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The s-Block Elements Test 33

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The s-Block Elements Test 33
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  • Question 1
    1 / -0
    The fuel in the atomic pile is:
  • Question 2
    1 / -0
    The hydration energy of $$Mg^{2+}$$ is larger than that of
    Solution
    Hydration energy depends on ionic radii and radii decreases as we move along column from left to right and increases down the group, also as positive charge increases, radii dereases. As radii increases, hydration energy decreases. So among all given options only sodium ion has bigger radii than $$Mg^{+2}$$ so it has lower hydration energy than $$Mg^{+2}$$. Hydration energy of $$Na^{+}  = -435$$ KJ/mol. Hydration energy of $$Mg^{+2}  = -1921$$ KJ/mol.
  • Question 3
    1 / -0
    Which of the following forms the most basic hydroxide?
    Solution
    As sodium has highest oxidation potential among all. So it has highest tendency for oxidation reaction and it forms most basic hydroxide.
  • Question 4
    1 / -0
    A chemistry student trying to detect the metallic ion in a salt makes a paste on the clean $$Pt$$  wire-loop of the salt with concentrated $$HCl.$$ When he takes a small amount of this paste and keeps it in a non-luminous Bunsen flame, the color of the flame changes to grassy green. He should, therefore, conclude that the metal is:
    Solution
    A chemistry student trying to detect the metallic ion in a salt makes a paste on the clean $$Pt$$ wire-loop of the salt with concentrated $$HCl$$. When he takes a small amount of this paste and keeps it in a non-luminous Bunsen flame, the color of the flame changes to grassy green. He should , therefore, conclude that the metal is Barium $$(Ba)$$. The table below gives a rough color guide for the elements.

    Flame color :
    $$Li =$$ red
    $$Na =$$  strong, persistent orange
    $$K =$$ lilac (pink)
    $$Rb =$$ red (red-violet)
    $$Cs =$$ blue/violet (see below)
    $$Ca =$$ orange-red
    $$Sr =$$ red
    $$Ba =$$ pale green
    $$Cu =$$ blue-green (often with white flashes)
    $$Pb =$$ gray-white
  • Question 5
    1 / -0
    The metallic luster exhibited by sodium is explained by :
    Solution
    Sodium: It is shiny and many of the properties of metal can be related to something called "metallic bonding". An over simplified description of metallic bonding is the "electron-sea model" in which a metal is envisioned as an array of metal cations surrounded by a sea of mobile electrons. 
    The metallic luster of metals - their shininess, and reflectivity - is due to the absorption and emission of light without changing the wavelength of the photon. Light is absorbed by the electrons, but rather than the energy being converted to heat or to emission of a different wavelength, the energy is emitted at the same wavelength. 
  • Question 6
    1 / -0
    Nitrolim is a :
    Solution
    When nitrogen is passed over calcium carbide at a suitable high temperature, we get a mixture called nitrolim which is a nitrogenous fertilizer, which is a mixture of calcium cyanamide and carbon.
  • Question 7
    1 / -0
    Which of the following metal sulphide is water soluble?
    Solution
    Calcium sulphide, $$CaS$$ and zinc sulphide $$ZnS$$ are slightly soluble in water.
    Cadmium sulphide $$CdS$$ and mercury (II) sulfide are insoluble in water.

  • Question 8
    1 / -0
    X and Y are two metals. When burnt in air, X forms only oxide while Y forms oxide and nitride. The metals X and Y may be :
    Solution
    Reaction with air;
    $$Mg+air\rightarrow MgO+Mg_3N_2$$
    and,
    sodium forms peroxide and monoxide as product with air
    $$Na+air\rightarrow Na_2O_2+Na_2O$$.
  • Question 9
    1 / -0
    Which of the following statement is incorrect?
    Solution
    (A) Sodium and potassium are soft and silvery-white metals. The softness is due to the presence of a single electron in the valence shell in a large-sized metal which produces a weak metallic bonds.
    Thus, option A is correct.

    (B) Sodium and potassium in the air get tarnished due to the formation of a layer of oxide or carbonates. Hence, they are stored in kerosene or paraffin oil.
    Thus, option B is correct.

    (C) Sodium burns in dry oxygen (excess) to form peroxide. Potassium burns in dry oxygen (excess) to form superoxide.
    Thus, option C is incorrect.

    (D) Sodium and potassium are soft and silvery-white metals. The softness is due to the presence of a single electron in the valence shell in a large-sized metal which produces a weak metallic bonds.
    Thus, option D is correct.

    The only incorrect option is C. Hence, option C is the answer.
  • Question 10
    1 / -0
    Which of the following reagent is used as fixer in photography?
    Solution
    $$Na_{2}S_{2}O_{3}$$ (as fixer) dissolves unreacted $$AgBr$$ as: 
    $$2Na_{2}S_{2}O_{3} +AgBr\rightarrow Na_{3}[Ag(S_{2}O_{3})_{2}] + NaBr $$
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