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The p-Block Elements Test - 37

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The p-Block Elements Test - 37
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following has allotropes?
    Solution
    Boron shows allotropy and exists in two forms crystalline and amorphous. Aluminum is a soft metal and does not exist in different forms.
  • Question 2
    1 / -0
    For one of the element various successive ionization enthalpies (in $$kJ$$ $${mol}^{-1}$$) are given below:
    I.E$${1}^{st}$$$${2}^{nd}$$$${3}^{rd}$$$${4}^{th}$$$${5}^{th}$$
    $$577.5$$$$1810$$$$2750$$$$11,580$$$$14,820$$
    The element is :
    Solution
    As the fourth ionization energy is exceptionally high it should be a third group element hence it will be $$Al$$.
  • Question 3
    1 / -0
    Which of the following occur with zinc in sulfides?
    Solution
    Indium tends to occur with zinc in sulfide minerals because the two elements have similar atomic radii and other chemical properties.
  • Question 4
    1 / -0
    Which of the following elements forms only covalent bonds with others?
    Solution
    Boron forms only covalent compounds whereas aluminIum and other elements of group 13 form even some ionic compounds.
  • Question 5
    1 / -0
    Which of the following exhibit covalency only upto 4?
    Solution
    Boron exhibit maximum covalency of four e.g., $${BH_ 4}^{-}$$ ion while other members exhibit a maximum covalency of six e.g., $$[Al{(OH)}_6]^{3-}$$.
  • Question 6
    1 / -0
    In $$III\ A$$ group which element shows different behaviour from its other group members:
    Solution
    Option $$(D)$$ is correct. 
    In $$III\ A$$ group, boron shows different behaviour from its other group members due to extremely low size and high nuclear charge/size ratio, high electronegativity and non-availability of $$d$$- electrons. 
  • Question 7
    1 / -0
    Which of the following element shows only $$+3$$ oxidation state?
    Solution
    Option $$(A)$$ is correct.
    Boron shows only $$+3$$ oxidation state.
    Electronic configuration of boron family  is $$ns^2 \:np^1$$. The atoms of these elements have 3 valence electrons, therefore all these elements show maximum of + 3 oxidation state. Boron shows only +3 oxidation state in its compound & other elements also show +1 oxidation state.The stability of the +3 oxidation state decreases on moving down the group.
    The +1 oxidation state becomes more stable as we move down to the group from boron to thallium because of inert pair effect.In the case of the last element, after the removal of one electron from $$p$$ orbital, the remaining $$ns^2$$ are strongly attracted by the nucleus and do not participate in bonding. 
  • Question 8
    1 / -0
    Three centered bond is present in which of the following compound of group 13 element?
    Solution
    Option $$(B)$$ is correct.
    Three centered bond is present in diborane,$$B_2H_6$$. It has three-centre 2-electron bonds, two of them to be exact, each one consisting of the two boron atoms and a hydrogen atom sharing two electrons.
    $$B_2H_6$$ has four terminal and two bridging hydrogen atoms.The four terminal hydrogen atoms and two boron atoms lie one plane. Above and below this plane, there are two bridging hydrogen atoms. Each boron atom forms four bonds eventhough it has only three electrons. The terminal $$B-H$$ bonds are regular bonds but the bridge $$B-H$$ bonds are different. Each bridge hydrogen is bonded to the two boron atoms only by sharing of two electrons. Such covalent bond is called three centre electron pair bond or a multicentre bond or banana bond

  • Question 9
    1 / -0
    Which of the following shows non-metallic character?
    Solution
    Option $$(A)$$ is correct.
    $$B$$ shows non-metallic character while $$Al,Ga,Th$$ are metals.
  • Question 10
    1 / -0
    Which among the following can show the maximum of four covalencies?
    Solution
    Option $$(D)$$ is correct.
    Boron shows the maximum of four covalencies as it has only four orbitals in its outermost shell (e.g. $$BH_4^-$$).Other elements of the group show covalency of even six due to the presence of $$d-$$ orbitals in them(e.g. $$[Al(OH)_6]^{3-}$$).
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