The p-Block Elements Test

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The p-Block Elements Test - 15

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Weekly Quiz Competition

Question 1
1 / -0

The correct statement with respect to the property of IV A group elements is:

A
their metallic nature decreases from carbon to lead

B
the stability of +2 oxidation state increases from carbon to lead

C
IP value increases from carbon to lead

D
atomic radius decreases from carbon to lead

Solution

Metallic nature increases from top to bottom due to decrease in electronegativity. Also, ionisation potential values decrease from top to bottom due to increase in atomic radius of element. However, stability of +2 oxidation state increases and +4 oxidation state decreases from top to bottom due to inert pair effect.
Question 2
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Which of the following is more stable?

A
$$Pb$$$$^{4+}$$

B
$$Sn$$$$^{4+}$$

C
$$Ge$$$$^{4+}$$

D
$$Si$$$$^{4+}$$
Question 3
1 / -0

Which element does not show allotropy?

A
Pb

B
Si

C
C

D
Sn

Solution

Pb orbitals are too diffused to form strong single Pb-Pb bonds.
Question 4
1 / -0

When a mixture of sand and coke is heated at 3723 K, the product formed is :

A
Carborundum

B
Corundum

C
Diamond

D
Coal

Solution

The reaction is,
$$SiO_2 + 3C \rightarrow SiC+2CO$$.

Silicon carbide is formed which is also known as carborundum.
Note: Corundum is an ore of aluminum.
Question 5
1 / -0

Which of the following is solid at room temperature?

A
$$CO$$

B
$$CO_{2}$$

C
$$SiO_{2}$$

D
$$OF_{2}$$

Solution

Silicon dioxide involves covalent $$Si-O$$ bonds. It has strong van der waal's forces of interactions and thus exists as solids.
Question 6
1 / -0

Bond energy is highest for :

A
$$Sn - Sn$$

B
$$Ge - Ge$$

C
$$C - C$$

D
$$Si - Si$$

Solution

Hint: Bond energy is the amount of energy that tells how strongly two atoms are connected together.

Explanation:

For covalent molecules, the bond energy is directly proportional to the electronegativity of the atoms and inversely proportional to the bond length.

Now moving down the group, the electronegativity of an atom decreases, and the size increases, which results in a decrease in the bond energy.

Thus, the bond energy will be,

$$C-C>Si-Si>Ge-Ge>Sn-Sn$$
Final Answer:

Henceforth the correct answer is option $$C$$.
Question 7
1 / -0

Silica dissolves readily in:

A
$$HF$$

B
$$HCl$$

C
$$HBr$$

D
$$HNO_{3}$$

Solution

Silica is very non-reactive in its normal form and resists the attacks by acids, metals and halogens. However, it reacts with HF and NaOH.

The reactions are respectively:

$$SiO_2 + 4HF \rightarrow SiF_4 + 2H_2O$$

$$SiO_2 + 2NaOH \rightarrow Na_2SiO_3 + H_2O$$

Hence, option A is correct.
Question 8
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Which of the following is correct?

A
$$GeO_{2}$$ is basic

B
$$SiO_{2}$$ is acidic oxide

C
$$SnCl_{4}$$ is more stable than $$SnCl_{2}$$

D
$$PbCl_{4}$$ is more stable than $$PbCl_{2}$$

Solution

Silicon dioxide has no basic properties, it is weakly acidic in nature.

$$GeO_2$$ is amphoteric in nature.

$$SnCl_2$$ is is more stable than $$SnCl_4$$ due to high positive charge on it and covalent character in $$SnCl_4$$.

Due to the inert pair effect, the higher oxidation state is less stable. The stability of $$+4$$ oxidation state decreases down the group. So, $$PbCl_2$$ is more stable than $$PbCl_4$$.

Hence option B is correct.
Question 9
1 / -0

Which element does not exhibit allotropy?

A
$$C$$

B
$$Sn$$

C
$$Si$$

D
$$Pb$$

Solution

$$Pb$$ orbitals are too large to form strong single $$Pb-Pb$$ bonds. So, it does not exhibit allotropy.
Question 10
1 / -0

Which is the anhydride of orthosilicic acid?

A
Si

B
SiO

C
$$SiO_{2}$$

D
$$SiO_{3}$$

Solution

Orthosilicic acid is $$H_4SiO_4$$. The anhydride of this acid polymerizes to form $$SiO_2$$.

$$H_4SiO_4 \xrightarrow{-2H_2O} SiO_2$$

Hence, option C is correct.

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 15

Result

The p-Block Elements Test - 15

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SHARING IS CARING

Question 1

their metallic nature decreases from carbon to lead

the stability of +2 oxidation state increases from carbon to lead

IP value increases from carbon to lead

atomic radius decreases from carbon to lead

Solution

Question 2

$$Pb$$$$^{4+}$$

$$Sn$$$$^{4+}$$

$$Ge$$$$^{4+}$$

$$Si$$$$^{4+}$$

Question 3

Pb

Si

C

Sn

Solution

Question 4

Carborundum

Corundum

Diamond

Coal

Solution

Question 5

$$CO$$

$$CO_{2}$$

$$SiO_{2}$$

$$OF_{2}$$

Solution

Question 6

$$Sn - Sn$$

$$Ge - Ge$$

$$C - C$$

$$Si - Si$$

Solution

Question 7

$$HF$$

$$HCl$$

$$HBr$$

$$HNO_{3}$$

Solution

Question 8

$$GeO_{2}$$ is basic

$$SiO_{2}$$ is acidic oxide

$$SnCl_{4}$$ is more stable than $$SnCl_{2}$$

$$PbCl_{4}$$ is more stable than $$PbCl_{2}$$

Solution

Question 9

$$C$$

$$Sn$$

$$Si$$

$$Pb$$

Solution

Question 10

Si

SiO

$$SiO_{2}$$

$$SiO_{3}$$

Solution

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