The s-Block Elements Test 14

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The s-Block Elements Test 14

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Weekly Quiz Competition

Question 1
1 / -0

The element of alkaline earth metal which shows a diagonal relationship with aluminium is:

A
$$Mg$$

B
$$Ba$$

C
$$Be$$

D
$$Ca$$
Solution
Option $$(C)$$ is correct.
$$Be$$ shows a diagonal relationship with aluminium.This is due to the similar value of charge/radius ratio and electronegativity. Some of the resemblances are as follows:

Unlike groups – 2 elements but like aluminium, beryllium forms covalent compounds.
The hydroxides of beryllium and aluminium are amphoteric in nature, whereas those of other elements of a group-2 are basic in nature.
The oxides of both $$Be$$ and $$Al \:i.e. \:BeO$$ and $$Al_2O_3$$ are high melting insoluble solids.
$$BeCl_2 $$ and $$AlCl_3$$ have bridged chloride polymeric structure.
Question 2
1 / -0

Which of the following metals dissolves in $$KOH$$ with the evolution of hydrogen?

A
$$Ca$$

B
$$Mg$$

C
$$Sr$$

D
$$Be$$

Solution

Option $$(D)$$ is correct.
Beryllium metal dissolves readily in a dilute aqueous base solution like $$KOH$$, to form $$Be(II)$$ complexes together with hydrogen gas.
Question 3
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Halides of which alkaline earth metal is known to have chains of $$-X_2MX_2M-$$ is:

A
$$Mg$$

B
$$Ba$$

C
$$Be$$

D
$$Ca$$

Solution

Option $$(C)$$ is correct.
Halides of which alkaline earth metal is known to have chains of $$-X_2MX_2M-$$ is $$Be$$. All halides of $$Be$$ are covalent and electron deficient. Because of this, they are unstable. So, in order to attain stability, they polymerise to make long chains. They do this by forming coordinate bonds (dative covalent bonds) between lone pairs on halide atoms and adjacent beryllium atoms.
Question 4
1 / -0

Which of the following element has the highest melting point?

A
$$Ba$$

B
$$Sr$$

C
$$Ca$$

D
$$Be$$

Solution

Option $$(D)$$ is correct.
$$Be$$ has the highest melting point due to its small size and high polarisation power. When it forms a metal, it means that the bonds are very high energy relative to the atomic size which causes the atoms to be bound tightly. This means it requires more energy (higher temperature) to break the bonds.
Question 5
1 / -0

Which member of IIA group shows covalency?

A
$$Ba$$

B
$$Be$$

C
$$Sr$$

D
$$Mg$$

Solution

Option $$(B)$$ is correct.
$$Be$$ shows covalency. Due to small size, can't ionize easily and high charge density on $$ Be$$, its polarizing power is maximum, since $$Be^{2+}$$ essentially pull the electrons cloud with other elements rather than lose electrons.
Question 6
1 / -0

Alkaline earth metals burn in nitrogen and form nitrides of type $$M_3N_2$$. which of them is volatile in nature?

A
$$Mg_3N_2$$

B
$$Ba_3N_2$$

C
$$Ca_3N_2$$

D
$$Be_3N_2$$

Solution

$$Be$$ is smallest and least electropositive element among alkaline earth metal. $$Be$$ when reacts with $$N$$ form weak bond hence $$B{ e }_{ 3 }{ N }_{ 2 }$$ is volatile while other metals form a strong bond and are not volatile, they are solid.
Question 7
1 / -0

Halides of alkaline earth metals are ionic except:

A
$$Be$$

B
$$Mg$$

C
$$Ca$$

D
$$Ba$$

Solution

Option $$(A)$$ is correct.
Halides of alkaline earth metals are ionic except $$Be$$. The polarising power of beryllium is high and the polarisability of halides is also high so beryllium essentially pulls the donated electrons back so they are effectively shared.
Beryllium is a small atom and forms a +2 charge so it has a high charge density making it easier for it to pull the electrons away from the halide despite its high EN value.
Question 8
1 / -0

Which of the following alkali metal did not easily tarnish in air?

A
$$Be$$

B
$$Ca$$

C
$$Mg$$

D
$$Sr$$

Solution

Option $$(A)$$ is correct.
$$ Be$$ does not easily tarnish in the air because the surface of beryllium metal is covered with a thin layer of oxide that helps protect the metal from attack by air. It does not oxidize in the air even at 600$$^°C$$.
Question 9
1 / -0

Which of the following is a covalent oxide?

A
$$BeO$$

B
$$CaO$$

C
$$SrO$$

D
$$BaO$$

Solution

Option $$(A)$$ is correct.
$$BeO$$ is a covalent oxide because of the small size of beryllium and electronegativity difference between $$Be$$ and $$O$$.
Question 10
1 / -0

Carbide of which of the following elements evolve methane on treatment with water due to diagonal relationship :

A
$$Be_2C , Mg_2C$$

B
$$Be_2C , Al_4C_3$$

C
$$Al_4C_3 , Mg_2C$$

D
$$Be_2C , Ga_4C_3$$

Solution

'Be' and 'Al' have diagonal relationship due to similer charge/ratio.
Due to small size 'Al' and 'Be' form carbide which on hydrolysis evolve methane.
answer is (B).

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The s-Block Elements Test 14

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The s-Block Elements Test 14

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SHARING IS CARING

Question 1

$$Mg$$

$$Ba$$

$$Be$$

$$Ca$$

Solution

Question 2

$$Ca$$

$$Mg$$

$$Sr$$

$$Be$$

Solution

Question 3

$$Mg$$

$$Ba$$

$$Be$$

$$Ca$$

Solution

Question 4

$$Ba$$

$$Sr$$

$$Ca$$

$$Be$$

Solution

Question 5

$$Ba$$

$$Be$$

$$Sr$$

$$Mg$$

Solution

Question 6

$$Mg_3N_2$$

$$Ba_3N_2$$

$$Ca_3N_2$$

$$Be_3N_2$$

Solution

Question 7

$$Be$$

$$Mg$$

$$Ca$$

$$Ba$$

Solution

Question 8

$$Be$$

$$Ca$$

$$Mg$$

$$Sr$$

Solution

Question 9

$$BeO$$

$$CaO$$

$$SrO$$

$$BaO$$

Solution

Question 10

$$Be_2C , Mg_2C$$

$$Be_2C , Al_4C_3$$

$$Al_4C_3 , Mg_2C$$

$$Be_2C , Ga_4C_3$$

Solution

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