The p-Block Elements Test

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The p-Block Elements Test - 49

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Weekly Quiz Competition

Question 1
1 / -0

$$H_{2}O_{2}$$ is a:

A
monobasic acid

B
dibasic acid

C
neutral compound

D
weak alkali

Solution

$$1.$$ $$H_2O_2$$ is a dibasic acid.
$$2.$$A dibasic acid is a type of acid that has two oxygen ions to donate to a base in an acid base reaction.
Therefore a dibasic molecule has two replaceable hydrogen atoms.
$$3.$$An acid is said to be monobasic, dibasic or tribasic according to the number of replaceable hydrogen
atoms,
$$4.$$ Since, $$H_2O_2$$ has two replaceable hydrogen atoms, That's why it is a dibasic acid.
Question 2
1 / -0

Compound A is produced by absorbing dinitrogen trioxide in $$Na_{2}CO_{3}$$ solution. Compound A is:

A
$$Na_{2}O$$

B
$$NaNO_{2}$$

C
$$N_{2}O$$

D
$$Na_{2}N_2O_{2}$$
Question 3
1 / -0

Which of the following metal is highest electropositive ( metallic) in nature?

A
Be

B
Rb

C
Mn

D
Mg

Solution

Generally all the alkali and alkaline-earth metal are electropositive in nature. Whereas the p-block elements like O, Cl, C, N are electronegative elements.
The most electropositive element among the given elements is $$Rb$$
thus, Option B is correct.

Note: alkali metals are more electropositive than alkaline-earth metal
Question 4
1 / -0

Colour of the solution when $$KI$$ reacts with $$Br_2$$ is:

A
pale yellow

B
reddish-brown

C
black

D
none of the above

Solution

They undergo a displacement reaction where a more reactive halogen in this case bromine displaces iodine from its salt.

$${ Br }_{ { 2 }_{ \left( l \right) } }+{ 2KI }_{ \left( aq \right) }\rightarrow { 2KBr }_{ \left( aq \right) }+{ I }_{ 2 }$$

In this reaction, the solution will have a slight change in colour to a different shade of brown since the bromine and iodine solution are both in a different shade of brown. Since it's reddish-brown.

Hence, option B is correct.
Question 5
1 / -0

Which one of the following is the correct statement?

A
Chlorides of both beryllium and aluminium have bridged chloride structures in solid phase

B
$${B_2}{H_6}.2N{H_3}$$ is known as 'inorganic' benzene

C
Boric acid s a protoic acid

D
Beryllium exhibits coordinatin number of six
Question 6
1 / -0

Which silicon compound is used in machinery (with moving parts) in a manner similar to the use of an allotrope of carbon (crystalline) which possesses properties of both a covalent network solid and a molecular solid?

A
Silica gel

B
Zeolite

C
Silicone

D
Asbestos

Solution

Little packets of silica gel are found in all sorts of products because silica gel is a desiccant -- it adsorbs and holds water vapor. In leather products and foods like pepperoni, the lack of moisture can limit the growth of mold and reduce spoilage. In electronics it prevents condensation, which might damage the electronics. If a bottle of vitamins contained any moisture vapor and were cooled rapidly, the condensing moisture would ruin the pills. You will find little silica gel packets in anything that would be affected by excess moisture or condensation.
Silica gel is nearly harmless, which is why you find it in food products. Silica, or silicon dioxide ($$SiO_2$$), is the same material found in quartz. The gel form contains millions of tiny pores that can adsorb and hold moisture. Silica gel is essentially porous sand.
Question 7
1 / -0

What the covalencey of phosphorus atoms in excited state?

A
$$3$$

B
$$4$$

C
$$5$$

D
$$1$$

Solution

Phosphorus can have expanded octet, because it can shift it's lone pair electrons ($$3s$$ orbital electrons) to empty $$3d$$ obital during excited state and thus can form 5 bonds. So now there is 5 spaces along the singly filled orbitals to keep electrons or we may say that there can be 5 bonds now.
Question 8
1 / -0

Hybridisation in of $$Xe{O_3}$$ molecule ?

A
$$s{p}$$

B
$$s{p^3}$$

C
$$s{p^2}$$

D
none

Solution

$$XeO_3$$ has structural formula.
Number of lone pair = $$1$$
Hybridisation in $$sp^3$$
No. of bonds = 3
Lonepair+bondpair= 3+1=4
Question 9
1 / -0

Which of the following acid has the same molecular weight and equivalent weight ?

A
$$H_3PO_2$$

B
$$H_3PO_3$$

C
$$H_3PO_4$$

D
$$H_2SO_4$$

Solution

Equivalent weight equal to molecular weight divided by n- factor.
$$n- factor$$ in case of $$H_3PO_2 = 1$$
Then Equivalent weight equal to molecular weight in case of $$H_3 PO_2$$.
Question 10
1 / -0

Covalency of sulphur in $$SO_{4}^{2-}$$ ion is:

A
4

B
6

C
2

D
5

Solution

The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion. The oxidation number of the sulfur atom in the $$SO_4^{-2}$$ion must be $$+6$$. For example, because the sum of the oxidation numbers of the atoms in this ion must equal -2.

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 49

Result

The p-Block Elements Test - 49

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SHARING IS CARING

Question 1

monobasic acid

dibasic acid

neutral compound

weak alkali

Solution

Question 2

$$Na_{2}O$$

$$NaNO_{2}$$

$$N_{2}O$$

$$Na_{2}N_2O_{2}$$

Question 3

Be

Rb

Mn

Mg

Solution

Question 4

pale yellow

reddish-brown

black

none of the above

Solution

Question 5

Chlorides of both beryllium and aluminium have bridged chloride structures in solid phase

$${B_2}{H_6}.2N{H_3}$$ is known as 'inorganic' benzene

Boric acid s a protoic acid

Beryllium exhibits coordinatin number of six

Question 6

Silica gel

Zeolite

Silicone

Asbestos

Solution

Question 7

$$3$$

$$4$$

$$5$$

$$1$$

Solution

Question 8

$$s{p}$$

$$s{p^3}$$

$$s{p^2}$$

none

Solution

Question 9

$$H_3PO_2$$

$$H_3PO_3$$

$$H_3PO_4$$

$$H_2SO_4$$

Solution

Question 10

4

6

2

5

Solution

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