The p-Block Elements Test

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The p-Block Elements Test - 51

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Weekly Quiz Competition

Question 1
1 / -0

What the covalency of phosphorous atom in excited state ?

A
3

B
4

C
5

D
1

Solution

Nitrogen atoms can form up to four covalent bonds.In the ammonium ion($$NH_4^+$$), the nitrogen atom forms four covalent bonds, again filling the outermost orbital with eight electrons: Phosphorus can form up to five covalent bonds, as in phosphoric acid $$(H_3PO_4)$$.
Question 2
1 / -0

Which of the following order regarding the melting point is correct?

A
$$Si>Ge>Pb>Sn$$

B
$$Si>Pb>Ge>Sn$$

C
$$Ge>Si>Pb>Sn$$

D
none of these

Solution

Si>Ge>Pb>Sn
Si and Ge has a high rigid solid structure so, it has high melting point.
Pb and Sn forms only 2 bonds due to inert pair effect so has less melting point
Also, going down the group bond strength between atoms decreases, due to the increase in atomic size.
So,melting point decreases down the group
Question 3
1 / -0

The most abundant IV A group element in the earth's crust is :

A
Germanium

B
Carbon

C
Silicon

D
Tin

Solution
Question 4
1 / -0

Oxidation state of carbon in HCN and HNC is respectively:-

A
$$2, 4$$

B
$$4,2$$

C
$$2, 2$$

D
$$4, 4$$

Solution
Question 5
1 / -0

Borax when dissolved in water exhibts

A
Alkaline nature

B
Acidic nature

C
Neutral nature

D
Amphoteric nature

Solution

when borox is dissolved in water it forms sodium borate and boric acid which forms a strong base hence it is alkaline in nature .
Borax dissociate into $$B_4{O_7}^{2-}$$ ions
After dissociation $$B_4{O_7}^{2-} \rightarrow {2OH}^{-} +4H_3BO_3$$
formation of $${OH}^-$$ shows alkaline nature .
Question 6
1 / -0

Aluminium becomes passive when treated with______

A
$$Conc.H_{2}SO_{4}$$

B
$$Conc.HNO_{3}$$

C
$$Conc.HCl$$

D
$$dil.HCl$$

Solution

Aluminium becomes passive when treated with Conc $$HN{O}_{3}$$ due to formation of $${Al}_{2}{O}_{3}$$. It forms a protective coating on the surface of the metal.
Question 7
1 / -0

Average atomic weight of boron is $$10.10$$ and boron exists in two isotopic forms $$B^{10}$$ and $$B^{11}$$. The percentage abundance of $$B^{10}$$ is?

A
$$10\%$$

B
$$90\%$$

C
$$50\%$$

D
$$20\%$$

Solution

Let the percentage in the form of $$ B^{10} $$ is x %
Therefore, the percentage in the form of $$ B^{11} $$ is (100-x) %
Average atomic mass = $$ x \times \dfrac{10}{100} + (100-x) \times \dfrac{11}{100} $$

$$ 10.10 = \dfrac{10 \times x}{100} + \dfrac{1100-11x}{100} $$

$$ 1010 = 1100 - x $$
$$ x = 90 $$

Therefore, the percentage in which $$ B^{10} $$ exists is 90 %
Question 8
1 / -0

Which of the following compound is amphoteric?

A
$$Al_2O_3$$

B
$$CrO_3$$

C
$$SO_2$$

D
$$CO_2$$

Solution

An amphoteric oxide is an oxide that can act as either an acid or base in a reaction to produce a salt and water.

$$Al_2O_3$$ reacts with acid as well as base. Hence, it is amphoteric in nature.

Hence, option A is correct.
Question 9
1 / -0

The relative stability of +1 oxidation state of group 13 elements follows the order:

A
$$Al < Ga < Tl < In$$

B
$$Tl < In < Ga < Al$$

C
$$Al < Ga < In < Tl$$

D
$$Ga < Al < In < Tl$$

Solution

Due to the inert pair effect as we move down the group in $$13^{th}$$ group lower oxidation state become more stable.

So, the correct order is: $$Al < Ga < In < Tl$$.
Question 10
1 / -0

Maximum covalency shown by boron is:

A
$$6$$

B
$$8$$

C
$$2$$

D
$$4$$

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 51

Result

The p-Block Elements Test - 51

Score

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SHARING IS CARING

Question 1

3

4

5

1

Solution

Question 2

$$Si>Ge>Pb>Sn$$

$$Si>Pb>Ge>Sn$$

$$Ge>Si>Pb>Sn$$

none of these

Solution

Question 3

Germanium

Carbon

Silicon

Tin

Solution

Question 4

$$2, 4$$

$$4,2$$

$$2, 2$$

$$4, 4$$

Solution

Question 5

Alkaline nature

Acidic nature

Neutral nature

Amphoteric nature

Solution

Question 6

$$Conc.H_{2}SO_{4}$$

$$Conc.HNO_{3}$$

$$Conc.HCl$$

$$dil.HCl$$

Solution

Question 7

$$10\%$$

$$90\%$$

$$50\%$$

$$20\%$$

Solution

Question 8

$$Al_2O_3$$

$$CrO_3$$

$$SO_2$$

$$CO_2$$

Solution

Question 9

$$Al < Ga < Tl < In$$

$$Tl < In < Ga < Al$$

$$Al < Ga < In < Tl$$

$$Ga < Al < In < Tl$$

Solution

Question 10

$$6$$

$$8$$

$$2$$

$$4$$

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