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The p-Block Elements Test - 18

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The p-Block Elements Test - 18
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Silicones have the general formula :
    Solution
    Organosilicon compounds are also called silicones which have general formula $$ [R_{2} SiO]_{n} $$.
  • Question 2
    1 / -0
    Which of the following is wrong about silica?
    Solution
    Quartz is the second most abundant mineral in the Earth's continental crust, after feldspar. Its crystal structure is a continuous framework of SiO4 silicon–oxygen tetrahedral, with each oxygen being shared between two tetrahedra, giving an overall chemical formula of SiO2. Pure quartz, traditionally called rock crystal or clear quartz, is colorless and transparent or translucent,  U.V. light can pass through quartz.
  • Question 3
    1 / -0
    $$SiO_{2}+A\rightarrow X+Y$$ In this reaction 'Y' is one of the global warming gases. 'A' is the water soluble alkali metal carbonate. Whose molecular weight is 106. The common name of 'X' is :
    Solution
    $$SiO_2 + Na_2CO_3 \rightarrow Na_2SiO_3 + CO_2$$
    A is $$Na_2CO_3$$ having atomic weight 106, Y is $$CO_2$$ and X is $$Na_2SiO_3$$ which is also called water glass.
  • Question 4
    1 / -0
    Hydrolysis of $$SiCl_{4}$$ gives compound $$X$$ and $$HCl$$. On heating to $$1000^{\circ}$$ $$C$$. $$X$$ loses water and forms $$Y$$. Identify $$X$$ and $$Y$$ respectively.
    Solution
    $$H_4SiO_4 \xrightarrow {1000 \ ^oC} SiO_2 + H_2O$$
    On hydrolysis, all the bonds of $$SiCl_{4}$$ are broken after which $$H^{+}$$ forms bonds with $$Cl^{-}$$ and $$OH^{-}$$ forms bonds with $$Si^{4+}$$, thus forming $$H_{4}SiO_{4}$$ and $$HCl$$.
    On deep heating, $$H_{4}SiO_{4}$$ loses two water molecules to form $$SiO_{2}$$
  • Question 5
    1 / -0
    Which of the following Si biocompatible

    Solution
    Silicones are used as sealant, greases,electrical insulators and for water proofing of fabrics. Being biocompatible they are also used in surgical and cosmetic plants.

  • Question 6
    1 / -0
    Which of the following bonds is present in silicone ?

    Solution

    Explanation

    Silicones belong to the organo-silicon polymer family since they are comprised entirely of carbon, silicon, and oxygen atoms.

    The repeating unit on all silicones is $$~{{R}_{2}}SiO$$, where R is the alkyl group.

    Because silicon is a carbon family element, its atoms are tetravalent. Oxygen is a bivalent atom. Each silicon atom is connected to two oxygen atoms and two carbon atoms. In silicones, each silicon atom has two methyl groups attached to it.

    As a result of the preceding construction, the bonding between silicon and oxygen atoms can be described as $$Si-O-Si-O-Si$$

    Henceforth, the correct answer is option A.
  • Question 7
    1 / -0
    Silica reacts with a hydride of superhalogen to form 'X'. On hydrolysis of 'X', another compound 'Y' is formed. 'Y' on heating at 1000$$^0$$C loses water to form 'Z'. The 'Z' can also be prepared by the reaction
    Solution
    Silica reacts with hydride of superhalogen to form $$SiX_4$$ which is compound X. It on hydrolysis gives $$Si(OH)_4$$ which is compound Y.  This on heating at $$1000^0C$$ loses water to form $$SiO_2$$ which is compound Z.
    $$SiO_2$$ can also be prepared by the reaction of silicon with oxygen.
    $$Si+O_{2}\rightarrow SiO_{2}$$
  • Question 8
    1 / -0
    The high melting point of $$ SiO_{2}$$ is due to:
    Solution
    The structure of silica is very similar to that of diamond, with each silicon atom having tetrahedral bond and bonded to 4 oxygen atoms, which in turn are connected to another silicon atom, thus effectively, each C-C bond of diamond has been replaced by a Si-O-Si link to give the silica lattice.Thus, due to strong covalent network, like diamond, even silica has very high melting point.
  • Question 9
    1 / -0
    A. $$CCl_{4}$$ does not act as lewis acid. 
    B. Silanes are strong reducing agents.
    C. Crystalline silica will have Diamond like structure.
    Which of the above statement(s) is/are true?
    Solution
    $$CCl_{4}$$ is electron precise. Hence it is not a lewis acid.
    Silanes possess $$Si-H$$ bonds, in which the $$Si$$ atom has a partial positive charge and the $$H$$ atoms have a partial negative charge. Thus, silanes can donate a $$H^{-}$$ ion, which can act as reducing agents.
    Crystalline silica does have diamond like structure.
  • Question 10
    1 / -0
    List -I                                                  List -2
    Arrange properly.
    A. Diamond                                       1.  Metal electrode
    B. Graphite                                        2. sp hybridized
    C. Silica                                             3. Acheson's process
    D. $$CO_2 $$                                             4. Agate
                                                              5. Cutting of glass
    The correct match is?

    Solution
    Diamond is used for cutting glass as diamond is harder than glass.
    Acheson process is used to prepare graphite from coke.
    $$CO_{2}$$ is linear in shape and hence has $$sp$$ hybridisation.
    Silica is used as agate.

    Option C is correct.
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