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The p-Block Elements Test - 41

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The p-Block Elements Test - 41
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  • Question 1
    1 / -0
    What is hybridisation of boron in $$[B(OH)_4]^-$$?
    Solution


    Hybridisation of boron in $$[B(OH)_4]^{-}$$ is $$sp^{3}$$
    Hybridisation is $$sp^{3}$$     (Refer to Image 1)

    electronic configuration of boron $$\longrightarrow1s^{2}2s^{2}2p^1$$
    (Refer to Image 2)

    electronic configuration of boron in first excited state 
    (Refer to Image 3)

    Boron forms $$4sp^3$$ hybrid orbitals
    The unpaired orbitals forms covalent bond with $$3-OH$$ groups
    The empty orbital forms co-ordinate covalent with $$-OH^{-}$$ group
    The boron atom in $$B(OH)_3 $$ is electron deficient: it has 6 rather than 8 electrons in its valence shell. It acts as a Lewis acid by readily accepting the lone pair from the oxygen in a water molecule to go from sp2 to sp3 hybridisation.

  • Question 2
    1 / -0
    Which of the following statement is correct with respect to the property of elements in carbon family?With an increase in their atomic number their:
    Solution
    As the atomic number of the element increases the stability of the  compounds in +2 oxidation state increases down the group  due to inert pair effect.
    Hence option $$D$$ is correct.
  • Question 3
    1 / -0
    Metals react with silicons to form:
  • Question 4
    1 / -0
    Which of the following oxide is formed by carbon?
    Solution
    Carbon suboxide $$O = C = C = C = O$$
  • Question 5
    1 / -0
    Boron nitride has the structure of the type:
    Solution
    Hexagonal boron nitride $$(h-BN)$$ is the equivalent in the structure of graphite.

    Like graphite, its plate-like microstructure and layered lattice structure give it good lubricating properties.

    Hence, option $$A$$ is correct.
  • Question 6
    1 / -0
    The only hydride formed by lead has the formula:
    Solution

    A hydride is the anion of hydrogen, $$H^{ - }$$, more commonly, it is a compound in which one or more hydrogen centres have nucleophilic, reducing, or basic properties. In compounds that are regarded as hydrides, the hydrogen atom is bonded to a more electropositive element or group. Compounds containing hydrogen bonded to metals or metalloid may also be referred to as hydrides. Almost all of the elements form binary compounds with hydrogen, the exceptions being $$He, Ne, Ar, Kr, Pm, Os, Ir, Rn, Fr,$$ and $$Ra$$

    Plumbane, $${ PbH }_{ 4 }$$, is a metal hydride and group 14 hydride composed of lead and hydrogen.

    $$\left[ 1 \right] $$ Plumbane is not well characterized or well known, and it is thermodynamically unstable with respect to the loss of a hydrogen atom.

    $$\left[ 2 \right] $$ Derivatives of plumbane include lead tetrafluoride, ($${ PbF }_{ 4 }$$), and tetraethyllead, $$\left( { \left( { CH }_{ 3 }{ CH }_{ 2 } \right)  }_{ 4 }Pb \right) $$

  • Question 7
    1 / -0
    The naturally occuring  radioactive isotope of carbon is:
    Solution
    The longest-lived radioisotope is $$^{14}C$$ , with a half life  of 5,700 years.
  • Question 8
    1 / -0
    Addition of mineral acid to an aqueous solution of Borax, the compound formed is:
    Solution

    Correct Option: $$D$$

    Hint: The chemical formula of Borax is $$Na_2B_4O_7$$.

    Explanation:

    • When a solution of Borax reacts with a mineral acid such as $$HCl$$ orthoboric acid is formed.

    • The reaction is as shown below;

    $$Na_2B_4O_7+5H_2O+2HCl\rightarrow 4H_3BO_3+2NaCl$$

    • Orthoboric acid is a weak, monobasic acid of boron.

  • Question 9
    1 / -0
    Physical properties of a substance are given.
    P $$\rightarrow$$ It is colour less
    Q $$\rightarrow$$ has intense smell
    R $$\rightarrow$$ It's aqueous solution possesses basic property.
    Which of the above physical properties are correct for sulphur dioxide?
    Solution
    Sulphur dioxide is a colorless gas and it has an intense smell.
  • Question 10
    1 / -0
    Which of the following is not silicate?
    Solution
    Except silica, all the other three are silicates.

    Zeolite $$-\ Na_2Al_2Si_2O_8\cdot xH_2O$$

    Feldspar $$-\ KAlSi_3O_8$$,

    Ultramarine $$-\ Na_8(AlO_2)_6 \cdot (SiO_2)_6S_2$$
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