenous base, ribose sugar, and triphosphate. It is found in free cells which breaks to form energy by breaking its high energy phosphate bonds. Karl Lohmann was first to discover ATP. It is produced by the mitochondria in the cell.
So, the correct answer is option B.
Question 4
1 / -0

One molecule of an enzyme is able to catalyse conversion of two molecules of substrate into products in $$5$$ minutes. Ten molecules of enzyme and $$25$$ molecules of substrate are mixed in a test tube. At the end of $$10$$ minutes the test tube will have

A
Products only

B
Products and enzymes molecules

C
Products and $$5$$ unreacted substrate molecules

D
Products, enzyme molecules and $$5$$ molecules of substrate

Solution

When enzyme reacts and binds with substrate they give products so, in the end of 10 minutes, there will be products and enzymes in the test tube because enzymes are not consumers in any reaction and they only bind to substrate and give products.
So the correct answer is B.
Question 5
1 / -0

The given graph shows the effect of substrate concentration on rate of reaction of enzyme Green Gram phosphatase. What does the graph indicate?

A
Formation of enzyme substrate complex.

B
Increase of pH at higher concentration of substrate.

C
Presence of enzyme inhibitor.

D
Rate of reaction is directly proportional to substrate concentration.

Solution

In the given graph, initially the rate of enzymatic reaction increases but after some time it begins to slow down which indicates the presence of an enzyme inhibitor.

So, the correct answer is 'Presence of enzyme inhibitor.'.
Question 6
1 / -0

Bond present between two residues of carbohydrate is

A
Amide

B
Phosphodiester

C
Glycosidic

D
Hydrogen bond

Solution

The amino acids are linked together by peptide bonds to form a protein. Peptide or amide bond is formed by the linkage of the carboxyl group of one amino acids with the amino group of the other amino acids
The bond formed between two monosaccharides is called a glycosidic bond. It is normally formed between the carbon-1 of one monosaccharide and carbon-4 of the other monosaccharide.
DNA and RNA are chain of polynucleotide which are joined by the phosphodiester bonds. DNA resembles RNA as both has polynucleotide chain. The two nucleotide is linked by phosphodiester bond.
So, the correct answer is option C.
Question 7
1 / -0

Figure given below shows three velocity - substrate concentration curves for an enzyme reaction. What do the curves depict?

A
$$a$$-normal enzyme action, $$b$$-competitive inhibition, $$c$$-noncompetitive inhibition

B
$$a$$-enzyme with an allosteric modulator added, $$b$$-normal enzyme activity, $$c$$-competitive inhibition

C
$$a$$-enzyme with an allosteric stimulator, $$b$$-competitive inhibitor added, $$c$$-normal enzyme reaction

D
$$a$$-normal enzyme reaction, $$b$$-no competitive inhibitor added $$c$$-allosteric inhibitor added

Solution

Graph a shows that enzyme acts normal in the reaction because it reaches the normal value of Vmax.
Graph b shows that a competitive inhibitor is involved in the reaction because it reaches the normal value of Vmax, but with the higher concentration of substrate to get it there. So the km value is higher.
Graph c shows that a non-competitive inhibitor, the reaction never reach its normal Vmax, as shown in the figure where Vmax is reduced so the concentration of enzyme is reduced.
So the correct answer is A.
Question 8
1 / -0

Which is protein in nature?

A
Polyethylene

B
Cellulose

C
Terylene

D
Silk and wool

Solution

Wool fibres are obtained from proteins. It contains lipids and proteins. It is made up of keratin protein.
Silk fibers are composed of fibroin. It is an insoluble protein.
So, the correct answer is option D.
Question 9
1 / -0

In a protein/polypeptide amino acids are linked by

A
Peptide bonds

B
Glycosidic bonds

C
Hydrogen bonds

D
All the above

Solution

Proteins are building blocks of the body. The proteins are made up of amino acids. The amino acids are linked together by peptide bonds to form a protein. The peptide bond is formed by the linkage of the carboxyl group of one amino acids with the amino group of the amino acids. The primary structure of proteins is formed by the linkage of amino acids by the peptide bond. It is formed by the condensation reaction.
So, the correct answer is option A.
Question 10
1 / -0

Organic compound found in most cells is

A
Water

B
Glucose

C
Oxygen

D
Sodium chloride

Solution

A monosaccharide is the simplest form of carbohydrate which is composed of carbon, hydrogen, and oxygen.
Glucose is a monomer which is formed by six carbon atom. The molecular formula is C$$_6$$H$$_{12}$$O$$_6$$. It is a monosaccharide which acts as an instant source of energy. It is the simplest form of sugar found in the cells. Glucose present in the blood is transported to the cell. Inside the cell, glucose is broken down by the aerobic respiration. Glycolysis converts glucose into pyruvate which is further metabolized by TCA cycle and electron transport chain to produce energy in form of ATP.
So, the correct answer is option B.

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Biomolecules Test - 67

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Biomolecules Test - 67

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SHARING IS CARING

Question 1

Reduction in activation energy

Increase in activation energy

Altering pH

Altering temperature

Solution

Question 2

Combining with product

Forming reactant-product complex

Changing equilibrium of reaction

Lowering activation energy

Solution

Question 3

Lipmann

Lohmann

Blackman

Bowman

Solution

Question 4

Products only

Products and enzymes molecules

Products and $$5$$ unreacted substrate molecules

Products, enzyme molecules and $$5$$ molecules of substrate

Solution

Question 5

Formation of enzyme substrate complex.

Increase of pH at higher concentration of substrate.

Presence of enzyme inhibitor.

Rate of reaction is directly proportional to substrate concentration.

Solution

Question 6

Amide

Phosphodiester

Glycosidic

Hydrogen bond

Solution

Question 7

$$a$$-normal enzyme action, $$b$$-competitive inhibition, $$c$$-noncompetitive inhibition

$$a$$-enzyme with an allosteric modulator added, $$b$$-normal enzyme activity, $$c$$-competitive inhibition

$$a$$-enzyme with an allosteric stimulator, $$b$$-competitive inhibitor added, $$c$$-normal enzyme reaction

$$a$$-normal enzyme reaction, $$b$$-no competitive inhibitor added $$c$$-allosteric inhibitor added

Solution

Question 8

Polyethylene

Cellulose

Terylene

Silk and wool

Solution

Question 9

Peptide bonds

Glycosidic bonds

Hydrogen bonds

All the above

Solution

Question 10

Water

Glucose

Oxygen

Sodium chloride

Solution

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