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The s-Block Elements Test 35

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The s-Block Elements Test 35
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  • Question 1
    1 / -0
    Which of the following is/are correct statement(s)?
    Solution
    Calcium ions are essential for the formation of bones and teeth, the enamel in theteeth is a double salt of calcium, $$3Ca_3(PO_4)_2 .CaF_2$$.
    The organic parts of the bone contain several proteins and $$Ca_3(PO_4)_2$$.
    In body, 
    Calcium ions are involved in blood clotting, normal muscle contraction.
  • Question 2
    1 / -0

    Directions For Questions

    Question given below are based on the above shown values of hydration energy and lattice energy:

    ...view full instructions

     Hydration energy
    $${\Delta H}_{hydra}.(kJ \,mol^{-1})$$
    Lattice energy 
    $${\Delta H_u}(kJ \,mol^{-1})$$
     $$Li^+$$ -499LiCl-840 
     $$Na^+$$-390NaCl-776 
     $$K^+$$-305KCl-703 
     $$Cl^-$$-382 
    Which salt can be used to control humidity?
    Solution

    $$\Delta\,H_{solution}\, =\, \Delta\,H_{hydration}\, -\, \Delta\,H_{lattice\ energy}$$ 


     $$\Delta H_{Hydration}\, =\, \Delta H_{hydration}(cation)\, +\, \Delta H_{hydration} (anion)$$


    $$\Delta\,H_{solution}$$ $$(LiCl) = -499 -382 + 840 = -41\ kJ/mol$$

    Similarly,

    $$\Delta\,H_{solution} (NaCl)  = -4 kJ/mol $$

    $$\Delta\,H_{solution}  (KCl) = +16 kJ/mol $$


    As $$\Delta\,H_{solution}  (LiCl)$$ is highest so it will absorb water most easily and it can control humidity easily.

  • Question 3
    1 / -0
    Burning of Mg is extinguished by :
    Solution
    Magnesium fires cannot be extinguished by water. Magnesium continues to burn after oxygen is depleted. It than reacts with nitrogen from air to form magnesium nitride $$(Mg_3N_2)$$. When attempts are made to extinguish magnesium fires with water, magnesium aggressively reacts with hydrogen gas. 
  • Question 4
    1 / -0
    The first ionization potentials ($$eV$$) of $$Be$$ and $$B$$ respectively are:
    Solution
    The first ionization potentials ($$eV$$) of $$Be$$ and $$B$$ respectively are $$9.32, 8,29$$.

    According to theory as we move from lest to right in a period the ionization potential should increase but in case of  $$Be$$ and $$B$$ Beryllium is having more ionization potential than Boran due to completely filled s orbital in Beryllium($$1s^{2}2s^{2}$$).

    Hence option D is correct.
  • Question 5
    1 / -0
    In the mineral, barium ion can be identified by :
    Solution
    $${ Ba }^{ 2+ }$$ ion in solution produces a yellow precipitate with $$K_{2}CrO_{4}$$
    $$Ba^{2+} + k_{2}CrO_{4}\rightarrow BaCrO_{4}\downarrow +  2K^+$$

    $${ Ba }^{ 2+ }$$ ions in solution produces a white precipitate with $$(NH_4)_2SO_{4}$$ Solutions.
    $${ Ba }^{ 2+ }+(NH_4)_2SO_4\rightarrow \underset{White\, ppt}{BaSO_4 \downarrow}+2NH_{4}^+$$

    Hence option- (D) is correct.

  • Question 6
    1 / -0
    The hydration energy of $$Mg^{2+}$$ is greater than that of :
    Solution
    $$Mg^{2+}$$ has the larger hydration energy, because hydration energy increases with the charge on the cation and decreases as the size of the cation increases. Therefore answer is $$Na^+$$.
  • Question 7
    1 / -0
    The alkali metal that reacts with nitrogen directly to form nitride is:
    Solution
    Alkali metals that react with nitrogen directly to form nitride is $$Li$$. This anamolous behaviour is due to its small size and high polarizing power.
    $$6 Li + N_2(g)\rightarrow 2 Li_3N$$
    Hence, option A is correct.
  • Question 8
    1 / -0
    Out of the elements marked A, B, C, D, E, F, G and H
    which form super oxide?  

    Solution
    As we move from top to bottom in a group the tendency of formation of superoxides will be increased due to an increase in the atomic size of the elements
    As we move from left to right in a period the tendency of formation of superoxides will be decreased due to a decrease in the atomic size of the elements.
    So elements E and G forms super oxides.
    Hence option A is correct.
  • Question 9
    1 / -0
    The product obtained on fusion of $$BaS{ O }_{ 4 }$$ and $${ Na }_{ 2 }C{ O }_{ 3 }$$ is:
    Solution
    When $$BaS{ O }_{ 4 }$$ and $${ Na }_{ 2 }C{ O }_{ 3 }$$ are fused, $$BaC{ O }_{ 3 }$$ is obtained.
    $$BaSO_4+Na_2CO_3\rightarrow BaCO_3+2NaSO_4$$
  • Question 10
    1 / -0
    Which of the following is not a alkali metal?
    Solution

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