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The p-Block Elements Test - 55

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The p-Block Elements Test - 55
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  • Question 1
    1 / -0
    Oxidation number of $$C$$ in $${C}_{6}{H}_{12}{O}_{6}$$ is
    Solution
    $$C_6H_{12}O_6$$
    $$6x+12-12=0$$
    $$C$$ has oxidation number $$=0$$
  • Question 2
    1 / -0
    Oxidation number of carbon in $${H}_{2}{C}_{2}{O}_{4}$$ is
    Solution
    $${H}_{2}\overset { \ast  }{ {C}_{2} } {O}_{4}$$

    Let, $$x$$ be the oxidation number of carbon in $${H}_{2}{C}_{2}{O}_{4}.$$

    Now,

    $$2\times (+1)+2\times x+4\times(-2) =0;\ \Rightarrow x=+3$$
  • Question 3
    1 / -0
    The oxidation number of carbon in $${CH}_{2}O$$ is
    Solution
    $$\overset { \ast  }{ C } {H}_{2}O$$
    $$x+2-2=0$$
    $$x=0$$
  • Question 4
    1 / -0
    $$ B^{3+} $$ cannot exist in aqueous solution because of its
    Solution
    Being covalent in nature because of small size and large charge it gets hydrolysed in an aqueous solution. In other words, on account of higher charge density i.e. charge/size ratio, it gets hydrolysed forming  $$H_{3}BO_{3} $$

    $$ 2B^{3+} + 6H_{2}O \rightarrow 2 H_{3}BO_{3} + 6H^{+} $$

    Hence, option C is correct.
  • Question 5
    1 / -0
    Oxidation state of elemental carbon is
    Solution
    Every element always shows zero oxidation state in the elemental stable form.
  • Question 6
    1 / -0
    Oxidation number of carbon in $${CH}_{3}-Cl$$ is
    Solution
    $$\overset { \ast  }{ C } {H}_{3}-Cl$$
    $$x+3(+1)+(-1)\times 1=0;x=-2$$
  • Question 7
    1 / -0
    The oxidation number of carbon in $${CH}_{2}{Cl}_{2}$$ is
    Solution
    $$\overset { \ast  }{ C } {H}_{2}{Cl}_{2}$$

    Let, $$x$$ be the oxidation number of carbon in $${CH}_{2}{Cl}_{2}.$$

    Now,

    $$x+2\times(+1)+2\times(-1)=0;\ \Rightarrow x=0$$
  • Question 8
    1 / -0
    Thallium shows different oxidation states because 
    Solution
    Thallium shows different oxidation states because of inert-pair effect.
    Hence, Option "B" is the correct answer.
  • Question 9
    1 / -0
    How many ionisation energies can carbon have
    Solution
    Carbon has total of 6 electrons and all 6 can be removed.
  • Question 10
    1 / -0
    Carbon containing molecules present in all life forms includes:
    Solution
    Being an organic molecule, carbon acts as a key element of nucleic acids.
    Carbon atoms appear in the sugar of the nucleic acid backbone, and the nitogenous bases. Carbon dioxide consists of a carbon atom covalently double bonded to two oxygen atoms. Carbon dioxide is soluble in water, in which it readily and reversibly converts to carbonic acid. The conjugate bases of a carbonic acid are known as the bicarbonate and carbonate ions.
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