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The p-Block Elements Test - 63

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The p-Block Elements Test - 63
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  • Question 1
    1 / -0

    The silicate anion in the mineral kaolinite is a chain of three $$ \displaystyle Si{ O }_{ 4 }$$ tetrahedral that share corners with adjacent tetrahedral. The mineral also contains $$ \displaystyle  { Ca }^{ 2+ }$$ ions, $$ \displaystyle  { Ca }^{ 2+ }$$ ions, and water molecules in a 1 :1 :1 ratio. Mineral is represented as :

    Solution
    The formula of silicate with three $$SiO_4$$ tetrahedral that share corners with adjacent tetrahedral = $$Si_3O_10^{8-}$$
    Charge on $$Ca = +2$$
    Charge on $$Cu= +2$$
    Charge on $$H_2O= 0$$
    To balance the $$-8$$ charge of silicate with $$Ca^{2+}, Cu^{2+}$$ and $$H_2O$$ in ration $$1:1:1$$ number of each required $$=2$$
    Hence the formula of mineral$$= Ca_2Cu_2Si_3O_{10}.2H_2O$$
  • Question 2
    1 / -0
    Borax is used as a buffer since-
    Solution
    As it can be seen that,
    aqueous solution of borax contains equal amount of weak acid and its salt so it can acts as buffer solution.

  • Question 3
    1 / -0
    When borax is dissolved in water :
  • Question 4
    1 / -0
    Which of the following product is formed when $$SiF_4$$ reacts with water?
    Solution
    In reaction with water, $$SiF_4$$ (like $$SiCI_4$$) gets hydrolysed to form $$H_4SiO_4$$ (silicic acid).
    $$SiF_4+4H_2O\longrightarrow Si(OH)_4$$ or $$H_4SiO_4+ 4HF$$
                                                (Silicic acid)
  • Question 5
    1 / -0
    Jena glass is a mixture of:
    Solution
    Option $$(A)$$ is correct.
    Jena glass is a mixture of zinc and barium borosilicates and is resistant to heat, chemicals and shock. It was used for chemical glassware, thermometers etc.
  • Question 6
    1 / -0
    The ground glass stopper is often seen to get stuck in the neck of glass bottles containing aq $$NaOH$$ solution This is due to: 
    Solution
    The ground glass stopper is often seen to get stuck in the neck of glass bottles containing aq $$NaOH$$ solution This is due to formation of solid $$Na_2SiO_3$$ around the neck of the bottle
    $$\displaystyle 2NaOH(aq)+SiO_{2}\rightarrow \underset{fuses\: \: with\: \: glass}{Na_{2}SiO_{3}(s)+H_{2}O}$$
    Hence option $$B$$ is correct.
  • Question 7
    1 / -0
    Electronic configuration of only one p-block element is exceptional. One molecule of that element consists of how many atoms of it?
    Solution
    The electronic configuration of an only p-block element is exceptional. One molecule of that element consists of only one atom of it.

    As the exception is found in only He, as helium has the electronic configuration to be $$1s^2$$. But other member of the same group has $$ns^2\; np^6$$ configuration.

    So, this is an exceptional case where He does not resemble its group in its configuration.
    And as He is a noble gas element so it is monoatomic gas.
  • Question 8
    1 / -0
    Which of the following electrolytes is least effective in causing flocculation of ferric hydroxide sol?
    Solution
    (i) Sols are coagulated by oppositely charged ions.
    (ii) Greater the charge on ion causing coagulation, higher will be its coagulating power.
    $$\therefore Fe(OH)_{3}$$ is positively charged sol.
    $$\therefore$$ Anion will coagulate this sol.
    (a) $$K_{3} [Fe(CN)_{6}]\rightarrow 3K^{+} + [Fe(CN)_{6}]^{3-}$$
    (b) $$K_{2}Cr_{2}O_{7}\rightarrow 2K^{+} + Cr_{2}O_{7}^{2-}$$
    (c) $$K Br\rightarrow K^{+} + Br^{-}$$
    (d) $$K_{2}SO_{4} \rightarrow 2K^{+} + SO_{4}^{2-}$$
    $$\because$$ In $$KBr, Br^{-}$$ has smallest negative charge among given choices.
    $$\therefore$$ It will be least effective in coagulating $$Fe(OH)_{3}$$.
  • Question 9
    1 / -0
    Stannite is an ore of __________.
    Solution
    Stannite is a mineral, a sulfide of copper, iron, and tin. The chemical formula $${Cu}_2FeSnS_4$$.
  • Question 10
    1 / -0
    The following element forms a molecule with eight of its own atoms:
    Solution
    Sulphur has the second-highest property of carbon. Its molecule has eight atoms bonded together.

    Hence, option B is correct.

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