The p-Block Elements Test

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The p-Block Elements Test - 34

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following do not have linear structure?

A
$$CO_2$$

B
$$N_2O$$

C
$$BeF_2$$

D
$$SnCl_2$$

Solution

Option $$(D)$$ is correct.

$$SnCl_2$$ do not have a linear structure. It has a lone pair of the electron due to which shape of molecule changes to angular i.e. $$V$$- shaped.

Hence the correct option is D.
Question 2
1 / -0

What is the oxidation state of nitrogen in $$N_2O_5$$?

A
5

B
10

C
4

D
3

Solution

Let the oxidation state of $$N$$ be $$x$$. Oxidation state of $$O$$ is $$-2$$ as it is in oxide form.

$$\Rightarrow 2x+5(-2)=0$$
$$\Rightarrow x=\dfrac{10}{2}=+5$$
Question 3
1 / -0

Which is only metal in group 15?

A
Phosphorus

B
Arsenic

C
Antimony

D
Bismuth

Solution

Option $$(D)$$ is correct.
Bismuth is only metal in group 15.
Phosphorus is non-metal, antimony and arsenic both are metalloids.
Question 4
1 / -0

Which of these forms nitride with nitrogen at higher temperature?

A
Aluminium

B
Boron

C
Both $$A$$ and $$B$$

D
Indium

Solution

Option $$(C)$$ is correct.
Aluminium and boron forms nitride with nitrogen at higher temperature due to the high bond energy of nitrogen. In case of aluminium, a thin oxide layer is formed so it also needs high temperature to react with nitrogen to form the nitride.
Question 5
1 / -0

Why $$Bi^{3+}$$ more stable than $$Bi^{+5}$$?

A
Due to inert pair effect

B
Due to inert gas electronic configuration

C
Due to half filled configuration

D
Due to lanthanide Contraction

Solution

Option $$(A)$$ is correct.
$$Bi^{3+}$$is more stable than $$Bi^{5+}$$ due to inert pair effect. Ongoing down the group, inert pair effect increases due to more penetration of $$s$$- orbital in nucleus due to which element tends to show lower oxidation state more stable than higher oxidation state. Thus, bismuth will show a strong tendency to change into +3 state from +5 state.
Question 6
1 / -0

Straight chain silicones are prepared by hydrolysis by:

A
$$R_2SiCl_2$$

B
$$R_3SiCl$$

C
$$RSiCl_3$$

D
$$R_2Si$$

Solution

Hydrolysis of $$R_2SiCl_2$$ gives straight chain that is linear silicones.
For example, if we consider $$R$$ as $$-CH_3$$ group, the molecule becomes $$(CH_3)_2SiCl_2$$, that is Dimethyldichlorosilane. On performing hydrolysis of this compound, we get.
$$n(CH_3)_2SiCl_2$$$$+$$$$nH_2O$$$$=$$$$[(CH_3)_2SiO]_n$$$$+$$$$2nHCl$$, where $$n$$ represents an integer or the number of moles.
$$[(CH_3)_2SiO]_n$$ are the straight chain silicones, that is compounds containing $$Si-O$$ backbones. They are polymers.
Option A is the correct answer.
Question 7
1 / -0

Which of the following is not pseudo halogen?

A
$$(CN_2)$$

B
$$(SCN_2)$$

C
$$(OCN)_2$$

D
$$H_2$$

Solution

Option $$(D)$$ is correct.

$$H_2$$ is not pseudo halogen compound.

The pseudohalogens are polyatomic analogues of halogens, whose chemistry, resembling that of the true halogens, allows them to substitute for halogens. They have a general formula of $$Ps–Ps$$ or $$Ps–X$$ (where $$Ps$$ is a pseudohalogen group), such as cyanogen, pseudohalide anions, such as cyanide ion. Well-known pseudohalogen functional groups include cyanide, cyanate, thiocyanate, and azide.
Question 8
1 / -0

Which of the following statement is correct?

A
The 1st ionisation enthalpy of group 13 elements is less than that of group 2 elements

B
The 1st ionization enthalpy of group 16 elements is more than of group 15 elements.

C
Germanium is non-metal

D
$$ClO_7$$ is amphoteric oxide

Solution

The statement (A) is correct.

The 1st ionisation enthalpy of group 13 elements is less than that of group 2 elements.

$$p$$ electrons are less penetrating and more shielded than $$s$$ electrons.

They are farther from the nucleus and hence held less tightly than the $$s$$ electrons.

So $$p$$ electrons can be easily removed.
Question 9
1 / -0

Which of the following metal will give $$N_2O$$ on reaction with dilute nitric acid?

A
$$Zn$$

B
$$Cu$$

C
$$Hg$$

D
$$Ag$$

Solution

Concentrated nitric acid is a powerful oxidising agent, and its reaction with zinc involves a complicated set of redox reactions. However the primary product is still zinc nitrate.

$$4Zn + 10HNO_3 \rightarrow 4Zn(NO_3)_2 + N_2O + 5H_2O$$
Question 10
1 / -0

Phosphorus pentaoxide reacts with $$H_2O$$ to form an acid. What is the basicity of that acid?

A
1

B
3

C
2

D
4

Solution

Option $$(B)$$ is correct.
Phosphorus pentaoxide reacts with $$H_2O$$ to form phosphoric acid.
$$P_2O_5 + 3H_2O \rightarrow 2H_3PO_4$$
Basicity of phosphoric acid is 3.Basicity of an acid refers to the number of replaceable hydrogen atoms in one molecule of the acid
$$H_3PO_4(aq) \rightarrow 3H^+(aq) + PO_4^{ 3-}(aq)$$

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The p-Block Elements Test - 34

Result

The p-Block Elements Test - 34

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SHARING IS CARING

Question 1

$$CO_2$$

$$N_2O$$

$$BeF_2$$

$$SnCl_2$$

Solution

Question 2

5

10

4

3

Solution

Question 3

Phosphorus

Arsenic

Antimony

Bismuth

Solution

Question 4

Aluminium

Boron

Both $$A$$ and $$B$$

Indium

Solution

Question 5

Due to inert pair effect

Due to inert gas electronic configuration

Due to half filled configuration

Due to lanthanide Contraction

Solution

Question 6

$$R_2SiCl_2$$

$$R_3SiCl$$

$$RSiCl_3$$

$$R_2Si$$

Solution

Question 7

$$(CN_2)$$

$$(SCN_2)$$

$$(OCN)_2$$

$$H_2$$

Solution

Question 8

The 1st ionisation enthalpy of group 13 elements is less than that of group 2 elements

The 1st ionization enthalpy of group 16 elements is more than of group 15 elements.

Germanium is non-metal

$$ClO_7$$ is amphoteric oxide

Solution

Question 9

$$Zn$$

$$Cu$$

$$Hg$$

$$Ag$$

Solution

Question 10

1

3

2

4

Solution

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