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The p-Block Elements Test - 38

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The p-Block Elements Test - 38
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  • Question 1
    1 / -0
    Oxide of which group 13 element is acidic in nature:
    Solution
    Option $$(A)$$ is correct.
    Oxide of boron is acidic in nature. Boron is a non-metal and oxides of non-metals acidic in nature.Boron oxide is acidic and reacts with water to form an acid, boric acid. So, it is an acidic oxide.
    $$B_2O_3 + 3H_2O \rightarrow 2B(OH)_3$$
    While moving down the group, acidic strength decreases and basic strength increases, thus the acidic character of oxides decreases down the group.
    Oxides of other elements of the group are amphoteric and basic in nature.
  • Question 2
    1 / -0
    Halide of which element exist only in monomeric form is/are:
    Solution
    Option $$(A)$$ is correct.
    Halides of boron exist only in monomeric form because boron atom is too small to coordinate with large halide ions.The energy released during the formation of the bridge structure is not sufficient for the cleavage of the typical $$p\pi- p\pi$$ bond in $$BX_3$$.
    Other members of the group exist as dimmers having halogen - bridged structure.
  • Question 3
    1 / -0
    Which of the following element of group IIIA element will show allotropy ?
    Solution

    Due to its small size and similar charge/mass ratio, boron differs from other group 13 members, but it resembles closely with silicon, the second element of group 14 to exhibit diagonal relationship. Some important similarities between boron and silicon are:

    a)      Both of them do not form cation and form only covalent compounds.

    b)      Both exists in amorphous and crystalline state and exhibit allotropy.

     Boron can be prepared in several crystalline and amorphous forms. Well known crystalline forms are α-rhombohedral, β-rhombohedral, and β-tetragonal.

  • Question 4
    1 / -0
    The hot water or steam is decomposed by group 13 elements except:
    Solution

    Boron is classified as a metalloid while the rest are considered post-transition metals. Most of the elements in the boron group show increasing reactivity as the elements get heavier in atomic mass and higher in atomic number. Boron, the first element in the group, is generally unreactive with many elements except at high temperatures. Hence, under normal circumstances boron does not react with water.

  • Question 5
    1 / -0
    The halides of group IIIA  elements behave as lewis acids. The acceptor ability is maximum for halides of  :
    Solution
    Option $$(D)$$ is correct.
    The acceptor ability is maximum for halides of  boron due to the availability of 3 valence electrons ($$2s^2 \:2p^1$$) for covalent bond formation using four orbitals ($$2s, 2p_x, 2p_y $$and $$2p_z$$) leads to electron deficiency in boron compounds. This deficiency makes them good electron acceptor and thus boron compounds behave as lewis acids.
  • Question 6
    1 / -0
    Which of the following is acidic in nature?
    Solution
    Option $$(D)$$ is correct.
    $$B(OH)_3$$ is acidic in nature while $$Al(OH)_3$$,$$Be(OH)_2$$ are amphoteric and $$Mg(OH)_2$$ is basic in nature.
  • Question 7
    1 / -0
    Aluminium oxide is not reduced by chemical reactions because:
    Solution
    As $$Al_2O_3$$ is highly stable it does not get reduced by chemical reaction because the small $$Al^{3+}$$ ions and $$O^{2-}$$ ions forms a very stable lattice.
  • Question 8
    1 / -0
    The formula of mineral borax is:
    Solution

    The formulae for mineral borax is :

    $$Na_2B_4O_7 · 10H_2O$$

    Mineral Borax is also easily converted to boric acid and other borates, which have many applications.

    When mineral borax is added to a flame, it produces a yellow green color. Borax is not used for this purpose in fireworks due to the overwhelming yellow colour of sodium. Boric acid is used to colour methanol flames a transparent green.

  • Question 9
    1 / -0
    $$Al$$ should not be washed with material containing washing soda :
    Solution

    $$2Al+Na_2CO_3+3H_2O \rightarrow 2NaAlO_2+CO_2 +3H_2$$

    So if $$Al$$ is washed with washing soda it forms sodium aluminate ($$NaAlO_2$$) which is soluble in water

    Hence option C is correct.

  • Question 10
    1 / -0
    An element of p-block in which last electron enters into s-orbital of valence shell instead of p-orbital is:
    Solution
    Electronic configuration of He is $$1{ s }^{ 2 }$$. It is kept in p-block with group 18 elements even after last electron enters into s-orbital of valence shell instead of p-orbital because it is a noble metal.

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