The p-Block Elements Test

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The p-Block Elements Test - 27

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Weekly Quiz Competition

Question 1
1 / -0

Glass is best described as a :

A
solid

B
liquid

C
super cooled liquid

D
colloidal sol

Solution

Glass is an amorphous (non-crystalline) solid material which doesn't have fix patterns of particles so it is a super cooled liquid.
Question 2
1 / -0

Which silicon compound is used as lubricant?

A
Asbestos

B
Silicone's

C
Zeolites

D
Mica

Solution

Silicone-based lubricants are super-slippery, as they are chemically hydrophobic. They tend to retain lubrication longer than water-based lubricants.
Question 3
1 / -0

Directions For Questions

The name 'silica' covers an entire group of minerals, which have the general formula $$SiO_2$$, the most common of which is quartz. Quartz is a framework silicate with $$SiO_4$$ tetrahedral arranged in spirals. The spirals can turn in a clockwise or anti-clockwise direction-a feature that results in there being two mirror images, optically active, varieties of quartz.

...view full instructions

The following pictures represent various silicate anions. Their formula are respectively:

A
$$SiO^{2-}_3$$ $$Si_3O^{2-}_7$$

B
$$SiO^{4-}_4$$ $$Si_3O^{8-}_{10}$$

C
$$SiO^{2-}_4$$ $$Si_3O^{2-}_9$$

D
$$SiO^{4-}_3$$ $$Si_3O^{8-}_7$$

Solution

in the first structure, one silicon(black hole ) atom attach with 4 oxygen(hole ) atom the following picture 1 is showing $$SiO_4^{4-}$$ here the $$Si(O_4)^4-$$ see like this

in the second picture is showing is $$Si_3O_{10}^{8-}$$
Question 4
1 / -0

Silicon is the _________ abundant element in the earth's crust.

A
most

B
2nd most

C
3rd most

D
none of these

Solution

Silicon is the second (27.7 % by mass) most abundant element in the earth's crust.
Question 5
1 / -0

Number of isotopes of carbon is :

A
$$3$$

B
$$4$$

C
$$5$$

D
$$6$$

Solution

Any of two or more forms of a chemical element, having the same number of protons in the nucleus, or the same atomic number, but having different numbers of neutrons in the nucleus, or different atomic weights are called isotopes.

Number of isotopes of carbon are 3.They are $$C_6^{12}$$,$$C_6^{13}$$ and $$C_6^{14}$$
Hence option A is correct.
Question 6
1 / -0

Thallium shows different oxidation states because :

A
of its high reactivity.

B
of inert pair of electrons.

C
of its amphoteric nature.

D
it is a transition metal.
Solution
Hint: Thallium has electrons in d and f subshells which provide poor shielding.
Correct Answer: Option B

Explanation
- $$Thallium$$ is a $$p$$ block element belonging to group $$13$$ and period $$6$$.
- Electronic configuration of $$Thallium$$ is $$\left [ Xe \right ] 4f^{14} 5d^{10} 6s^{2} 6p^{1}$$.
- $$d$$ and $$f$$ electrons of inner shells provide poor shielding, thus the attraction of the nucleus on the $$s$$ electrons of the outermost shell increases. This is called the inert pair effect.
- Whereas, $$s$$ electrons provide strong shielding to $$p$$ electrons, thus making it easy for the $$p$$ electrons to be released.
- Thus, although $$Thallium$$ shows $$+3$$ and $$+1$$ oxidation states, $$+1$$ is more common.
Question 7
1 / -0

Which of the following is most stable?

A
$$Sn^{2+}$$

B
$$Ge^{2+}$$

C
$$Si^{2+}$$

D
$$Pb^{2+}$$

Solution

Option (D) is correct.
$$Pb^{2+}$$ is most stable.
The stability of $$+2$$ oxidation state increases down the group due to inert pair effect.
$$Pb^{2+}$$ > $$Sn^{2+}$$> $$Ge^{2+}$$ > $$Si^{2+}$$
Question 8
1 / -0

Aluminium is much more reactive than iron because its standard reduction potential is higher than iron. Still, aluminium is less easily corroded than iron because :

A
aluminium reacts with atmospheric carbon dioxide to form a self-protective layer of $$Al_2O_3$$.

B
it has a higher reducing power and forms a self protective layer of $$Al_2O_3$$.

C
it has a higher reducing power and does not react with oxygen so easily.

D
both A and B.

Solution

Aluminium is much more reactive than iron because its standard reduction potential is higher than iron. However, aluminium is still less easily corroded than iron because oxygen forms a protective oxide layer of $$Al_2O_3$$ on its surface.
Question 9
1 / -0

Boron compounds behave as Lewis acids because of their :

A
acidic nature.

B
covalent nature.

C
ionic nature.

D
vacant orbital.

Solution

A Lewis acid is an electron pair acceptor, while Lewis base is an electron pair donor.

Boron compounds behave as Lewis acids because of their vacant orbital. Its octet is incomplete, in which boron can accept an electron pair.

Hence, option D is correct.
Question 10
1 / -0

Which is likely to show inert pair effect?

A
K

B
Mg

C
Al

D
Pb

Solution

Inert pair effect is the name given to tendency of electrons present in the outer most s sub shell of post-transition metals, like Pb, Bi etc. to not undergo ionisation, and to remain unshared. This is most stated in Groups 13, 14 and 15.

A possible given explanation is that due to presence of f-subshell electrons are to diffused, due to the shape of the f orbitals, to effectively shield the s electrons from the pull of the nucleus.

A good example would be the elements of Group 13. Aluminium in +1 state is unknown, and the stability of +1 oxidation state increases as we go down the group. Thallium is most stable in +1 oxidation state, and compounds of Thallium in +3 oxidation state are known to be very strong oxidising agents, and have a tendency to reduce quickly to +1 state.
Hence option D is correct.

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The p-Block Elements Test - 27

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The p-Block Elements Test - 27

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Question 1

solid

liquid

super cooled liquid

colloidal sol

Solution

Question 2

Asbestos

Silicone's

Zeolites

Mica

Solution

Question 3

$$SiO^{2-}_3$$ $$Si_3O^{2-}_7$$

$$SiO^{4-}_4$$ $$Si_3O^{8-}_{10}$$

$$SiO^{2-}_4$$ $$Si_3O^{2-}_9$$

$$SiO^{4-}_3$$ $$Si_3O^{8-}_7$$

Solution

Question 4

most

2nd most

3rd most

none of these

Solution

Question 5

$$3$$

$$4$$

$$5$$

$$6$$

Solution

Question 6

of its high reactivity.

of inert pair of electrons.

of its amphoteric nature.

it is a transition metal.

Solution

Question 7

$$Sn^{2+}$$

$$Ge^{2+}$$

$$Si^{2+}$$

$$Pb^{2+}$$

Solution

Question 8

aluminium reacts with atmospheric carbon dioxide to form a self-protective layer of $$Al_2O_3$$.

it has a higher reducing power and forms a self protective layer of $$Al_2O_3$$.

it has a higher reducing power and does not react with oxygen so easily.

both A and B.

Solution

Question 9

acidic nature.

covalent nature.

ionic nature.

vacant orbital.

Solution

Question 10

K

Mg

Al

Pb

Solution

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