The p-Block Elements Test

Result

The p-Block Elements Test - 40

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

The type of hybridization of boron in diborane is :

A
$$sp$$

B
$$sp^2$$

C
$$sp^3$$

D
$$sp^3d^2$$

Solution

The hybridization of $$B_2H_6$$ (diborane) is $$sp^{3}$$ because each boron molecule has a tetrahedral geometry.
Hence option C is correct
Question 2
1 / -0

Which of the following is non-metal?

A
$$Ga$$

B
$$In$$

C
$$Th$$

D
$$B$$
Solution
Explanation:
- Nonmetals are present in the right corner of the periodic table in $$p-block$$
- Nonmetals accept electrons while metals donate electrons.
- $$Ga, In$$ are a post-transition metal present in $$p-block$$
- $$Th$$ is a radioactive metal present in the $$f-block$$ in the actinide series.
- $$B$$ is a nonmetal as it accepts electrons and it is present in $$p-block$$
Correct Option : $$D$$
Question 3
1 / -0

The no. of unpaired electrons in carbon is :

A
$$1$$

B
$$2$$

C
$$3$$

D
$$4$$

Solution

based on the electronic configaration of carbon, it has two unpaired electrons present.
Hence, option B is correct.
Question 4
1 / -0

An aqueous solution of borax is :

A
neutral

B
acidic

C
basic

D
none
Solution
Hint: If a strong base and weak acid are formed in the reaction then the solution becomes basic in nature.
If a strong acid and weak base are formed in the reaction then the solution becomes acidic in nature.

Explanation:

Reaction of borax with water is shown as below;
$$ Na_2B_4O_7 + 7H_2O \rightarrow 2NaOH + 4H_3BO_3 + 10H_2O $$
In the above reaction, there is the formation of $$NaOH$$ and $$H_3BO_3$$ that is boric acid.

Sodium hydroxide is a very strong base. On the other hand, boric acid ($${H}_{3}{BO}_{3}$$) is a weak acid.

So, both sodium hydroxide and boric acid try to neutralize each other. But due to the high basic strength of sodium hydroxide, weak acid boric acid cannot completely neutralize it in the solution and the solution will become slightly alkaline in nature.
Correct Option: $$C$$
Question 5
1 / -0

In which of the following the inert pair effect is most prominent?

A
$$C$$

B
$$Si$$

C
$$Ge$$

D
$$Pb$$

Solution

In lead ($$Pb$$) inert pair effect is most prominent because as we move from carbon to lead in the group the tendency of non-participation inner ns electrons in chemical bonding increases due to the large size of atoms.
So Pb is having more tendency of showing inert pair effect.($$Pb$$ is more stable at +2 oxidation state than +4 oxidation state)
Hence option $$D$$ is correct.
Question 6
1 / -0

Element of group $$13$$ :

A
exhibit oxidation state of $$+3$$ only

B
form $$M^+$$ and $$M^{+3}$$

C
exhibit oxidation state of $$+1$$ and $$+3$$

D
none of these

Solution

Element of group $$13$$ exhibit oxidation state of $$+1$$ and $$+3$$.
In $$Ga, In$$ and $$Tl$$, both $$+1$$ and $$+3$$ oxidation states are observed. The elements belong to $$13$$ group.

For thallium $$+1$$ is more stable than $$+3$$ due to inert pair effect.
Question 7
1 / -0

Silicon is used as semiconductor in solid state devices in:

A
computers

B
microelectronics

C
both $$A$$ and $$B$$

D
none of these

Solution

Option $$(C)$$ is correct.
Silicon is used as semiconductor in solid state devices in computers and microelectronics because of its combination of low raw material cost, relatively simple processing, higher band gap and a useful temperature range make it currently the best compromise among the various competing materials. Silicon can be easily oxidized to form thin layer of $$SiO_2$$ and thick oxide used else where to isolate components from one another.
Question 8
1 / -0

The metalloid in the carbon family is:

A
carbon

B
tin

C
silicon

D
lead

Solution

In Group 14 elements, only carbon and silicon form bonds as nonmetals by sharing electrons covalently. Silicon and germanium are semimetals (metalloids), existing in compounds with either +4 or -4 charges. Tin and lead are metals.
Question 9
1 / -0

Which of the following characteristic property increases as we go down the carbon group?

A
Acidic nature of oxides

B
Electronegativity

C
Metallic characters

D
Non-metallic characters

Solution

The metallic character of an element can be defined as how readily an atom can lose an electron.Metallic character increases as you move down a group because the atomic size is increasing. When the atomic size increases, the outer shells are farther away.The electrons of the valence shell have less attraction to the nucleus and, as a result, can lose electrons more readily. This causes an increase in metallic character.
Question 10
1 / -0

The number of oxides formed by carbon is:

A
$$2$$

B
$$3$$

C
$$4$$

D
$$5$$

Solution

Carbon can form three oxides - carbon-mono oxide, carbon di-oxide and carbon sub-oxide.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 40

Result

The p-Block Elements Test - 40

Score

-

Rank

-

SHARING IS CARING

Question 1

$$sp$$

$$sp^2$$

$$sp^3$$

$$sp^3d^2$$

Solution

Question 2

$$Ga$$

$$In$$

$$Th$$

$$B$$

Solution

Question 3

$$1$$

$$2$$

$$3$$

$$4$$

Solution

Question 4

neutral

acidic

basic

none

Solution

Question 5

$$C$$

$$Si$$

$$Ge$$

$$Pb$$

Solution

Question 6

exhibit oxidation state of $$+3$$ only

form $$M^+$$ and $$M^{+3}$$

exhibit oxidation state of $$+1$$ and $$+3$$

none of these

Solution

Question 7

computers

microelectronics

both $$A$$ and $$B$$

none of these

Solution

Question 8

carbon

tin

silicon

lead

Solution

Question 9

Acidic nature of oxides

Electronegativity

Metallic characters

Non-metallic characters

Solution

Question 10

$$2$$

$$3$$

$$4$$

$$5$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.